具有超过 9 个参数的宏

Question 1

那如果要画五块板呢？或者八块呢？

这是一个接受的实现任何板数，并在环境中成对输出figure。如果数量为奇数，则最后一个板会在另一个环境中单独输出figure。

\documentclass{article}
\usepackage[
  a4paper,
  hmargin = 2.4cm,
  vmargin = 3cm
]{geometry}

\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{xcolor}
\usepackage{xparse}
\usepackage{xskak}

\setchessboard{smallboard}

\ExplSyntaxOn

\NewDocumentCommand{\opgaverLoesninger}{m}
 {
  \svend_opgaver_loesninger:n { #1 }
 }

\tl_new:N \l__svend_opgaver_final_tl
\seq_new:N \l__svend_opgaver_tables_in_seq
\seq_new:N \l__svend_opgaver_tables_out_seq

\cs_new_protected:Nn \svend_opgaver_loesninger:n
 {
  \seq_set_split:Nnn \l__svend_opgaver_tables_in_seq { \\ } { #1 }
  \seq_clear:N \l__svend_opgaver_tables_out_seq
  \seq_map_inline:Nn \l__svend_opgaver_tables_in_seq
   {
    \seq_put_right:Nx \l__svend_opgaver_tables_out_seq
     {
      \__svend_opgaver_board:nn
       { \clist_item:nn { ##1 } { 1 } } 
       { \clist_item:nn { ##1 } { 2 } } 
      \__svend_opgaver_caption:n { \clist_item:nn { ##1 } { 3 } }
     }
   }
  \__svend_opgaver_make_tables:
 }

\cs_new_protected:Nn \__svend_opgaver_board:nn
 {
  \newgame
  \fenboard{#2 ~ #1 ~ - ~ - ~ 0 ~ 1 }
 }

\cs_new_protected:Nn \__svend_opgaver_caption:n
 {
  \scalebox{1.2}{\showboard}\par
  \vspace*{2ex}
  {\LARGE Løsning: ~ \textcolor{blue}{#1}}
 }

\cs_new_protected:Nn \__svend_opgaver_make_tables:
 {
  \tl_clear:N \l__svend_opgaver_final_tl
  \int_if_odd:nT { \seq_count:N \l__svend_opgaver_tables_out_seq }
   {
    \seq_pop_right:NN \l__svend_opgaver_tables_out_seq \l__svend_opgaver_final_tl
   }
  \int_step_inline:nnnn { 1 } { 2 } { \seq_count:N \l__svend_opgaver_tables_out_seq }
   {
    \begin{figure}[!htbp]
    \begin{minipage}[b]{0.5\textwidth}
    \centering
    \seq_item:Nn \l__svend_opgaver_tables_out_seq { ##1 }
    \end{minipage}
    \begin{minipage}[b]{0.5\textwidth}
    \centering
    \seq_item:Nn \l__svend_opgaver_tables_out_seq { ##1+1 }
    \end{minipage}
    \end{figure}
   }
   \tl_if_empty:NF \l__svend_opgaver_final_tl
   {
    \begin{figure}[!htbp]
    \centering
    \tl_use:N \l__svend_opgaver_final_tl
    \end{figure}
   }
 }

\ExplSyntaxOff

\begin{document}

\opgaverLoesninger{
  w, 6k1/6p1/1p5p/3r4/1P6/6P1/4B1KP/8, Lc4 \\
  w, 1k6/pp6/2p3p1/4n1P1/8/P6P/KP1B4/8, Lf4 \\
  w, 8/1p4kp/p5p1/B7/3n4/1P5P/2P3P1/6K1, Lc3 \\
  w, k7/p6p/1p4p1/3r4/1P5P/P5P1/1KB5/8, Le4 \\
  w, k7/p6p/1p4p1/3r4/1P5P/P5P1/1KB5/8, Le4
}

\end{document}

与使用括号的语法相比，用\\逗号分隔板和每个板中的数据更简单且更具可读性。

稍加修改，您还可以设置板的放大倍数（默认 1.2）和每行的板数（默认 2）。

放大倍数用改变mag=<factor>，每行的板数用的n=<number>可选参数设置\opgaverLoesninger。

该选项single（布尔值，single=true隐式）将创建单个图形环境，但您当然要负责使其适合页面。它出现在示例中只是为了举例。如果您尝试\opgaverLoesninger[single]{...}（五个板的相同强制参数），浮动将太大（四个板则不行）。

