我应该将一系列图像按顺序排列并用箭头连接起来。这就是我设法做到的:
使用此代码:
\begin{figure}[!htbp]
\centering
\subfloat{
\begin{forest}
[\textbf{\(\textbf{P}\sb{id1}\)}
[\(\textbf{\#text}\sb{id2}\)]
[\(\textbf{B}\sb{id3}\) [\(\textbf{\#text}\sb{id4}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{forest}
}
\subfloat{
$\xrightarrow{R(id1, id6)}$
}
\subfloat{
\begin{forest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id2}\)]
[\(\textbf{B}\sb{id3}\) [\(\textbf{\#text}\sb{id4}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{forest}
}
\subfloat{
$\xrightarrow{R(id2, id7)}$
}
\subfloat{
\begin{forest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{B}\sb{id3}\) [\(\textbf{\#text}\sb{id4}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{forest}
}
\subfloat{
$\xrightarrow{R(id3, id8)}$
}
\subfloat{
\begin{forest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{\#text}\sb{id4}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{forest}
}
\subfloat{
$\xrightarrow{R(id4, id9)}$
}
\subfloat{
\begin{forest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{STRONG}\sb{id9}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{forest}
}
\subfloat{
$\xrightarrow{ I(id10) }$
}
\subfloat{
\begin{forest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{STRONG}\sb{id9}\) [\(\textbf{\#text}\sb{id10}\)]]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{forest}
}
\subfloat{
$\xrightarrow{R(id5, id11)}$
}
\subfloat{
\begin{forest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{STRONG}\sb{id9}\) [\(\textbf{\#text}\sb{id10}\)]]]
[\(\textbf{U}\sb{id11}\)]
]
\end{forest}
}
\subfloat{
$\xrightarrow{ I(id12) }$
}
\subfloat{
\begin{forest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{STRONG}\sb{id9}\) [\(\textbf{\#text}\sb{id10}\)]]]
[\(\textbf{U}\sb{id11}\) [\(\textbf{\#text}\sb{id12}\)]]
]
\end{forest}
}
\caption{Applicazione delle operazioni di \textit{diff} sull'albero \textit{oTree}.}
\label{fig:sekowsolsenzaspanseqoperazioni}
\end{figure}
这非常好,但我希望箭头居中对齐而不是向下。
我希望每行之间能有更多的空间。
像这样:
我怎样才能做到这一点?
我的序言部分内容:
\documentclass[a4paper, 11pt, titlepage]{book}
\usepackage[italian]{babel}
\usepackage{courier}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{forest, adjustbox}
\usepackage{mathtools}
\usepackage{graphicx}
\usepackage{subfig}
\captionsetup[subfigure]{subrefformat=simple,labelformat=simple,listofformat=subsimple}
\renewcommand\thesubfigure{(\alph{subfigure})}
如果可能的话,我愿意继续使用该套餐子浮点型因为我的文档中有很多这样的数字,而且我不想改变所有内容。
多谢!
答案1
\subfloat
为此,您不需要。所有树都可以封装在一个tabular
环境中,该环境可保证相对于箭头所在的公式轴垂直居中。
我还补充说,\small
这会使所有内容稍微小一些,并有助于控制尺寸。
\documentclass[a4paper, 11pt, titlepage]{book}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[italian]{babel}
\usepackage{courier}
\usepackage{forest, adjustbox}
\usepackage{mathtools}
\usepackage{graphicx}
% centered forest
\newenvironment{cforest}
{\tabular{@{}c@{}}\forest}
{\endforest\endtabular}
\begin{document}
\begin{figure}[!htbp]
\centering\small
%% first row
\begin{cforest}
[\textbf{\(\textbf{P}\sb{id1}\)}
[\(\textbf{\#text}\sb{id2}\)]
[\(\textbf{B}\sb{id3}\) [\(\textbf{\#text}\sb{id4}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{cforest}
$\xrightarrow{R(id1, id6)}$
\begin{cforest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id2}\)]
[\(\textbf{B}\sb{id3}\) [\(\textbf{\#text}\sb{id4}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{cforest}
%% second row
$\xrightarrow{R(id2, id7)}$
\begin{cforest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{B}\sb{id3}\) [\(\textbf{\#text}\sb{id4}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{cforest}
$\xrightarrow{R(id3, id8)}$
%% third row
\begin{cforest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{\#text}\sb{id4}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{cforest}
$\xrightarrow{R(id4, id9)}$
\begin{cforest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{STRONG}\sb{id9}\)]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{cforest}
%% fourth row
$\xrightarrow{ I(id10) }$
\begin{cforest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{STRONG}\sb{id9}\) [\(\textbf{\#text}\sb{id10}\)]]]
[\(\textbf{\#text}\sb{id5}\)]
]
\end{cforest}
$\xrightarrow{R(id5, id11)}$
%% fifth row
\begin{cforest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{STRONG}\sb{id9}\) [\(\textbf{\#text}\sb{id10}\)]]]
[\(\textbf{U}\sb{id11}\)]
]
\end{cforest}
$\xrightarrow{ I(id12) }$
\begin{cforest}
[\textbf{\(\textbf{P}\sb{id6}\)}
[\(\textbf{\#text}\sb{id7}\)]
[\(\textbf{EM}\sb{id8}\) [\(\textbf{STRONG}\sb{id9}\) [\(\textbf{\#text}\sb{id10}\)]]]
[\(\textbf{U}\sb{id11}\) [\(\textbf{\#text}\sb{id12}\)]]
]
\end{cforest}
\caption{Applicazione delle operazioni di \textit{diff} sull'albero \textit{oTree}.}
\label{fig:sekowsolsenzaspanseqoperazioni}
\end{figure}
\end{document}