![宏参数和pgf键解释问题](https://linux22.com/image/371359/%E5%AE%8F%E5%8F%82%E6%95%B0%E5%92%8Cpgf%E9%94%AE%E8%A7%A3%E9%87%8A%E9%97%AE%E9%A2%98.png)
在此 mmwe 中,如果在 macto 的参数上使用相同的测试,则该测试有效,但在 pgf 键上使用时则失败。知道原因吗?
\documentclass{article}
\usepackage{xparse,tikz}
\usetikzlibrary{calc}
\usepackage{ifluatex}
\makeatletter
\ifluatex
\RequirePackage{pdftexcmds}
\let\pdfstrcmp\pdf@strcmp
\let\pdffilemoddate\pdf@filemoddate
\fi
\tikzset{%
Cote/.style={to path={\pgfextra{
\pgfinterruptpath
\draw[>=latex,|<->|] let
\p1=($(\tikztostart)!2mm!90:(\tikztotarget)$),
\p2=($(\tikztotarget)!2mm!-90:(\tikztostart)$)
in(\p1) -- (\p2) node[pos=.5,sloped,above]{\Cote{\@aspect}};
\endpgfinterruptpath
}(\tikztostart) -- (\tikztotarget) \tikztonodes}}
}
\pgfkeys{tikz/Cote/.cd,
aspect/.store in=\@aspect,
aspect=o,
}
\makeatletter
\NewDocumentCommand{\Cote}{m
}{%
\ifnum\pdfstrcmp{\unexpanded\expandafter{\@car#1\@nil}}{(}=\z@
true
\else
false
\fi
}
\makeatother
\begin{document}
\Cote{(F)} -- \Cote{F}
\begin{tikzpicture}
\path[Cote/aspect=F] (0,0) to[Cote] (5,0) ;
\path[Cote/aspect=(F)] (0,2) to[Cote] (5,2) ;
\end{tikzpicture}
\end{document}
编辑更复杂的宏存在问题。我的 mwe 太小了。
非最小例子是我对这个问题的回答:如何定义 tikz 样式选项以在特定点之间绘制尺寸线
\documentclass{article}
\usepackage{xparse,tikz}
\usetikzlibrary{calc}
\usepackage{ifluatex}
\makeatletter
\ifluatex
\RequirePackage{pdftexcmds}
\let\pdfstrcmp\pdf@strcmp
\let\pdffilemoddate\pdf@filemoddate
\fi
\tikzset{%
Cote/.style={to path={\pgfextra{
\pgfinterruptpath
\draw[>=latex,|<->|] let
\p1=($(\tikztostart)!2mm!90:(\tikztotarget)$),
\p2=($(\tikztotarget)!2mm!-90:(\tikztostart)$)
in(\p1) -- (\p2) node[pos=.5,sloped,above]{\expandafter\Cote{$\pi$}\expandafter<\@aspect>};
\endpgfinterruptpath
}(\tikztostart) -- (\tikztotarget) \tikztonodes}}
}
\pgfkeys{tikz/Cote/.cd,
aspect/.store in=\@aspect,
aspect=o,
}
\makeatletter
\NewDocumentCommand{\Cote}{md<>
}{%
#1
\ifnum\pdfstrcmp{\unexpanded\expandafter{\@car#2\@nil}}{(}=\z@
true
\else
false
\fi
}
\makeatother
\begin{document}
\Cote{$\pi$}<($\pi$)> -- \Cote{$\pi$}<F>
\begin{tikzpicture}
\path[Cote/aspect=F] (0,0) to[Cote] (5,0) ;
\path[Cote/aspect=(F)] (0,2) to[Cote] (5,2) ;
\end{tikzpicture}
\end{document}
答案1
你的问题不太清楚,但我猜你想
\documentclass{article}
\usepackage{xparse,tikz}
\usetikzlibrary{calc}
\usepackage{ifluatex}
\makeatletter
\ifluatex
\RequirePackage{pdftexcmds}
\let\pdfstrcmp\pdf@strcmp
\let\pdffilemoddate\pdf@filemoddate
\fi
\tikzset{%
Cote/.style={to path={\pgfextra{
\pgfinterruptpath
\draw[>=latex,|<->|] let
\p1=($(\tikztostart)!2mm!90:(\tikztotarget)$),
\p2=($(\tikztotarget)!2mm!-90:(\tikztostart)$)
in(\p1) -- (\p2) node[pos=.5,sloped,above]{\expandafter\Cote\expandafter{\@aspect}};
\endpgfinterruptpath
}(\tikztostart) -- (\tikztotarget) \tikztonodes}}
}
\pgfkeys{tikz/Cote/.cd,
aspect/.store in=\@aspect,
aspect=o,
}
\makeatletter
\NewDocumentCommand{\Cote}{m
}{%
\ifnum\pdfstrcmp{\unexpanded\expandafter{\@car#1\@nil}}{(}=\z@
true
\else
false
\fi
}
\makeatother
\begin{document}
\Cote{(F)} -- \Cote{F}
\begin{tikzpicture}
\path[Cote/aspect=F] (0,0) to[Cote] (5,0) ;
\path[Cote/aspect=(F)] (0,2) to[Cote] (5,2) ;
\end{tikzpicture}
\end{document}
测试@aspect
is的第一个标记(
,而不是测试是否为@aspect
is (
(这始终为假)