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数学投影机问题

tag-icon • tag-icon beamer compiling mathematics
数学投影机问题

我删除了可以正常工作的幻灯片，检查它们是否编译正确，并将所有不能正常工作的幻灯片都包含在这里（也单独检查）。

\documentclass[17pt]{beamer}
\usepackage{amsmath}
\usepackage{verbatim}
\usepackage[utf8]{inputenc}
\usepackage[OT1]{fontenc}
\usepackage{graphicx}
\usebackgroundtemplate

\begin{document}
\sffamily \bfseries

\begin{frame}
\frametitle{Limit of a Rational Polynomial Function}\pause
begin{itemize}
\item Let us find $\lim_{x \to \2} \frac {3x^{2}-x-10} {x^{2}-4}$
\end{itemize}
\end{frame}

\begin{frame}
\frametitle{Limit of a Rational Polynomial Function}\pause
begin{itemize}
\item To understand limits of functions
\end{itemize}
$\lim_{x \to \2} \frac {3x^{2}-x-10} {x^{2}-4} = 2.75$
\end{frame}

\begin{frame}
\frametitle{Limit of a Discontinuous Function}\pause
Let us find $\lim_{x \to \0} f(x) = \[   \left\{
\begin{array}{11}
          $(2x+3) & x \leq 0$ \\
          $3(x+1) & x $>$ 0$ \\
          \end{array}
          \right. \]
and $\lim_{x \to \1} f(x) = \[   \left\{
\begin{array}{11}
          $(2x+3) & x \leq 0$ \\
          $3(x+1) & x $>$ 0$ \\
          \end{array}
          \right. \]
\end{frame}

\begin{frame}
\frametitle{Limit of a Discontinuous Function}\pause
Let us find $\lim_{x \to \0} f(x) = \[   \left\{
\begin{array}{11}
          $(2x+3) & x \leq 0$ = 3 \\
          $3(x+1) & x $>$ 0$ \\
          \end{array}
          \right. \]
and $\lim_{x \to \1} f(x) = \[   \left\{
\begin{array}{11}
          $(2x+3) & x \leq 0$ = 6 \\
          $3(x+1) & x $>$ 0$ \\
          \end{array}
          \right. \]
\end{frame}

\begin{frame}
\frametitle{Assignment}\pause
\begin{itemize} [<+-|alert@+>] 
\item Find $\lim_{x \to \2} (x^{3}-2x^{2})/(x^{2}-5x+6)$
\item Evaluate $\lim_{x \to \0} \frac {sin 4x} {sin 2x}$
\end{itemize}
\end{frame}

\end{document}

答案1

一些错误：

  • begin{itemize}->\begin{itemize}

  • \2-> 2，\1和相同\0

  • 正如大卫卡莱尔在他的评论中所说的那样，array已经处于数学模式，您不需要使用$...$。

  • 数组的对齐不ll应该11

  • 不要\[...\]在数学模式中嵌套显示数学环境（）

  • sin应该\sin

  • \usepackage{graphicx}并且\usebackgroundtemplate是多余的

  • 不是一个 tex 错误，但(2x+3) x≤0=6看起来具有误导性。也cases可能更适合作为array

\documentclass[17pt]{beamer}
\usepackage{amsmath}
\usepackage{verbatim}
\usepackage[utf8]{inputenc}
\usepackage[OT1]{fontenc}
\usepackage{graphicx}
\usebackgroundtemplate

\begin{document}
\sffamily \bfseries

\begin{frame}
\frametitle{Limit of a Rational Polynomial Function}\pause
\begin{itemize}
\item Let us find $\lim_{x \to 2} \frac {3x^{2}-x-10} {x^{2}-4}$
\end{itemize}
\end{frame}

\begin{frame}
\frametitle{Limit of a Rational Polynomial Function}\pause
\begin{itemize}
\item To understand limits of functions
\end{itemize}
$\lim_{x \to 2} \frac {3x^{2}-x-10} {x^{2}-4} = 2.75$
\end{frame}

\begin{frame}
\frametitle{Limit of a Discontinuous Function}\pause
Let us find \[\lim_{x \to 0} f(x) = \left\{
\begin{array}{ll}
          (2x+3) & x \leq 0 \\
          3(x+1) & x > 0 \\
          \end{array}
          \right. \]
and \[\lim_{x \to 1} f(x) = \left\{
\begin{array}{ll}
          (2x+3) & x \leq 0 \\
          3(x+1) & x > 0 \\
          \end{array}
          \right. \]
\end{frame}

\begin{frame}
\frametitle{Limit of a Discontinuous Function}\pause
Let us find \[\lim_{x \to 0} f(x) = \left\{
\begin{array}{ll}
          (2x+3) & x \leq 0 = 3 \\
          3(x+1) & x > 0 \\
          \end{array}
          \right. \]
and \[\lim_{x \to 1} f(x) = \left\{
\begin{array}{ll}
          (2x+3) & x \leq 0 = 6 \\
          3(x+1) & x > 0 \\
          \end{array}
          \right. \]
\end{frame}

\begin{frame}
\frametitle{Assignment}\pause
\begin{itemize} [<+-|alert@+>] 
\item Find $\lim_{x \to 2} (x^{3}-2x^{2})/(x^{2}-5x+6)$
\item Evaluate $\lim_{x \to 0} \frac {\sin 4x} {\sin 2x}$
\end{itemize}
\end{frame}

\end{document}

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