我正在做一个多项选择微积分测试,并有以下代码。
\documentclass[12pt]{article}
\usepackage{amsmath,amssymb}
\usepackage[margin=1in]{geometry}
\usepackage{enumerate}
\usepackage{multicol}
\begin{document}
\begin{enumerate}[1) ]
% QUESTION 6
\item Solve for \(x\): \(x=\cfrac{1}{2-\cfrac{1}{2+\cfrac{1}{2-\cfrac{1}{2+\ddots}}}}\)
\begin{multicols}{5}
\begin{enumerate}[(A) ]
\item \(\sqrt{2}\)
\item \(\dfrac{\sqrt{5}-1}{2}\) %CORRECT
\item \(\dfrac{1+\sqrt{5}}{2}\)
\item \(\dfrac{1}{\sqrt{3}}\)
\item NOTA
\end{enumerate}
\end{multicols}
\end{enumerate}
\end{document}
但是,这会产生以下结果。请注意选项 A 垂直位于其他选项上方。
我该如何解决这个问题?请注意,我还将答案选项与其他问题的相应选项水平对齐,就像这样。
答案1
该tasks
包可以最简单地完成此操作:
\documentclass[12pt]{article}
\usepackage{amsmath,amssymb}
\usepackage[margin=1in, showframe]{geometry}
\usepackage{enumerate, tasks}
\settasks{counter-format =(tsk[A]),label-offset =1em}
\begin{document}
\begin{enumerate}[1)]
% QUESTION 6
\item Solve for \(x\): \(x=\cfrac{1}{2-\cfrac{1}{2+\cfrac{1}{2-\cfrac{1}{2+\ddots}}}}\)
\begin{tasks}(5)
\task \(\sqrt{2}\)
\task \(\dfrac{\sqrt{5}-1}{2}\) %CORRECT
\task \(\dfrac{1+\sqrt{5}}{2}\)
\task \(\dfrac{1}{\sqrt{3}}\)
\task NOTA
\task \(1 + \sqrt{3}\)
\end{tasks}
\end{enumerate}
\end{document}
答案2
这是multicol
环境 - 在包的文档中,multicol
它说它尝试对齐基线,但是每列只有一行,显然很难做到这一点。
作为一种解决方法,添加一些不可见的东西,以便所有行具有相同的高度和深度,或者至少增加多列环境中每列第一行的高度。
例如
\documentclass[12pt]{article}
\usepackage{amsmath,amssymb}
\usepackage[margin=1in]{geometry}
\usepackage{enumerate}
\usepackage{multicol}
\begin{document}
\begin{enumerate}[1) ]
% QUESTION 6
\item Solve for \(x\): \(x=\cfrac{1}{2-\cfrac{1}{2+\cfrac{1}{2-\cfrac{1}{2+\ddots}}}}\)
\begin{multicols}{5}
\begin{enumerate}[(A) ]
\item \(\sqrt{2}\)\vphantom{\(\dfrac{\sqrt{5}-1}{2}\)}
\item \(\dfrac{\sqrt{5}-1}{2}\) %CORRECT
\item \(\dfrac{1+\sqrt{5}}{2}\)\vphantom{\(\dfrac{\sqrt{5}-1}{2}\)}
\item \(\dfrac{1}{\sqrt{3}}\)\vphantom{\(\dfrac{\sqrt{5}-1}{2}\)}
\item NOTA\vphantom{\(\dfrac{\sqrt{5}-1}{2}\)}
\end{enumerate}
\end{multicols}
\end{enumerate}
\end{document}
答案3
您可以尝试使用enumitem
带有水平列表选项的包inline
来代替multicol
:
\documentclass[12pt]{article}
\usepackage{amsmath,amssymb}
\usepackage[margin=1in]{geometry}
\usepackage[inline]{enumitem}
\begin{document}
\begin{enumerate}[label=\arabic*)]
% QUESTION 6
\item Solve for \(x\): \(x=\cfrac{1}{2-\cfrac{1}{2+\cfrac{1}{2-\cfrac{1}{2+\ddots}}}}\)
\noindent\begin{enumerate*}[label=(\Alph*),itemjoin = \hspace{0.5in}]
\item \(\sqrt{2}\)
\item \(\dfrac{\sqrt{5}-1}{2}\) %CORRECT
