如何合并 \pgfextra 块中的行

Question

我想使用样式“覆盖”（append after command）制作一个块，它看起来像这样，但带有连接的线段。

有没有办法修改我的代码来实现连接？不幸的是，我真的不知道如何使用\pgfextra，我修改了另一个我闲置的 .tex 文件，该文件基于我放错位置的 TikZ 示例，所以对我来说这是货物崇拜 TikZ 编程。

\documentclass[border=6mm]{standalone}
\usepackage{tikz}
\usetikzlibrary{shapes,shadows,arrows,positioning,calc}
\begin{document}
\begin{tikzpicture}[node distance=5mm, auto,
    block/.style={
        thick,draw=black,
        rectangle, minimum size=6mm, minimum width=12mm,
        minimum height=10mm, node distance=5mm,
        top color=white,
        drop shadow
    },
      satstyle/.style={
        append after command={
             \pgfextra{\let\lastnode\tikzlastnode} 
            ($(\lastnode.south) + (0,0.3em)$) edge
            ($(\lastnode.north) + (0,-0.3em)$) 
            ($(\lastnode.west) + (0.3em,0)$) edge
            ($(\lastnode.east) + (-0.3em,0)$) 
            ($(\lastnode.south west) + (0.5em,0.5em)$) edge[-, very thick]
            ($(\lastnode.south) + (-0.2em,0.5em)$)
            ($(\lastnode.south) + (-0.2em,0.5em)$) edge[-, very thick]
            ($(\lastnode.north) + (0.2em,-0.5em)$) 
            ($(\lastnode.north) + (0.2em,-0.5em)$) edge[-, very thick]
            ($(\lastnode.north east) + (-0.5em,-0.5em)$)
        }
       },
    >=latex
    ]
\node (X) [block, satstyle] at (0,0) {};
\end{tikzpicture}
\end{document}

Answer 1

尝试：

\documentclass[border=6mm]{standalone}
\usepackage{tikz}
\usetikzlibrary{shapes,shadows,arrows,positioning,calc}
\newcommand\ppbb{path picture bounding box}

\begin{document}
\begin{tikzpicture}[node distance=5mm, auto,
block/.style = {
    rectangle, draw, thick, fill=white,
              minimum height=9mm, minimum width=12mm,
              drop shadow
                  },
  sat/.style = {block,  
    path picture={
        \draw[-latex,thin]
    ($(\ppbb.south) + (0,0.5ex)$) edge ($(\ppbb.north) + (0,-0.5ex)$)
    ($(\ppbb.west)  + (0.5ex,0)$)  to  ($(\ppbb.east)  + (-0.5ex,0)$);
        \draw[very thick] 
    ($(\ppbb.south west) + (1ex,1ex)$) --
        ($(\ppbb.south) + (-1ex,1ex)$) --
        ($(\ppbb.north) + (1ex,-1ex)$) --
        ($(\ppbb.north east) + (-1ex,-1ex)$);
                        }% end path picture
                    },
                    ]
\node (X) [sat] {};
\end{tikzpicture}
\end{document}

我稍微重新设计了你的饱和度符号：

绘制边缘时，仅绘制给定坐标之间的线段。

Answer 2

将 Zarko 的答案改编成我原来的设计，我需要使用\newcommand\ppbb{path picture bounding box}和

satstyle/.style = {
    path picture={
    \draw[-, thin]
        ($(\ppbb.south) + (0,0.3em)$) edge ($(\ppbb.north) + (0,-0.3em)$)
        ($(\ppbb.west)  + (0.3em,0)$)  to  ($(\ppbb.east)  + (-0.3em,0)$);
    \draw[very thick] 
        ($(\ppbb.south west) + (0.5em,0.5em)$) --
        ($(\ppbb.south) + (-0.2em,0.5em)$) --
        ($(\ppbb.north) + (0.2em,-0.5em)$) --
        ($(\ppbb.north east) + (-0.5em,-0.5em)$);
      }% end path picture
   },

完整示例：

\documentclass[border=6mm]{standalone}
\usepackage{tikz}
\usetikzlibrary{shapes,shadows,arrows,positioning,calc}
\newcommand\ppbb{path picture bounding box}
\begin{document}
\begin{tikzpicture}[node distance=5mm, auto,
    block/.style={
        thick,draw=black,
        rectangle, minimum size=6mm, minimum width=12mm,
        minimum height=10mm, node distance=5mm,
        top color=white,
        drop shadow
    },
    satstyle/.style = {
        path picture={
        \draw[-, thin]
            ($(\ppbb.south) + (0,0.3em)$) edge ($(\ppbb.north) + (0,-0.3em)$)
            ($(\ppbb.west)  + (0.3em,0)$)  to  ($(\ppbb.east)  + (-0.3em,0)$);
        \draw[very thick] 
            ($(\ppbb.south west) + (0.5em,0.5em)$) --
            ($(\ppbb.south) + (-0.2em,0.5em)$) --
            ($(\ppbb.north) + (0.2em,-0.5em)$) --
            ($(\ppbb.north east) + (-0.5em,-0.5em)$);
          }% end path picture
       },
    >=latex
    ]
\node (X) [block, satstyle] at (0,0) {};
\end{tikzpicture}
\end{document}