因此，这是使该表正常工作所需的第二个问题：
我正在使用这个：
\documentclass{article}
\usepackage[margin=1cm,a3paper]{geometry}
\usepackage{siunitx}
\usepackage[T1]{fontenc}
\usepackage{stix}
\usepackage{graphicx}
\usepackage[utf8]{inputenc}
\usepackage[ngerman]{babel}
\usepackage{pgfplotstable}
\usepackage{pdflscape}
\usepackage{tabu}
\usepackage{longtable}
\usepackage{makecell}
\usepackage[style=authoryear-comp,maxbibnames=25, maxcitenames=2,backend=biber]{biblatex}
%some bib libraries and style commands
\usepackage{booktabs}
\pgfplotsset{compat=1.12}
\usepackage{multicol}
\usepackage{hyperref}
\usepackage[babel,german=quotes]{csquotes}
\usepackage{array}
\pgfplotstableset{every head row/.style={before row=\toprule, after row=\midrule\endhead},
every last row/.style={after row=\bottomrule}}
\begin{document}
\begin{landscape}%
\pgfplotstabletypeset[begin table=\begin{longtable},end table=\end{longtable},
header=true, col sep=comma, use comma, row sep=newline,
math/.style={preproc cell content/.append style={/pgfplots/table/@cell content/.add={$}{$}},},
%0
columns/Autor/.style={string replace*={##1}{\textcite{##1}},column name={Quelle}, string type, column type =l},
%1
columns/Ort/.style={column name={Ort}, string type, column type = l},
%2
columns/Longitude/.style={column name={Longitude},string replace*={##1}{\ang{##1}}, string type, column type=r},
%3
columns/Latitude/.style={column name={Latitude},string replace*={##1}{\ang{##1}} , string type, column type=r},
%4
columns/Wert/.style={, column type=r, dec sep align, fixed,precision=2,column name={\makecell{Werte}},clear infinite,},
%5
columns/Einheit/.style={column name={[Einheit]}, string type, column type=l,math},
%6
columns/Beschreibung/.style={column name=Beschreibung,string replace*={##1}{{\mathrm{##1}}}, string type, column type=l,math},
%7
columns/Dichte/.style={, column type=r, dec sep align,fixed,precision=2,column name={\makecell[c]{$\rho$ \\ $[kg \cdot m^{-3}]$}},clear infinite },
%8
columns/DichteQuelle/.style={string replace*={##1}{\textcite{##1}},column name={Quelle $\rho$}, string type, column type =l},
%9
columns/l/.style={column name={$l$}, precision=2, column type=r,clear infinite },
%10
columns/NAI/.style={,fixed,precision=2, column type=r , dec sep align,column name={\makecell[c]{NAI \\ $[m^3\cdot ha^{-1}]$}},clear infinite },
%11
columns/Baumarten/.style={column name={Spezies}, string replace*={##1}{\textit{##1}}, string type, column type =l}
]
{
Autor,Ort,Longitude,Latitude,Wert,Einheit,Beschreibung,Dichte,DichteQuelle,l,NAI,Baumarten
VasconcelosEtAl2012,Brasilien ,-1;19;0,+47;57;0,14.45,Mg \ ha^{-1} year^{-1},ANPP,0.704,NogueiraEtAl2005,0.5,4.928,-
BernierEtAl2007,Chibougamau Quebec,+49;41;31.2,+74;25;55.2,2090,kg \ ha^{-1} yr^{-1},ANPP_{Stems},0.45,AseevaEtAl2014,NaN,4.644444444,Picea mariana (Black Spruce)
}
\end{landscape}%
\end{document}
因此，当我在表格的第二行（第三行加上标题）中放入一些带有 的条目以x_{some text}制作索引时，就会出现问题。在早期版本中，我只是用s
包裹单元格内容，它甚至无法输入像 这样的内容。我想要那种没有 的单位样式... 最大的问题是我的系统不会给我报告或任何提示来解决这个问题。有人有想法吗？ 提前感谢您的努力。$replace string*^{-1}/
答案1
您对问题的分析不正确。引发错误的单元格包含
ANPP_{Stems}
并且位于具有规范的列中
columns/Beschreibung/.style={column name=Beschreibung,
string replace*={##1}{{\mathrm{##1}}}, string type, column type=l,math},
如果你用以下代码替换条目
ANPP_1
该表编译起来没有问题（除了缺少参考书目）。另一方面，如果你写
ANPP{Stems}
您确实会收到错误，所以是花括号导致了这个问题。
除了使用string replace*，您还可以直接在列样式中使用预处理器，如下所示：
preproc cell content/.append style={@cell content={\mathrm{##1}}}
或者你可以将mathrm其与你的math风格结合起来：
mathrm/.style={preproc cell content/.append style
={@cell content={$\mathrm{##1}$}}}
\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage{pgfplotstable}
\usepackage{tabu}
\usepackage{longtable}
\usepackage{booktabs}
\pgfplotsset{compat=1.12}
\pgfplotstableset{every head row/.style={before row=\toprule, after row=\midrule\endhead},
every last row/.style={after row=\bottomrule}}
\begin{document}
\pgfplotstabletypeset[begin table=\begin{longtable},end table=\end{longtable},
header=true, col sep=comma, use comma, row sep=newline,
math/.style={preproc cell content/.append style
={/pgfplots/table/@cell content/.add={$}{$}}},
columns/Beschreibung/.style={column name=Beschreibung,
preproc cell content/.append style={@cell content={\mathrm{##1}}},
string type, column type=l,math}]
{Beschreibung
ANPP
ANPP_{Stems}
}
\pgfplotstabletypeset[begin table=\begin{longtable},end table=\end{longtable},
header=true, col sep=comma, use comma, row sep=newline,
mathrm/.style={preproc cell content/.append style
={@cell content={$\mathrm{##1}$}}},
columns/Beschreibung/.style={column name=Beschreibung,
string type, column type=l,mathrm}]
{Beschreibung
ANPP
ANPP_{Stems}
}
\end{document}