\begin{eqnarray}
F_{\theta}=[(2m+M)R^2+2J_w+2n^2J_m]\ddot{\theta}+(MLR \cos ( \psi - \zeta) -2n^2J_m) \ddot{\psi} -MLR \dot{\psi}^2 sin ( \psi - \zeta) + (M+m)g \sin \zeta \label{eqn13}\\
F_{\psi} = (MLR cos \psi-2J_m)\ddot{\theta}+(ML^2+J_{ \psi}+2J_m)\ddot{ \psi} -MgL sin \psi-ML^2\dot{ \phi}^2 sin \psi cos \psi\label{eqn14}
\end{eqnarray}
答案1
这是你想要的？
% My standard header for TeX.SX answers:
\documentclass[a4paper]{article} % To avoid confusion, let us explicitly
% declare the paper format.
\usepackage[T1]{fontenc} % Not always necessary, but recommended.
% End of standard header. What follows pertains to the problem at hand.
\usepackage{amsmath}
\begin{document}
Some text before the equations.
\begin{align}
F_{\theta} &=
\begin{aligned}[t]
&\bigl[(2m+M)R^2+2J_w+2n^2J_m\bigr]\ddot{\theta} \\
&\quad +\bigl(MLR \cos ( \psi - \zeta) -2n^2J_m\bigr) \ddot{\psi} \\
&\quad -MLR \dot{\psi}^2 \sin ( \psi - \zeta)
+ (M+m)g \sin \zeta
\end{aligned}
\label{eqn13} \\[\jot]
F_{\psi} &=
\begin{aligned}[t]
&(MLR \cos \psi-2J_m)\ddot{\theta}
+(ML^2+J_{ \psi}+2J_m) \ddot{\psi} \\
&\quad -MgL \sin \psi-ML^2\dot{ \phi}^2 \sin \psi \cos \psi
\end{aligned}
\label{eqn14}
\end{align}
Some text after the equations.
\end{document}
输出：
