我的代码
\begin{subequations}
\begin{numcases}{}
q - 1 & \text{se $\psi = \psi_0$ e $\chi = \chi_0$} \label{roman*} \\
-1 & \text{se $\psi = \psi_0$ e $\chi \neq \chi_0$} \\
0 & \text{se $\psi \neq \psi_0$ e $\chi = \chi_0$} \\
& \text{Se $\chi \neq \chi_0$ e
$\psi \neq \psi_0 \Rightarrow \lvert G(\psi,\chi)\rvert = \sqrt{q}$}
\end{numcases}
\end{subequations}
它列出了(1a),(1b),我想放“i”,“ii”...
答案1
subequations
如果您只想要单层枚举,则不需要。无论您选择哪种方式,都需要重新定义\theequation
:
\documentclass{article}
\usepackage{amsmath,cases}
\begin{document}
Perhaps you're looking for
\begin{subequations}
\renewcommand{\theequation}{\theparentequation\roman{equation}}%
\begin{numcases}{}
q - 1 & \text{se $\psi = \psi_0$ e $\chi = \chi_0$} \\
-1 & \text{se $\psi = \psi_0$ e $\chi \neq \chi_0$} \\
0 & \text{se $\psi \neq \psi_0$ e $\chi = \chi_0$} \\
& \text{Se $\chi \neq \chi_0$ e
$\psi \neq \psi_0 \Rightarrow \lvert G(\psi,\chi)\rvert = \sqrt{q}$}
\end{numcases}
\end{subequations}
But you could also be interested in%
\renewcommand{\theequation}{\roman{equation}}
\begin{numcases}{}
q - 1 & \text{se $\psi = \psi_0$ e $\chi = \chi_0$} \\
-1 & \text{se $\psi = \psi_0$ e $\chi \neq \chi_0$} \\
0 & \text{se $\psi \neq \psi_0$ e $\chi = \chi_0$} \\
& \text{Se $\chi \neq \chi_0$ e
$\psi \neq \psi_0 \Rightarrow \lvert G(\psi,\chi)\rvert = \sqrt{q}$}
\end{numcases}
\end{document}
答案2
我不推荐cases
和numcases
,而是empheq
。
\documentclass{article}
\usepackage[T1]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[italian]{babel}
\usepackage{amsmath,empheq}
\begin{document}
\begin{subequations}\label{general}
\renewcommand{\theequation}{\theparentequation\,\roman{equation}}%
\begin{empheq}[left=\empheqlbrace]{alignat=2}
& q-1 &\qquad& \text{se $\psi = \psi_0$ e $\chi = \chi_0$} \\
& {-1} & & \text{se $\psi = \psi_0$ e $\chi \neq \chi_0$} \\
& 0 & &\text{se $\psi \neq \psi_0$ e $\chi = \chi_0$} \\
& & &\text{Se $\chi \neq \chi_0$ e
$\psi \neq \psi_0 \Rightarrow
\lvert G(\psi,\chi)\rvert = \sqrt{q}$}
\end{empheq}
\end{subequations}
\end{document}