不确定具有复杂节点（不仅仅是标签）的 Tikz 树的实现

Question

你将如何实现这个

在 tikz 中？到目前为止，我刚刚为我的树做了类似的事情：

\begin{tikzpicture}[
    level distance=3em,
    every node/.style = {shape=rectangle, rounded corners, draw, align=center},
    level 1/.style={sibling distance=7.5em},
    level 2/.style={sibling distance=4em},
    level 3/.style={sibling distance=4em},
    level 4/.style={sibling distance=4em}]

    \node{8}
    child { node {5}
        child { node {9} }
        child { node {7}
            child { node {1} }
            child { node {12}
                child { node {2} }
                child [missing]
            }
        }
    }
    child { node {4}
        child[missing]
        child { node {11}
            child { node {3} }
            child[missing]
        }
    };
\end{tikzpicture}

如果可能的话，我正在努力寻找一个或多或少一致的解决方案。我遇到的问题是如何使节点更加美观，而不仅仅是使用标签。

Answer 1

另一种方法。使用controls绘制曲线和一个简单的tabular节点：

代码（仍有改进空间）：

\documentclass[tikz, border=10pt]{standalone}
\usepackage{array}

\newcommand{\tnode}[1]{
    \begin{tabular}{l|l}
        \multicolumn{2}{l}{node} \\\hline
        *parent & val=#1
    \end{tabular}}

\begin{document}

\begin{tikzpicture}[
    level distance=7em,
    every node/.style = {align=center, font=\ttfamily, 
        inner sep=0pt, draw, rounded corners,},
    level 1/.style={sibling distance=12em, nodes={xshift=5em}},
    level 2/.style={sibling distance=12em},
    thick, <-, shorten >=2pt, shorten <=2pt,
    ]
    \node (root) {\tnode{A}} 
        child { node {\tnode{B}}
            [nodes={xshift=-8em}, edge from parent path = 
                {([xshift=-20pt]\tikzparentnode.south) 
                .. controls +(0,-1) and +(-2,1) 
                .. (\tikzchildnode.west)}] 
                child { node{\tnode{E}}}}
        child { node {\tnode{C}} 
            [edge from parent path = 
                {([xshift=0pt]\tikzparentnode.south) 
                .. controls +(0,-1) and +(-1,0) 
                .. (\tikzchildnode.west)}] }
        child { node {\tnode{D}} 
            [nodes={xshift=-5em}, edge from parent path = 
                {([xshift=20pt]\tikzparentnode.south)
                .. controls +(0,-1) and +(-1,1)  
                .. (\tikzchildnode.west)}] 
                child { node {\tnode{F}} 
                    [edge from parent path = 
                     {([xshift=-20pt]\tikzparentnode.south)
                    .. controls +(0,-1) and +(-2,1)  
                    .. (\tikzchildnode.west)}]} 
                child { node {\tnode{G}} 
                    [edge from parent path = 
                     {([xshift=20pt]\tikzparentnode.south)
                    .. controls +(0,-1) and +(-1,0)  
                    .. (\tikzchildnode.west)}]}
                };
    \draw (root.north) to[out=110, in=-180, looseness=3] (root.west);
\end{tikzpicture}

\end{document}

Answer 2

我对这个解决方案并不完全满意，但它接近我想要做的事情。

\begin{tikzpicture}[
    level distance=5em,
    every node/.style = {rectangle split, rectangle split parts=2, minimum height=4ex, draw, align=center},
    level 1/.style={sibling distance=10em},
    level 2/.style={sibling distance=7em},
    level 3/.style={sibling distance=7em},
    level 4/.style={sibling distance=7em},
    level 5/.style={sibling distance=7em},
    thick,<-]

    \node{*parent\nodepart{two}val = A}
    child { node {*parent\nodepart{two}val = B}
        child { node {*parent\nodepart{two}val = E}
            child { node {*parent\nodepart{two}val = H} }
            child { node {*parent\nodepart{two}val = I} }
        }
        child [missing]
    }
    child { node {*parent\nodepart{two}val = C}
    }
    child { node {*parent\nodepart{two}val = D} 
        child { node {*parent\nodepart{two}val = F} 
            child { node {*parent\nodepart{two}val = J} }
            child { node {*parent\nodepart{two}val = K} 
                child { node {*parent\nodepart{two}val = M} }
            }
            child { node {*parent\nodepart{two}val = L} }
        }
        child { node {*parent\nodepart{two}val = G} }
    };
\end{tikzpicture}