算法/algorithmicx booktabs 样式的水平线

Question

我正在使用包算法，算法和书签。

算法和表格都有水平线。如你所见，这些线有不同的线强度和间距。

我希望算法和其标题周围的水平线和间距与 的精美设计完全匹配booktabs。

\documentclass{scrreprt}

\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{lmodern}

\usepackage{algorithm}
\usepackage{algpseudocode}
\usepackage{booktabs}

\begin{document}

\begin{algorithm}
\caption{Euclid}
\begin{algorithmic}[1]
\Procedure{Euclid}{$a,b$}\Comment{The g.c.d. of a and b}
\State $r\gets a\bmod b$
\While{$r\not=0$}\Comment{We have the answer if r is 0}
\State $a\gets b$
\State $b\gets r$
\State $r\gets a\bmod b$
\EndWhile\label{euclidendwhile}
\State \textbf{return} $b$\Comment{The gcd is b}
\EndProcedure
\end{algorithmic}
\end{algorithm}

\begin{table}
\centering
\begin{tabular}{ccc}
\toprule
First name & Last Name & Age \\
\midrule
John & Doe & 30 \\
John & Doe & 30 \\
\bottomrule
\end{tabular}
\end{table}

\end{document}

Answer 1

好主意！

我们可以通过修改来创建新的浮动样式ruled：

\documentclass{scrreprt}

\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{lmodern}

\usepackage{algorithm}
\usepackage{algpseudocode}
\usepackage{booktabs}

\makeatletter
\newcommand\fs@booktabsruled{%
  \def\@fs@cfont{\bfseries\strut}\let\@fs@capt\floatc@ruled
  \def\@fs@pre{\hrule height\heavyrulewidth depth0pt \kern\belowrulesep}%
  \def\@fs@mid{\kern\aboverulesep\hrule height\lightrulewidth\kern\belowrulesep}%
  \def\@fs@post{\kern\aboverulesep\hrule height\heavyrulewidth\relax}%
  \let\@fs@iftopcapt\iftrue
}
\makeatother

\floatstyle{booktabsruled}
\restylefloat{algorithm}

\begin{document}

\begin{algorithm}
\caption{Euclid}
\begin{algorithmic}[1]
\Procedure{Euclid}{$a,b$}\Comment{The g.c.d. of a and b}
\State $r\gets a\bmod b$
\While{$r\not=0$}\Comment{We have the answer if r is 0}
\State $a\gets b$
\State $b\gets r$
\State $r\gets a\bmod b$
\EndWhile\label{euclidendwhile}
\State \textbf{return} $b$\Comment{The gcd is b}
\EndProcedure
\end{algorithmic}
\end{algorithm}

\begin{table}
\centering
\begin{tabular}{ccc}
\toprule
First name & Last Name & Age \\
\midrule
John & Doe & 30 \\
John & Doe & 30 \\
\bottomrule
\end{tabular}
\end{table}

\end{document}