对于此代码,曲线之间的填充与箭头线宽的一半重叠,如垂直箭头所示。那么,如何确保它不与任何边界路径重叠?
此外,对于\tikzfillbetween
,我想知道如何让它接受两个以上的周围路径。例如,如何判断\tikzfillbetween
要填充的区域是由路径Paxis
和形成Raxis
的curve
?
\documentclass[border=2mm]{standalone}
\usepackage{pgfplots,tikz}
\usetikzlibrary{shapes.geometric,hobby,arrows.meta}
\usepgfplotslibrary{fillbetween}
\begin{document}
\begin{tikzpicture}[x=1.5mm,y=1.5mm]
\draw[ultra thick, ->, name path=Paxis] (0,0) ++(0,15) -- ++(0,-10) coordinate (tipParrow);
\draw[ultra thick, ->, name path=Raxis] (0,0) ++(0,15) -- ++(10,0) coordinate (tipRarrow);
\draw [ultra thick,name path=curve] [use Hobby shortcut] (tipParrow) ++(0,2) .. ++(2,1) .. ++(2,4.5) .. ([shift={(-2,0)}]tipRarrow);
\tikzfillbetween[ of=curve and Raxis, split] {red};
\end{tikzpicture}
\end{document}
答案1
将填充放在背景层上:
\documentclass[border=2mm]{standalone}
\usepackage{pgfplots}
\usetikzlibrary{arrows.meta, backgrounds, hobby, shapes.geometric,}
\usepgfplotslibrary{fillbetween}
\begin{document}
\begin{tikzpicture}[x=1.5mm,y=1.5mm]
\draw[ultra thick, ->, name path=Paxis] (0,0) ++(0,15) -- ++(0,-10) coordinate (tipParrow);
\draw[ultra thick, ->, name path=Raxis] (0,0) ++(0,15) -- ++(10,0) coordinate (tipRarrow);
\draw [ultra thick,name path=curve] [use Hobby shortcut] (tipParrow) ++(0,2) .. ++(2,1) .. ++(2,4.5) .. ([shift={(-2,0)}]tipRarrow);
\scoped[on background layer]
\tikzfillbetween[ of=curve and Raxis, split] {red};
\end{tikzpicture}
\end{document}
编辑: 我将上面的代码简化为:
\documentclass[border=2mm]{standalone}
\usepackage{pgfplots}
\usetikzlibrary{arrows.meta, backgrounds, hobby, shapes.geometric,}
\usepgfplotslibrary{fillbetween}
\begin{document}
\begin{tikzpicture}[x=1.5mm,y=1.5mm]
\draw[ultra thick, Straight Barb-Straight Barb, name path=Paxis]
(0,-10) coordinate (tipParrow) |- (10,0) coordinate (tipRarrow);
\draw [ultra thick,name path=curve] [use Hobby shortcut]
(tipParrow) ++(0,2) .. ++(2,1) .. ++(2,4.5) .. ([shift={(-2,0)}]tipRarrow);
\scoped[on background layer]
\tikzfillbetween[of=curve and Paxis, split] {red};
\end{tikzpicture}
\end{document}
现在的结果是:
你的第二个问题:上面的代码部分解决了它。