\begin{table}[ht]
\caption{Table 5.1: Case studied depending on pre-chamber pressure and CVC chamber fuel blends}
\begin{center}
\begin{tabular}{|c|c|c|}
\hline
Case Number&Pre-chamber Pressure (bar)&CVC chamber fuel blends (by volume)\\
\hline
5.1&2&Fuel-B, 50:50 CH$_{4}$-H$_{2}$ blend\\
\hline
5.2&2&Fuel-A, 30:70 CH$_{4}$-H$_{2}$ blend\\
\hline
5.3&4&Fuel-B, 50:50 CH$_{4}$-H$_{2}$ blend\\
\hline
5.4&4&Fuel-A, 30:70 CH$_{4}$-H$_{2}$ blend\\
\hline
5.5&6&Fuel-B, 50:50 CH$_{4}$-H$_{2}$ blend\\
\hline
5.6&6&Fuel-A, 30:70 CH$_{4}$-H$_{2}$ blend\\
\hline
\end{tabular}
\end{center}
\label{tab:multicol}
\end{table}
\\
\\
\\
\\
\\
\\\
\\
\begin{table}[ht]
\caption{Table 5.2. Thermodynamic properties and mass fraction}
\begin{center}
\begin{tabular}{|c|c|c|c|c|}
\hline
\multirow{Mass fraction, Y} &
\multicolumn{2}{c}
%{\hspace*{-3.5mm} \hspace*{3mm}
{Pre-chamber } \vline
&
\multirow{CVC chamber}
%\vline
&
\multirow{nozzle}
\\
\cline{2-3}
& Case 4.1 Reactive
& Case 4.2 Inert H
%& Case 4.3 Inert U
\\
\hline
He&0&0.0905&0.2152&0\\
\hline
CH_{4}&0&0&0&0.0552\\
\hline
Ar&1.21e-2&0.2248&0.4755&0\\
\hline
CO&3.40e-2&0&0&0\\
\hline
CO_{2}&1.11e-1&0&0&0\\
\hline
H&6.08e-5&0&0&0\\
\hline
H_{2}&1.01e-3&0&0&0\\
\hline
H$_{2}${O}&1.23e-1&0&0&0\\
\hline
NO&3.31e-3&0&0&0\\
\hline
N_{2}&7.08e-1&0.6847&0.3092&0.7247\\
\hline
O&2.41e-4&0&0&0\\
\hline
OH&3.64e-3&0&0&0\\
\hline
O_{2}&2.65e-3&0&0&0.2201\\
\hline
Temperature(K)&2670&2670&2670&300\\
\hline
Pressure(bar)&6&6&6&1\\
\hline
\end{tabular}
\end{center}
\label{tab:multicol}
\end{table}
答案1
-命令multirow通常需要三个参数（应该跨越多少行、内容的宽度以及要打印的内容）。您还必须记住正确使用 -环境。您忘记在包含缺失垂直线的行中tabular添加两个。缺少该垂直线是因为表格在该列的该点结束。&\\
将代码更改为具有先前不起作用的表的 MWE：
\documentclass{article}
\usepackage{multirow}
\begin{document}
\begin{table}[ht]
\caption{Table 5.2. Thermodynamic properties and mass fraction}
\begin{center}
\begin{tabular}{|c|c|c|c|c|}
\hline
\multirow{2}{*}{Mass fraction, Y} & \multicolumn{2}{c}{Pre-chamber } \vline &\multirow{2}{*}{CVC chamber}&\multirow{2}{*}{nozzle} \\
\cline{2-3}
& Case 4.1 Reactive & Case 4.2 Inert H &&\\
\hline
He&0&0.0905&0.2152&0\\
\hline
$CH_{4}$&0&0&0&0.0552\\
\hline
Ar&1.21e-2&0.2248&0.4755&0\\
\hline
CO&3.40e-2&0&0&0\\
\hline
$CO_{2}$&1.11e-1&0&0&0\\
\hline
H&6.08e-5&0&0&0\\
\hline
$H_{2}$&1.01e-3&0&0&0\\
\hline
$H_{2}${O}&1.23e-1&0&0&0\\
\hline
NO&3.31e-3&0&0&0\\
\hline
$N_{2}$&7.08e-1&0.6847&0.3092&0.7247\\
\hline
O&2.41e-4&0&0&0\\
\hline
OH&3.64e-3&0&0&0\\
\hline
$O_{2}$&2.65e-3&0&0&0.2201\\
\hline
Temperature(K)&2670&2670&2670&300\\
\hline
Pressure(bar)&6&6&6&1\\
\hline
\end{tabular}
\end{center}
\label{tab:multicol}
\end{table}
\end{document}
电流输出：
答案2
虽然您的问题已修复（\multirow需要 3 个参数），但我会诚实地更改您的表格以提高其可读性。这些是我会做的更改：
- 删除所有垂直规则和大部分水平规则，然后切换到
booktabs包。 dcolumn使用该包并设置新的列类型，将小数点处的数值对齐。- 如果需要，您可以添加交替灰线，以便更容易阅读行。您不会在下面的输出中看到这一点，但如果您想看到，您可以取消注释（删除它
%前面的）命令%\rowcolors{3}{gray!5}{white}。
我还将标题移到了表格下方，但您可以根据自己的喜好随意移动它（尽管我通常在下面看到它）。
输出
代码
\documentclass{article}
\usepackage{booktabs, dcolumn}
\usepackage{multirow,array}
\usepackage{geometry}
\usepackage[table]{xcolor}
\newcolumntype{.}{D{.}{.}{-1}}
\begin{document}
\begin{table}[h!]
\centering
%\rowcolors{3}{gray!5}{white}
\begin{tabular}{r.*{4}{.}}
\toprule
\multirow{2}{*}{Mass fraction, Y} & \multicolumn{2}{c}{Pre-chamber} & \multicolumn{1}{c}{\multirow{2}{*}{CVC chamber}} & \multicolumn{1}{c}{\multirow{2}{*}{nozzle}} \\
& \multicolumn{1}{c}{Case 4.1 Reactive} & \multicolumn{1}{c}{Case 4.2 Inert H} & & \\ \midrule
He & 0 & 0.0905 & 0.2152 & 0 \\
CH$_{4}$ & 0 & 0 & 0 & 0.0552 \\
Ar & 1.21e-2 & 0.2248 & 0.4755 & 0 \\
CO & 3.40e-2 & 0 & 0 & 0 \\
CO$_{2}$ & 1.11e-1 & 0 & 0 & 0 \\
H & 6.08e-5 & 0 & 0 & 0 \\
H$_{2}$ & 1.01e-3 & 0 & 0 & 0 \\
H$_{2}${O} & 1.23e-1 & 0 & 0 & 0 \\
NO & 3.31e-3 & 0 & 0 & 0 \\
N$_{2}$ & 7.08e-1 & 0.6847 & 0.3092 & 0.7247 \\
O & 2.41e-4 & 0 & 0 & 0 \\
OH & 3.64e-3 & 0 & 0 & 0 \\
O$_{2}$ & 2.65e-3 & 0 & 0 & 0.2201 \\
Temperature (K) & 2670 & 2670 & 2670 & 300 \\
Pressure (bar) & 6 & 6 & 6 & 1 \\ \bottomrule
\end{tabular}
\caption{Table 5.2. Thermodynamic properties and mass fraction}
\label{tab:multicol}
\end{table}
\end{document}