\item \(\dfrac{1+\sqrt{5}}{2}\)
\item \(\dfrac{1}{\sqrt{3}}\)
\item NOTA
\end{enumerate*}
\end{enumerate}
\end{document}
答案4
这里有一个选项,允许您定制多个选择的对齐方式并根据您的需要进行扩展:
\documentclass{article}
\usepackage{environ,enumitem,amsmath,xkeyval,expl3}
\ExplSyntaxOn
\cs_new_eq:NN \calc \fp_eval:n
\ExplSyntaxOff
\newlist{question}{enumerate}{1}
\setlist[question]{label={\arabic*)}}
% http://tex.stackexchange.com/q/127005/5764
\makeatletter
\define@key{mc}{choices}{\setlength{\mchoicewidth}{\dimexpr\calc{1/#1}\linewidth}}
\define@boolkey{mc}{resume}[true]{}
\define@choicekey*{mc}{align}[\val\nr]{left,center,right}{%
\expandafter\global\expandafter\let\expandafter\mc@align
\ifcase\nr\relax% left
\raggedright
\or% center
\centering
\or% right
\raggedleft
\fi
}
\newcounter{multiplechoice}
\renewcommand{\themultiplechoice}{\Alph{multiplechoice}}
\NewEnviron{multiplechoice}[1]{%
\par\nobreak
\setkeys{mc}{choices=5,resume=false,align=left,#1}%
\ifKV@mc@resume\else
\setcounter{multiplechoice}{0}%
\vspace{\bigskipamount}%
\fi
\setlength{\parindent}{0pt}%
\def\item##1\item{\dosomething{##1}}%
\expandafter\@empty\BODY\item}
\newlength{\mchoicewidth}
\newcommand{\dosomething}[1]{%
\def\ampora@arg{#1}%
\ifx\ampora@arg\ampora@stop
\expandafter\env@ignore % to end the recursion
\else
\refstepcounter{multiplechoice}%
\begin{tabular}[t]{@{}p{\mchoicewidth}@{}}
(\themultiplechoice)\nobreakspace
\mc@align #1
\end{tabular}%
\expandafter\item % to continue the recursion
\fi
}
\edef\ampora@stop{\noexpand\env@ignore\space}
\makeatother
\begin{document}
\begin{question}
\item Solve for $x$: $x = \cfrac{1}{2 - \cfrac{1}{2 + \cfrac{1}{2 - \cfrac{1}{2 + \ddots}}}}$
\begin{multiplechoice}{}
\item $\sqrt{2}$
\item $\dfrac{\sqrt{5}-1}{2}$ %CORRECT
\item $\dfrac{1+\sqrt{5}}{2}$
\item $\dfrac{1}{\sqrt{3}}$
\item NOTA
\end{multiplechoice}
\item Solve for $x$: $x = \cfrac{1}{2 - \cfrac{1}{2 + \cfrac{1}{2 - \cfrac{1}{2 + \ddots}}}}$
\begin{multiplechoice}{choices=3,align=center}
\item $\sqrt{2}$
\item $\dfrac{\sqrt{5}-1}{2}$ %CORRECT
\item $\dfrac{1+\sqrt{5}}{2}$
\end{multiplechoice}
\begin{multiplechoice}{choices=2,resume,align=center}
\item $\dfrac{1}{\sqrt{3}}$
\item \raggedleft NOTA
\end{multiplechoice}
\end{question}
\end{document}
环境multiplechoice
提供了一个键值强制的参数,您可以设置数字choices
(默认为 5),是否希望环境编号来自resume
前一个编号,以及每个项目的通用对齐方式。您可以根据需要使用以下方法覆盖单个项目的对齐方式:
\begin{multiplechoice}{..}
\item ...
\item \raggedleft <some item>
\item ...
\end{multiplechoice}