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绘制图表箭头的问题

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绘制图表箭头的问题

附上 latex 中的代码。我想从 $R'$ 画一个（虚线）箭头到 $R_S$，但我定义的箭头总是与来自 $R_S$ 的箭头合并。我该怎么做？

\usepackage{tikz-cd}

\begin{document}

\begin{tikzcd}
S \arrow[r, "i_R"] \arrow[d, "\phi| _S"]
   & R \arrow [r,"\tau"] \arrow[d,"\phi"] & R_S  \arrow[dl,dashed,"\exists !\phi'"]   \\
(R')^{*} \arrow [r,"i_{R'}"] 
   & R' % \arrow [ur,dashed,"\exists !\tau'" yshift=-2.5ex]
\end{tikzcd}

\end{document}

答案1

您可以移动两个对角箭头；我还建议交换垂直箭头中的标签。

\documentclass{article}
\usepackage{tikz-cd}

\begin{document}

\begin{tikzcd}
S \arrow[r, "i_R"] \arrow[d, "\phi| _S"']
   & R \arrow[r,"\tau"] \arrow[d,"\phi"']
   & R_S \arrow[dl,dashed,"\exists !\phi'",shift left=0.5ex] \\
(R')^{*} \arrow[r,"i_{R'}"]
   & R'  \arrow[ur,dashed,"\exists !\tau'",shift left=0.5ex]
\end{tikzcd}

\end{document}

（抱歉，由于技术原因，目前我无法添加图片）

您可以通过向右移动两个对角箭头并交换标签位置来交换它们。

\documentclass{article}
\usepackage{tikz-cd}

\begin{document}

\begin{tikzcd}
S \arrow[r,"i_R"] \arrow[d,"\phi| _S"']
   & R \arrow[r,"\tau"] \arrow[d,"\phi"']
   & R_S  \arrow[dl,dashed,"\exists !\phi'\!"',shift right=0.5ex] \\
(R')^{*} \arrow[r,"i_{R'}"]
   & R'  \arrow[ur,dashed,"\exists !\tau'"', shift right=0.5ex]
\end{tikzcd}

\end{document}

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