tikz 命名路径的反向剪辑

Question

我正在尝试使用非常酷的倒置剪辑这个问题结合use path我偷来的密钥，重新使用命名路径这个问题但是，似乎我从 stackexchange 窃取 TikZ 代码的货运技巧在这里不够用，因为在我构建的 MWE 中，剪辑的反转没有按预期工作：

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{intersections}
\begin{document}

\tikzset{invclip/.style={clip,insert path={{[reset cm]
      (-16383.99999pt,-16383.99999pt) rectangle (16383.99999pt,16383.99999pt)
}}}}

\makeatletter
\tikzset{
  use path for main/.code={%
    \tikz@addmode{%
      \expandafter\pgfsyssoftpath@setcurrentpath\csname tikz@intersect@path@name@#1\endcsname
    }%
  },
  use path for actions/.code={%
    \expandafter\def\expandafter\tikz@preactions\expandafter{\tikz@preactions\expandafter\let\expandafter\tikz@actions@path\csname tikz@intersect@path@name@#1\endcsname}%
  },
  use path/.style={%
    use path for main=#1,
    use path for actions=#1,
  }
}
\makeatother

\begin{tikzpicture}[outer sep=0mm]
  \coordinate (A) at (-1,-1);
  \coordinate (B) at (1,-1);
  \coordinate (C) at (1,1);
  \coordinate (D) at (-1,1);
  \path[draw=black,name path=P] (A) -- (B) -- (C) -- (D) --cycle;
  \begin{scope}
    \begin{pgfinterruptboundingbox} % useful to avoid the rectangle in the bounding box
      \path[invclip] (A) -- (B) -- (C) -- (D); % works just fine
      %\path[invclip,use path=P]; % doesn't work at all
    \end{pgfinterruptboundingbox} 
  \fill[orange!50] (-2,-2) rectangle (2,2);
  \end{scope}
\end{tikzpicture} 
\end{document}

这很好用：

但这不起作用：

如何使用反向剪辑use path？