使用 algorithmic 包编写伪代码

Question

我有个疑问，为什么第四行给我留了一行空白？我可以删除“语句”end while 和 end for 吗？

\begin{algorithmic} [1]
\FOR{$j \gets 0$ \TO $n - 1$  } \STATE{$t \gets A[j]$ \STATE {$i\gets j-1$}
 \STATE{\WHILE{$i\geq 0$ and $A[i]>t$} \STATE{$A[i+1]\gets A[i]$\STATE{$i\gets i-1$}} \ENDWHILE $A[i+1]\gets t$}} \ENDFOR
\end{algorithmic}

Answer 1

我认为您滥用了该工具：您不应该嵌套\WHILE声明\STATE。

\documentclass{article}
\usepackage{algorithmic}

\begin{document}

\begin{algorithmic} [1]
\FOR{$j \gets 0$ \TO $n - 1$}
  \STATE{$t \gets A[j]$}
  \STATE {$i\gets j-1$}
  \WHILE{$i\geq 0$ and $A[i]>t$}
    \STATE{$A[i+1]\gets A[i]$}
    \STATE{$i\gets i-1$}
  \ENDWHILE
  \STATE{$A[i+1]\gets t$}
\ENDFOR
\end{algorithmic}

\end{document}

正如 Manuel 在评论中正确建议的那样，该noend选项会使“End”标签消失：

\documentclass{article}
\usepackage[noend]{algorithmic}

\begin{document}

\begin{algorithmic} [1]
\FOR{$j \gets 0$ \TO $n - 1$}
  \STATE{$t \gets A[j]$}
  \STATE {$i\gets j-1$}
  \WHILE{$i\geq 0$ and $A[i]>t$}
    \STATE{$A[i+1]\gets A[i]$}
    \STATE{$i\gets i-1$}
  \ENDWHILE
  \STATE{$A[i+1]\gets t$}
\ENDFOR
\end{algorithmic}

\end{document}