绘制带有部分的垂直线

Question

我看过另一个例子，但很难适应我的需求。Tikz 对我来说很新。

  \begin{center}
  \begin{tikzpicture}[every edge/.style={shorten <=1pt, shorten >=1pt}]
  \draw (0,0)  node [below] {0} -- (1,0) node [below] {1};
  % draw the tick marks
  \coordinate (p) at (0,2pt);
  \foreach \myprop/\mytext [count=\n] in {0.06/$p_1$,0.06/$p_2$,0.06/$p_3$,0.06/$p_4$,0.06/$p_5$,0.15/$p_6$,0.13/$p_7$,0.14/$p_8$,0.15/$p_9$,0.13/$p_10$}
  \draw [decorate,decoration={brace,amplitude=2}] (p)  edge [draw] +(0,-4pt) -- ++(\myprop,0) coordinate (p) node [midway, above=2pt, anchor=south] {\mytext} ;
  \path (1,2pt) edge [draw]  ++(0,-4pt);
\end{tikzpicture}
\end{center}

Latex 将所有值挤压在一起而不是将它们分散到 0 到 1 的轴上。

Answer 1

以下是修改内容的一种方法：

\documentclass[tikz,border=10pt,multi]{standalone}
\usetikzlibrary{decorations.pathreplacing,calc,positioning}
\begin{document}
  \begin{tikzpicture}[every edge/.style={shorten <=1pt, shorten >=1pt}]
  \draw (0,0)  node [below] {0} -- (10,0) node [below] {1};
  % draw the tick marks
  \coordinate (p) at (0,2pt);
  \foreach \myprop/\mytext [count=\n] in {1/$p_1$,2/$p_2$,.5/$p_3$,1/$p_4$,5/\dots,.5/$p_n$}
  \draw [decorate,decoration={brace,amplitude=2}] (p)  edge [draw] +(0,-4pt) -- ++(\myprop,0) coordinate (p) node [midway, above=2pt, anchor=south] {\mytext} ;
  \path (10,2pt) edge [draw]  ++(0,-4pt);
\end{tikzpicture}
\end{document}

Answer 2

这是一个例子。根据你在问题后面的评论，我放了 10 个段（11 个刻度）。

\documentclass[tikz,border=7mm]{standalone}
\usetikzlibrary{decorations.pathreplacing}
\begin{document}
  \begin{tikzpicture}
    % draw segment and ticks
    \draw[-](0,0)--(10,0) foreach~in{0,...,10}{(~,-2pt)--(~,2pt)};
    % draw braces and labels
    \foreach[count=\j]\i in{0,...,9}
      \draw[decorate,decoration=brace](\i cm + 1pt,3pt) -- node[above,font=\scriptsize]{$p_{\j}$} (\j cm - 1pt,3pt);
  \end{tikzpicture}
\end{document}