答案1
- 以您的声誉您应该知道您应该提供 MWE。
- 如果您已经知道它们的名称,为什么还要询问如何在 LaTeX 中重现符号
\zeta
?\sum
如果此代码不能解决您的问题,请编辑您的问题并更加具体:
\documentclass{book}
\usepackage{amsmath, amssymb}
\begin{document}
\[
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \sum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
\]
\end{document}
编辑:
正如 Mico 所说,这是使用包的结果newtxmath
:
\documentclass{book}
\usepackage{newtxmath}
\DeclareMathOperator*{\mysum}{\text{\raisebox{-2pt}{\scalebox{2}{$\Sigma$}}}}
\begin{document}
\[
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \sum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
\]
\end{document}
最终,您可以创建自己的数学运算符。
第二次编辑
正如您正确指出的那样,我的第一个解决方案(\mysum
)在没有采用显示样式时不会变小。
我创建了另一个命令(\mynewsum
),它可以根据操作符的大小进行缩放\sum
。
如果您更喜欢我的第一种显示样式解决方案,则可以混合使用前两种解决方案(请参阅\myfinesum
)。
\documentclass{book}
\usepackage{amsmath, amssymb}
\usepackage{array}
\usepackage{booktabs}
\renewcommand*{\arraystretch}{3}
\usepackage{graphicx}
\usepackage{scalerel}
\DeclareMathOperator*{\mysum}{\raisebox{-2pt}{\scalebox{2}{$\Sigma$}}}
\DeclareMathOperator*{\mynewsum}{\scalerel*{\Sigma}{\sum}}
\DeclareMathOperator*{\myfinesum}{%
\mathchoice
{\raisebox{-2pt}{\scalebox{2}{$\Sigma$}}}%
{\scalerel*{\Sigma}{\sum}}%
{\scalerel*{\Sigma}{\sum}}%
{\scalerel*{\Sigma}{\sum}}
}
\begin{document}
\noindent
\begin{tabular}{l>{$\displaystyle}c<{$}>{$\textstyle}c<{$}>{$\scriptstyle}c<{$}>{$\scriptscriptstyle}c<{$}}
\toprule
&
\text{Display style}
&
\text{Text style}
&
\textstyle\text{Script style}
&
\textstyle\text{Scriptscript style}
\\[10pt]
\midrule
\textbackslash\texttt{mysum}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \mysum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \mysum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \mysum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \mysum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
\\[10pt]
\textbackslash\texttt{mynewsum}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \mynewsum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \mynewsum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \mynewsum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \mynewsum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
\\[10pt]
\textbackslash\texttt{myfinesum}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \myfinesum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \myfinesum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \myfinesum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
&
-\frac{{\zeta}^{\prime}(s)}{\zeta(s)} = \myfinesum_{m\geq 1}\frac{\Lambda(n)}{{n}^{s}}
\\[10pt]
\bottomrule
\end{tabular}
\end{document}