TikZ-仅绘制路径线的顶点

Question

有没有办法只绘制三角形的顶点？

\begin{tikzpicture}[x=1mm, y=1mm]

    \coordinate (A) at (0:12);
    \coordinate (B) at (120:12);
    \coordinate (C) at (240:12);

    \foreach \i in {0, 1, ..., 9}{

        \draw[line width=0.1mm] (A) -- (B) -- (C) -- cycle;

        \path
             (A) coordinate (X)
          -- (B) coordinate[pos=0.2] (A)
          -- (C) coordinate[pos=0.2] (B)
          -- (X) coordinate[pos=0.2] (C);
    }

\end{tikzpicture}

第一个三角形的边缘应该可见。

Answer 1

insert path对于此类事情来说非常方便

\begin{tikzpicture}[scale=.5,c/.style={insert path={node[inner sep=2pt,fill,circle]{}}}]
  \coordinate (A) at (0:12);
  \coordinate (B) at (120:12);
  \coordinate (C) at (240:12);
  \draw[line width=0.1mm] (A) -- (B) -- (C) -- cycle;
  \foreach \i in {0, 1, ..., 9}{
    \path  (A) [c]coordinate (X)
        -- (B) [c]coordinate[pos=0.2] (A)
        -- (C) [c]coordinate[pos=0.2] (B)
        -- (X)    coordinate[pos=0.2] (C);
  }
\end{tikzpicture}

Answer 2

这解决方案没有和percusse有insert path稍微小一点的圆圈：

\documentclass{article}
\usepackage{tikz}

\begin{document}
\begin{tikzpicture}[scale=.5]
  \coordinate (A) at (0:12);
  \coordinate (B) at (120:12);
  \coordinate (C) at (240:12);
  \draw[line width=0.1mm] (A) -- (B) -- (C) -- cycle;
  \path[               
    every node/.style={circle, fill, inner sep=1.5pt},
  ]
    \foreach \i in {0, 1, ..., 9}{
         (A) node (X) {}
      -- (B) node{} coordinate[pos=0.2] (A)
      -- (C) node{} coordinate[pos=0.2] (B)
      -- (X.center) coordinate[pos=0.2] (C)
    }
  ;
\end{tikzpicture}
\end{document}