我想链接 TikZ 图片中的公式元素......
如同
代码:
\documentclass[t]{beamer}
\usepackage{tikz}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usepackage{color}
\usepackage{tcolorbox}
\begin{document}
\begin{frame}{}
\begin{tcolorbox}
\begin{center}
\begin{tikzpicture}[scale=1.0]
%\tkzInit[xmax=4, ymax=6]
%\tkzAxeXY
%\tkzGrid
%\tkzClip
%
\tkzDefPoint(0,3){A}
\tkzDefPoint(0,0){B}
\tkzDefPoint(6,0){C}
\tkzDrawSegment(A,B)
\tkzDrawSegment(A,C)
\tkzDrawSegment(B,C)
\tkzLabelPoints[below](B,C)
\tkzLabelPoints[above](A)
\tkzMarkRightAngle[size=0.4](A,B,C)
\tkzLabelSegment[below,pos=.5](B,C){Side opposite to $\angle A$}
\tkzLabelSegment[sloped](B,A){Side adjacent to $\angle A$}
%\tkzLabelSegment[right,pos=.5,red](B,C){25 cm}
\tkzLabelSegment[sloped](C,A){Hypotenuse}
\tkzMarkAngle[size=0.8](A,C,B)
\tkzMarkAngle[size=0.6](B,A,C)
%\tkzMarkAngle[size=0.5,mark=|](C,B,A)
\end{tikzpicture}
\end{center}
\end{tcolorbox}
%
\begin{tcolorbox}[opacityframe=0.5,colback=red!5!white,colframe=red!75!black]
\begin{align*}
\cos A = \frac{\text{Side adjacent to }\angle A}{Hypotenuse} =\frac{AB}{AC}
\end{align*}
\end{tcolorbox}
\end{frame}
%
\end{document}
答案1
与链接答案非常相似。使用记忆图片来记住节点,使用alias
给标签命名,并使用overlay
连接事物。
\documentclass[t]{beamer}
\usepackage{tikz}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usepackage{color}
\usepackage{tcolorbox}
\newcommand{\tikznode}[2]{\relax
\ifmmode%
\tikz[remember picture,baseline=(#1.base),inner sep=0pt] \node (#1) {$#2$};
\else
\tikz[remember picture,baseline=(#1.base),inner sep=0pt] \node (#1) {#2};%
\fi}
\begin{document}
\begin{frame}{}
\begin{tcolorbox}
\begin{center}
\begin{tikzpicture}[scale=1.0,remember picture]
%\tkzInit[xmax=4, ymax=6]
%\tkzAxeXY
%\tkzGrid
%\tkzClip
%
\tkzDefPoint(0,3){A}
\tkzDefPoint(0,0){B}
\tkzDefPoint(6,0){C}
\tkzDrawSegment(A,B)
\tkzDrawSegment(A,C)
\tkzDrawSegment(B,C)
\tkzLabelPoints[below](B,C)
\tkzLabelPoints[above](A)
\tkzMarkRightAngle[size=0.4](A,B,C)
\tkzLabelSegment[below,pos=.5,alias=lab2](B,C){Side opposite to $\angle A$}
\tkzLabelSegment[sloped,alias=lab1](B,A){Side adjacent to $\angle A$}
%\tkzLabelSegment[right,pos=.5,red](B,C){25 cm}
\tkzLabelSegment[sloped,alias=lab3](C,A){Hypotenuse}
\tkzMarkAngle[size=0.8](A,C,B)
\tkzMarkAngle[size=0.6](B,A,C)
%\tkzMarkAngle[size=0.5,mark=|](C,B,A)
\end{tikzpicture}
\end{center}
\end{tcolorbox}
%
\begin{tcolorbox}[opacityframe=0.5,colback=red!5!white,colframe=red!75!black]
\begin{align*}
\cos A = \frac{\tikznode{Lab1}{\text{Side adjacent to }\angle A}}{%
\tikznode{Lab3}{Hypotenuse}} =\frac{AB}{AC}
\end{align*}
\end{tcolorbox}
\begin{tikzpicture}[overlay,remember picture]
\draw[latex-latex] (Lab1) to[out=135,in=-90] (lab1.west);
\draw[latex-latex] (Lab3.east) to[out=0,in=-45] (lab3.east);
\end{tikzpicture}
\end{frame}
%
\end{document}
编辑:如果您想逐步展示连接,我建议您overlay-beamer-styles
。
\documentclass[t]{beamer}
\usepackage{tikz}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usepackage{color}
\usepackage{tcolorbox}
\usetikzlibrary{overlay-beamer-styles} %<-added
\newcommand{\tikznode}[2]{\relax
\ifmmode%
\tikz[remember picture,baseline=(#1.base),inner sep=0pt] \node (#1) {$#2$};
\else
\tikz[remember picture,baseline=(#1.base),inner sep=0pt] \node (#1) {#2};%
\fi}
\begin{document}
\begin{frame}{}
\begin{tcolorbox}
\begin{center}
\begin{tikzpicture}[scale=1.0,remember picture]
%\tkzInit[xmax=4, ymax=6]
%\tkzAxeXY
%\tkzGrid
%\tkzClip
%
\tkzDefPoint(0,3){A}
\tkzDefPoint(0,0){B}
\tkzDefPoint(6,0){C}
\tkzDrawSegment(A,B)
\tkzDrawSegment(A,C)
\tkzDrawSegment(B,C)
\tkzLabelPoints[below](B,C)
\tkzLabelPoints[above](A)
\tkzMarkRightAngle[size=0.4](A,B,C)
\tkzLabelSegment[below,pos=.5,alias=lab2](B,C){Side opposite to $\angle A$}
\tkzLabelSegment[sloped,alias=lab1](B,A){Side adjacent to $\angle A$}
%\tkzLabelSegment[right,pos=.5,red](B,C){25 cm}
\tkzLabelSegment[sloped,alias=lab3](C,A){Hypotenuse}
\tkzMarkAngle[size=0.8](A,C,B)
\tkzMarkAngle[size=0.6](B,A,C)
%\tkzMarkAngle[size=0.5,mark=|](C,B,A)
\end{tikzpicture}
\end{center}
\end{tcolorbox}
%
\begin{tcolorbox}[opacityframe=0.5,colback=red!5!white,colframe=red!75!black]
\begin{align*}
\cos A = \frac{\tikznode{Lab1}{\text{Side adjacent to }\angle A}}{%
\tikznode{Lab3}{Hypotenuse}} =\frac{AB}{AC}
\end{align*}
\end{tcolorbox}
\begin{tikzpicture}[overlay,remember picture]
\draw[latex-latex,visible on=<2->] (Lab1) to[out=135,in=-90] (lab1.west);
\draw[latex-latex,visible on=<3->] (Lab3.east) to[out=0,in=-45] (lab3.east);
\end{tikzpicture}
\end{frame}
%
\end{document}