我想自动添加时间，以便 Latex 可以制定时间表。
这是已知的日期，但是否有可能存在一个包或类似时间的东西。
\documentclass{article}
\usepackage{datenumber}
\begin{document}
\setdatetoday
\addtocounter{datenumber}{30}%
\setdatebynumber{\thedatenumber}%
In 30 days is \datedate
10:30-\addtime{10:30}{0:45} - talk 1 \\ %this would add 45min
\addtime{10:30}{0.45}-\addtime{10:30}{1:30} talk 2 \\ %this would add 1h30min
\end{document}
答案1
我不知道这个包，但可以写一个宏：
overflowdays如果时间超过午夜，则会出现一个包含 1 的 LaTeX 计数器（代码中的示例）。
\documentclass{article}
\usepackage{datenumber}
\makeatletter
\newcount\@hours
\newcount\@minutes
\newcounter{overflowdays}
\newcommand*{\addtime}[2]{%
\@add@time#1\@@atendi#2\@@atendii
}
\def\@add@time#1:#2\@@atendi#3:#4\@@atendii{%
% add hours
\@hours=#1\advance\@hours#3\relax
% add minutes
\@minutes=#2\advance\@minutes#4\relax
% get full hours from minutes
\@tempcnta\@minutes\divide\@tempcnta60\relax
% add them to the hours
\advance\@hours\@tempcnta
% full hours from minutes back to minutes
\multiply\@tempcnta60\relax
% and subtract from minutes
\advance\@minutes-\@tempcnta
% get full days from hours
\@tempcnta\@hours\divide\@tempcnta24\relax
% set overflowday
\setcounter{overflowdays}{\@tempcnta}%
% full days from hours back to hours
\multiply\@tempcnta24\relax
% and subtract from hours
\advance\@hours-\@tempcnta
% give out
\ifnum\@hours<10\relax0\fi% comment out to get rid of leading 0 for hours
\the\@hours:\ifnum\@minutes<10\relax0\fi\the\@minutes
}
\makeatother
\begin{document}
\setdatetoday
\addtocounter{datenumber}{30}%
\setdatebynumber{\thedatenumber}%
In 30 days is \datedate
10:30-\addtime{10:30}{0:45} - talk 1 \\ %this would add 45min
\addtime{10:30}{0:45}-\addtime{10:30}{1:30} talk 2 \\ %this would add 1h30min
Works too (\verb|\addtime{23:30}{2:00}|): \addtime{23:30}{2:00} and we are \theoverflowdays\ day(s) further
There is no input controll (\verb|\addtime{25:90}{30:70}|): \addtime{25:90}{30:70} (days: \theoverflowdays)
\end{document}