\documentclass{article}
\usepackage[
  a4paper,
  hmargin = 2.4cm,
  vmargin = 3cm
]{geometry}

\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage{xcolor}
\usepackage{xparse}
\usepackage{xskak}

\setchessboard{smallboard}

\ExplSyntaxOn

\NewDocumentCommand{\opgaverLoesninger}{O{}m}
 {
  \keys_set:nn { svend/opgaver } { n=2, mag=1.2, single=false, #1 }
  \svend_opgaver_loesninger:n { #2 }
 }

\keys_define:nn { svend/opgaver }
 {
  n      .int_set:N  = \l__svend_opgaver_n_int,
  mag    .tl_set:N   = \l__svend_opgaver_mag_tl,
  single .bool_set:N = \l__svend_opgaver_single_bool,
  single .default:n  = true,
 }

\tl_new:N \l__svend_opgaver_final_tl
\seq_new:N \l__svend_opgaver_tables_in_seq
\seq_new:N \l__svend_opgaver_tables_out_seq

\cs_new_protected:Nn \svend_opgaver_loesninger:n
 {
  \seq_set_split:Nnn \l__svend_opgaver_tables_in_seq { \\ } { #1 }
  \seq_clear:N \l__svend_opgaver_tables_out_seq
  \seq_map_inline:Nn \l__svend_opgaver_tables_in_seq
   {
    \seq_put_right:Nx \l__svend_opgaver_tables_out_seq
     {
      \__svend_opgaver_board:nn
       { \clist_item:nn { ##1 } { 1 } } 
       { \clist_item:nn { ##1 } { 2 } } 
      \__svend_opgaver_caption:n { \clist_item:nn { ##1 } { 3 } }
     }
   }
  \__svend_opgaver_make_tables:
 }

\cs_new_protected:Nn \__svend_opgaver_board:nn
 {
  \newgame
  \fenboard{#2 ~ #1 ~ - ~ - ~ 0 ~ 1 }
 }

\cs_new_protected:Nn \__svend_opgaver_caption:n
 {
  \scalebox{\l__svend_opgaver_mag_tl}{\showboard}\par
  \vspace*{2ex}
  {\LARGE Løsning: ~ \textcolor{blue}{#1}}
 }

\cs_new_protected:Nn \__svend_opgaver_make_tables:
 {
  \bool_if:NT \l__svend_opgaver_single_bool { \begin{figure}[!htbp] \centering }
  \int_step_inline:nnnn
   { 1 } % start
   { \l__svend_opgaver_n_int } % step
   { \seq_count:N \l__svend_opgaver_tables_out_seq } % end
   {
    \bool_if:NF \l__svend_opgaver_single_bool { \begin{figure}[!htbp] \centering }
    \int_step_inline:nnnn { 0 } { 1 } { \l__svend_opgaver_n_int - 1 }
     {
      \tl_if_empty:xF
       { \seq_item:Nn \l__svend_opgaver_tables_out_seq { ##1+####1 } }
       {
        \begin{minipage}[b]{ \dim_eval:n { \textwidth/\l__svend_opgaver_n_int } }
        \centering
        \seq_item:Nn \l__svend_opgaver_tables_out_seq { ##1+####1 }
        \end{minipage}
       }
     }
    \bool_if:NTF \l__svend_opgaver_single_bool { \\ \bigskip } { \end{figure} }
   }
  \bool_if:NT \l__svend_opgaver_single_bool { \end{figure} }
 }
\cs_generate_variant:Nn \tl_if_empty:nF { x }

\ExplSyntaxOff

\begin{document}

\opgaverLoesninger[mag=0.5,n=4,single]{
  w, 6k1/6p1/1p5p/3r4/1P6/6P1/4B1KP/8, Lc4 \\
  w, 1k6/pp6/2p3p1/4n1P1/8/P6P/KP1B4/8, Lf4 \\
  w, 8/1p4kp/p5p1/B7/3n4/1P5P/2P3P1/6K1, Lc3 \\
  w, k7/p6p/1p4p1/3r4/1P5P/P5P1/1KB5/8, Le4 \\
  w, k7/p6p/1p4p1/3r4/1P5P/P5P1/1KB5/8, Le4
}

\end{document}

Answer

那如果要画五块板呢？或者八块呢？