同伦图

Question

我需要用 tikZ 构建一个像这里这样的图表https://en.wikipedia.org/wiki/Homotopy_category_of_chain_complexes。我尝试了很多次，但是没有效果。

Answer 1

\documentclass[12pt]{article}
\usepackage{amsmath}
\usepackage{tikz-cd}
\begin{document}
\[\begin{tikzcd}[row sep=1.5cm,column sep=1.5cm]
\cdots \arrow[r,"d_A^{n-2}"] & A^{n-1}\arrow[dl,"h^{n-1}" description]
\arrow[r,"d_A^{n-1}"] \arrow[d,"~f^{n-1}",xshift=-1mm] \arrow[d,swap,"g^{n-1}~",xshift=1mm] 
& A^{n} \arrow[dl,"h^{n}" description,swap]
\arrow[r,"d_A^{n}"] \arrow[d,"~f^{n}",xshift=-1mm] \arrow[d,swap,"g^{n}~",xshift=1mm]
& A^{n+1} \arrow[dl,"h^{n+1}" description,swap]
\arrow[r,"d_A^{n+1}"] \arrow[d,"~f^{n+1}",xshift=-1mm] \arrow[d,swap,"g^{n-1}~",xshift=1mm]
& \arrow[dl,"h^{n+2}" description,swap]\cdots\\
\cdots \arrow[r,"d_A^{n-2}"] &  B^{n-1}\arrow[r,"d_B^{n-1}"] & B^{n} 
\arrow[r,"d_B^{n}"] & B^{n+1} 
\arrow[r,"d_B^{n+1}"] & \cdots
\\
\end{tikzcd}\]
\end{document}

Answer 2

为了锻炼（我还在学习tikz-cd）和娱乐：

• 基于土拨鼠用（非常）小的变化来回答
• DAS为较短的代码定义了对角箭头的样式（ ）
• 用于'交换功能：例如\arrow[d,"g^{n-1}" ',代替\arrow[d,"g^{n-1}",swap,
• 向下箭头的位移与土拨鼠回答
• 尝试在编辑器中美化代码

\documentclass[12pt,margin=3mm]{standalone}
\usepackage{tikz-cd}

\begin{document}
\[
    \begin{tikzcd}[
   row sep = 1.5cm,
column sep = 1.5cm,
 DAS/.style = {% Diagonal Arrow with Sloped labels
              dl, swap, sloped, pos=0.3}
                    ]
\cdots \arrow[r,"d_A^{n-2}"]
    & A^{n-1}\arrow["h^{n-1}",DAS]
             \arrow[r,"d_A^{n-1}"]
                \arrow[d,"g^{n-1}" ',xshift=-1mm]
                \arrow[d,"f^{n-1}",xshift=1mm]
        & A^{n} \arrow["h^{n}",DAS]
                \arrow[r,"d_A^{n}"]
                    \arrow[d,"g^{n}" ',xshift=-1mm]
                    \arrow[d,"f^{n}",xshift=1mm]
            & A^{n+1}   \arrow[dl,"h^{n+1}",DAS]
                        \arrow[r,"d_A^{n+1}"]
                            \arrow[d,"g^{n-1}" ',xshift=-1mm]
                            \arrow[d,"f^{n+1}",xshift=1mm]
                & \arrow["h^{n+2}",DAS]\cdots    \\
\cdots \arrow[r,"d_A^{n-2}"]
    &  B^{n-1}  \arrow[r,"d_B^{n-1}"]
        & B^{n} \arrow[r,"d_B^{n}"]
            & B^{n+1} \arrow[r,"d_B^{n+1}"]
                & \cdots
\end{tikzcd}
\]
\end{document}