我读这个答案， 和这个关于如何对\texttt文本进行连字符处理以及处理特殊字符。但是，它并没有真正实现我的意图。
\documentclass{scrreprt}
\usepackage{classicthesis,lipsum} % classicthesis to make it closer to my actual document
\DeclareFontFamily{\encodingdefault}{\ttdefault}{\hyphenchar\font=23}
\lccode`\:`\:
\begin{document}
This is a meaningless line of text \texttt{and:this:is:meaninglessly:typewritten:text}.
This line is equally meaningless, but also also also also also also contains a \texttt{somewhatlongishwordwhichshouldbehyphenated}
\end{document}
生产
显然，\font=23不是所提到的字符的代码点在这个答案中。所以我想我可以简单地这样做\usepackage[T1]{fontenc}，但这会取消输入文本：
\documentclass{scrreprt}
\usepackage{classicthesis,lipsum}
\usepackage[T1]{fontenc}
\DeclareFontFamily{\encodingdefault}{\ttdefault}{\hyphenchar\font=23}
\lccode`\:`\:
\begin{document}
This is a meaningless line of text \texttt{and:this:is:meaninglessly:typewritten:text}.
This line is equally meaningless, but also also also also also also also also contains a \texttt{somewhatlongishwordwhichshouldbehyphenated}
\end{document}
这正确地“连字符”，但字体是错误的
如何才能获得带有连字符的 T1 字体编码和打字文本？
答案1
T1 编码字体中的字符 23 是不可见的复合字标；OT1 编码字体中没有这样的字符，因此您确实需要 T1。
然而，声明一个字体系列是不够的，事实上你会得到
LaTeX Font Warning: Font shape `T1/cmtt/m/n' undefined
(Font) using `T1/cmr/m/n' instead on input line 8.
这解释了为什么字体不是等宽的。如果您明确声明了字体系列，则还需要提供整个字体定义，除非字体描述文件已经加载。
\documentclass{scrreprt}
\usepackage{classicthesis,lipsum}
\usepackage[T1]{fontenc}
\lccode`\:=`\:
\AtBeginDocument{%
% load the .fd file for \ttfamily
\sbox0{\fontsize{10}{12}%
% set the hyphenchar for the current font
\ttfamily\hyphenchar\font=23 }%
% set the hyphenchar for every other font in the family
\DeclareFontFamily{\encodingdefault}{\ttdefault}{\hyphenchar\font=23 }%
}
\begin{document}
This is a meaningless line of text \texttt{and:this:is:meaninglessly:typewritten:text}.
This line is equally meaningless, but also also also also also also also also contains
a \texttt{somewhatlongishwordwhichshouldbehyphenated}
\end{document}
