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完整代码

tag-icon • tag-icon tikz-pgf
完整代码

我正在尝试声明一个自定义 pgf 形状。我遇到一个问题，我无法访问东、西、北、南锚点。这有效：

\pgfdeclareshape{mixer}{%
  \inheritsavedanchors[from=circle]
  \inheritanchorborder[from=circle]
  \inheritanchor[from=circle]{center}
  \inheritanchor[from=circle]{north}
  \inheritanchor[from=circle]{south}
  \inheritanchor[from=circle]{west}
  \inheritanchor[from=circle]{east}
  \backgroundpath{%
    \pgf@x=\radius
    \pgf@y=\radius
    \centerpoint \pgf@xa=\pgf@x \pgf@ya=\pgf@y
    \pgfpathcircle{\pgfpoint{\pgf@xa}{\pgf@ya}}{\radius}
  }
}

但是，当我尝试使用类似的东西时：

\northeast \pgf@xa=\pgf@x \pgf@ya=\pgf@y

或者

\north \pgf@xa=\pgf@x \pgf@ya=\pgf@y

我收到未定义的命令。这是为什么？

答案1

你还有机会：这些锚点的定义隐藏在

\pgf@anchor@⟨shape name⟩@⟨anchor name⟩

因此\north可以通过

\pgf@anchor@mixer@north

完整代码

\documentclass{article}
\usepackage{tikz}

\begin{document}
\makeatletter
\pgfdeclareshape{mixer}{%
  \inheritsavedanchors[from=circle]
  \inheritanchorborder[from=circle]
  \inheritanchor[from=circle]{center}
  \inheritanchor[from=circle]{north}
  \inheritanchor[from=circle]{south}
  \inheritanchor[from=circle]{west}
  \inheritanchor[from=circle]{east}
  \backgroundpath{%
    \centerpoint
    \pgfpathcircle{\pgfpoint{\pgf@x}{\pgf@y}}{\radius}
    \pgfpathmoveto{\pgf@anchor@mixer@east}
    \pgfpathlineto{\pgf@anchor@mixer@north}
    \pgfpathmoveto{\pgf@anchor@mixer@south}
    \pgfpathlineto{\pgf@anchor@mixer@west}
    \pgfusepath{stroke}
  }
}

\tikz\node[mixer]{0123456789};

\end{document}

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