多线方程

Question

考虑以下乳胶代码：

\begin{document}
\begin{align*}
    \text{d}F &= 0\\
    (\text{d}x^{\mu}\partial_{\mu})\wedge (F_{0i}\ \text{d}x^{0}\wedge \text{d}x^{i}+F_{ij}\ \text{d}x^{i}\wedge \text{d}x^{j}) &= 0\\
    (\text{d}x^{0}\partial_{0}+\text{d}x^{k}\partial_{k})\wedge (F_{0i}\ \text{d}x^{0}\wedge \text{d}x^{i}+F_{ij}\ \text{d}x^{i}\wedge \text{d}x^{j}) &= 0\\
    \begin{multlined}[t][0.0\textwidth]
    (\partial_{0}F_{0i})\ \text{d}x^{0}\wedge\text{d}x^{0}\wedge\text{d}x^{i}+(\partial_{0}F_{ij})\ \text{d}x^{0}\wedge\text{d}x^{i}\wedge\text{d}x^{j}\\
    +(\partial_{k}F_{0i})\ \text{d}x^{k}\wedge\text{d}x^{0}\wedge\text{d}x^{i}+(\partial_{k}F_{ij})\ \text{d}x^{k}\wedge\text{d}x^{i}\wedge\text{d}x^{j}\end{multlined} &= 0\\
\end{align*}
\end{document}

如果你编译它，你会发现最后的等式是一个多线等式，但是这个等式右边的 0 不在 = 符号的右边，而是在正上方。

如何修复此问题？

Answer 1

这里似乎没有必要multline，因为以下内容似乎提供了您想要的内容：

\documentclass{article}

\usepackage{amsmath}

\newcommand{\dx}{\mathrm{d}x}
\newcommand{\mathand}{\wedge}

\begin{document}

\begin{align*}
  \text{d}F &= 0\\
  (\dx^\mu \partial_\mu) \mathand (F_{0i} \dx^0 \mathand \dx^i + F_{ij} \dx^i \mathand \dx^j) &= 0 \\
  (\dx^0 \partial_0 + \dx^k \partial_k) \mathand (F_{0i} \dx^0 \mathand \dx^{i}+F_{ij} \dx^i \mathand \dx^j) &= 0 \\
  (\partial_0 F_{0i}) \dx^0 \mathand \dx^0 \mathand \dx^i + (\partial_0 F_{ij}) \dx^0 \mathand \dx^i \mathand \dx^j + {} \qquad \\
  (\partial_k F_{0i}) \dx^k \mathand \dx^0 \mathand \dx^i + (\partial_k F_{ij}) \dx^k \mathand \dx^i \mathand \dx^j &= 0
\end{align*}

\end{document}