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使用 Tikz 在绘图中放置弧线

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使用 Tikz 在绘图中放置弧线

我正在尝试使用 tikz 获取以下图表，但是无法实现：

在此处输入图片描述

这是我迄今为止最好的尝试：

在此处输入图片描述

这是产生我的（相当糟糕的）尝试的 MWE：

\documentclass[standalone]
\usepackage{tikz}
\usetikzlibrary{fit, calc, matrix, positioning, arrows.meta, intersections, through, backgrounds, patterns}

\begin{document}

\begin{tikzpicture}[my plot/.style={thick, smooth, samples=100, domain=0:1}, my grid/.style={densely dotted,opacity=0.5, every node/.style={black,opacity=1}}, my axis/.style={latex-latex},scale=0.75]
\coordinate (start plot) at (0,{(0)});
\coordinate (end plot) at (6,{(6)});
\draw[my axis] ([shift={(-0cm,0cm)}]start plot |- end plot) node[above] {$h_2$} |- node[coordinate](origin){} ([shift={(0cm,-0cm)}]start plot -| end plot) node[right] {$h_1$};
\def\x{0.5}\def\y{4}\def\p{0.55}
\draw[Red,thick,domain=0:90] plot ({cos(\x)}, {sin(\x)});
\end{tikzpicture}

\end{document}

关于如何获得所需输出的任何线索？ 感谢大家的时间！

答案1

像这样： 在此处输入图片描述

这个图像相当复杂：

\documentclass [tikz, margin=3mm]{standalone}
\usetikzlibrary{arrows, calc, intersections, positioning}
\usepackage{sansmath}

\begin{document}
    \begin{tikzpicture}[
    node distance = 0pt,
 every pin/.style = {pin distance=11mm, pin edge={stealth-}},
every node/.style = {font=\sansmath, color=blue!60!black},
       dot/.style = {circle, fill=black, inner sep=0mm, minimum size=2mm,
                     node contents={}},% 
      line/.style = {-stealth, shorten >=1mm, shorten <= 1mm},
                        ]
\coordinate (O) at (0,0);
\coordinate[right=55mm of O]    (X);
\coordinate[above=55mm of O]    (Y);
\coordinate[above right=1 and 2 of O]   (d);
\coordinate[right=2 of X |- Y]  (e);
% main axis
\draw[->]   ([xshift=-0.1] O) -- (X) node[right] {$h_1$};
\draw[->]   ([yshift=-0.1] O) -- (Y) node[above] {$h_2$};
% hyperbolas
\draw[blue, thick,name path=A]              ($(e)-(5.4,0)$) arc(180:270:5.5 and 4.4);
\draw[blue, thick, scale=0.9,name path=B]   ($(e)-(5.4,0)$) arc(180:270:5.5 and 4.4);
\draw[blue, thick, scale=0.8,name path=C]   ($(e)-(5.4,0)$) arc(180:270:5.5 and 4.4);
% main locus + S dotted line
\path[name path=S] (O) -- (45:6);
\path[name intersections={of=B and S, by={s}}];
\coordinate[left =of s -| O]    (s1);
\coordinate[below=of s |- O]    (s2);
\draw[red,thick]    let \p1 = ($(s)-(O)$),
                        \n1 = {veclen(\x1,\y1)} in
                    ($(O)+(\n1,0)$) arc(0:90:\n1);
\draw[densely dotted]  (s1) -|  (s2) node [pos=0.25,above] {$S$};
\node[dot,at=(s),pin=60:{$F(S,d)$}];
% auxilary axis
\draw[densely dashed]   (Y -| d) |- ([xshift=2cm] X |- d); 
\node[dot,at=(d),label=below left:$d$];
% hyperbola comments
\node[align=left,right] (comment) at (5,4) {equilateral hyperbolas\\ with $d$ as the origin};
\path[name path=D] (s2) -- (15:8);
\draw[name intersections={of=A and D, by={h1}},line] (comment.210) -- (h1);
\draw[name intersections={of=B and D, by={h2}},line] (comment.210) -- (h2);
\draw[name intersections={of=C and D, by={h3}},line] (comment.210) -- (h3);
    \end{tikzpicture}
\end{document}

红色弧的半径是通过与坐标的 45 度斜率的交点计算得出的O。交点命名为，其到和轴s的投影确定了虚线的起点和终点。yx

双曲线是用xradius=5.5和近似的湾弧yradus=4.4。代码中的注释指示图像的每个元素。通过它们，代码是结构化的，也应该可以澄清代码，希望如此 :)

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