两个高斯重叠的阴影区域

Question

我正在尝试遮蔽两个高斯重叠的区域。

我的代码如下（根据 Christian 的回答修改而来：如何绘制由两个相交的高斯分布曲线所界定的区域？)：

\documentclass[t]{beamer}
\usepackage{pgfplots}
\usepgfplotslibrary{fillbetween}
\pgfmathdeclarefunction{gauss}{2}{\pgfmathparse{1/(#2*sqrt(2*pi))*exp(-((x-#1)^2)/(2*#2^2))}}

\begin{document}

\begin{frame}
\begin{tikzpicture}
\begin{axis}[domain=0:10,samples=100,height=6cm,width=10cm, ytick=\empty,xtick=\empty]

% Draw gaussians                                                                                                                                            
\addplot [name path=model,very thick, smooth, color=red!50!black] {gauss(5,1)};
\addplot [name path=obs,very thick, smooth, color=black] {gauss(5,1.5)};

% calculate region to shade                                                                                                                                   
\path[name path=lower,
intersection segments={
of=model and obs,
sequence=A0 -- B1
}
];
\path[name path=axis] (axis cs:-10,0) -- (axis cs:16,0);

% shade region                                                                                                                                                
\addplot[color=red!20!gray!20]
fill between[
of=axis and lower,
soft clip={domain=1:10}]
;

\end{axis}
\end{tikzpicture}

\end{frame}
\end{document}

谢谢，奥利弗

Answer 1

您必须在代码中将该段添加A2到sequence：

sequence=A0 -- B1 -- A2

或者使用较新版本的语法：

sequence={L1 -- R2 --L3}

代码：

\documentclass{standalone}
\usepackage{pgfplots}
\pgfplotsset{compat=1.13}
\usepgfplotslibrary{fillbetween}
\pgfmathdeclarefunction{gauss}{2}
  {\pgfmathparse{1/(#2*sqrt(2*pi))*exp(-((x-#1)^2)/(2*#2^2))}}


\begin{document}
\begin{tikzpicture}
\begin{axis}[
  domain=0:10,samples=100,
  height=6cm,width=10cm,
  ytick=\empty,xtick=\empty,
  every axis plot/.append style={very thick,smooth}
]

\addplot [name path=model, color=red!50!black] {gauss(5,1)};
\addplot [name path=obs, color=black] {gauss(5,1.5)};
\path[name path=axis] (axis cs:0,0) -- (axis cs:10,0);

\path[name path=lower,
  intersection segments={of=model and obs,
    sequence={L1 -- R2 --L3}
  }];
\addplot[color=red!20!gray!20]
  fill between[of= lower and axis];

\end{axis}
\end{tikzpicture}
\end{document}

---

下面是一张显示所用段的附加图片L1（橙色）、R2（蓝色）和L2（绿色）：

代码：

\documentclass{standalone}
\usepackage{pgfplots}
\pgfplotsset{compat=1.13}
\usepgfplotslibrary{fillbetween}
\pgfmathdeclarefunction{gauss}{2}
  {\pgfmathparse{1/(#2*sqrt(2*pi))*exp(-((x-#1)^2)/(2*#2^2))}}


\begin{document}
\begin{tikzpicture}
\begin{axis}[
  domain=0:10,samples=100,
  height=6cm,width=10cm,
  ytick=\empty,xtick=\empty,
  every axis plot/.append style={very thick,smooth}
]

\addplot [name path=model, color=red!50!black] {gauss(5,1)};
\addplot [name path=obs, color=black] {gauss(5,1.5)};
\path[name path=axis] (axis cs:0,0) -- (axis cs:10,0);


\path[draw,orange,line width=1mm,
  intersection segments={of=model and obs,
    sequence={L1}
  }];

\path[draw,blue,line width=1mm,
  intersection segments={of=model and obs,
    sequence={R2}
  }];


\path[draw,green,line width=1mm,
  intersection segments={of=model and obs,
    sequence={L3}
  }];

\end{axis}
\end{tikzpicture}
\end{document}

Answer 2

这是一个（不太好的）解决方案/解决方法。

\documentclass{standalone}
\usepackage{pgfplots}
\usepgfplotslibrary{fillbetween}
\pgfmathdeclarefunction{gauss}{2}{\pgfmathparse{1/(#2*sqrt(2*pi))*exp(-((x-#1)^2)/(2*#2^2))}}
\pgfplotsset{compat=newest}

\begin{document}

\begin{tikzpicture}
\begin{axis}[domain=0:10,samples=100,height=6cm,width=10cm, ytick=\empty,xtick=\empty]

\addplot [name path=model,very thick, smooth, color=red!50!black] {gauss(5,1)};
\addplot [name path=obs,very thick, smooth, color=black] {gauss(5,1.5)};

\path[name path=lower,
intersection segments={
of=model and obs,
sequence=A0 -- B1
}
];
\path[name path=axis] (axis cs:-10,0) -- (axis cs:16,0);

\addplot[color=red!20!gray!20]
fill between[
of= model and axis]
;
\addplot[color=white]
fill between[
of=model and obs,
soft clip={domain=1:10}]
;

\end{axis}
\end{tikzpicture}

\end{document}