![带交叉点的圆圈周围的方框](https://linux22.com/image/353215/%E5%B8%A6%E4%BA%A4%E5%8F%89%E7%82%B9%E7%9A%84%E5%9C%86%E5%9C%88%E5%91%A8%E5%9B%B4%E7%9A%84%E6%96%B9%E6%A1%86.png)
我想创建一个带有三个相交圆的矩形框:
\documentclass[a4paper,11pt,fleqn]{scrartcl}
\usepackage{pgf,tikz}
\usetikzlibrary{arrows,shadows,decorations.pathreplacing,intersections,positioning,fit,calc,backgrounds}
\def\firstcircle{(0,0) circle (1.5cm)}
\def\secondcircle{(60:2.1cm) circle (1.5cm)}
\def\thirdcircle{(0:2.1cm) circle (1.5cm)}
\begin{document}
\begin{figure}[H]
\centering
\begin{tikzpicture}
\begin{scope}
\clip \firstcircle;
\clip \secondcircle;
\fill[red] \thirdcircle;
\end{scope}
\node (firstcircle) {};
\node (secondcircle) {};
\node (thirdcircle) {};
\draw[name=first] \firstcircle node[below] (A) {$A$};
\draw[name=second] \secondcircle node [above] (B) {$B$};
\draw[name=third] \thirdcircle node [below] (C) {$C$};
\node (box) [fit=(firstcircle)(secondcircle)(thirdcircle), inner sep=1cm,draw,rounded corners] {};
\end{tikzpicture}
\end{figure}
\end{document}
我的问题是:矩形应该围绕所有圆圈。
答案1
像这样:
我显著地改变了你的代码,圆圈被绘制为节点:
\documentclass[a4paper,11pt,fleqn]{scrartcl}
\usepackage{pgf,tikz}
\usetikzlibrary{arrows,shadows,decorations.pathreplacing,intersections,positioning,fit,calc,backgrounds}
\def\firstcircle{(0,0) circle (1.5cm)}
\def\secondcircle{(60:2.1cm) circle (1.5cm)}
\def\thirdcircle{(0:2.1cm) circle (1.5cm)}
\begin{document}
\begin{figure}%[H]
\centering
\begin{tikzpicture}[
C/.style = {circle, draw, minimum size=30mm},% C as circle, minimum size is circle diameter
F/.style = {draw, rounded corners, inner sep=1cm}% F as fit node
]
\node (first) [C] at (0,0) {$A$};
\node (second) [C] at (60:2.1) {$B$};
\node (third) [C] at ( 0:2.1) {$B$};
\node (box) [F, fit=(first)(second)(third)] {};
\begin{scope}
\clip \firstcircle;
\clip \secondcircle;
\fill[red] \thirdcircle;
\end{scope}
\end{tikzpicture}
\end{figure}
\end{document}