我想把第三个表往下拉，这样就能和其他表对齐了。还有一个问题，就是第三个表的表头连在一起了。
\documentclass[usenames,dvipsnames]{beamer}
\usepackage{dcolumn}
\usefonttheme[onlymath]{serif}
\usepackage{amsmath}
\usepackage{booktabs}
\usepackage[justification=centering]{caption}
\usetheme{Madrid}
\newcolumntype{2}{D{.}{}{2.0}}
\begin{document}
\begin{frame}
\frametitle{GF(7)}
\setlength\doublerulesep{0pt}
\begin{columns}
\footnotesize
\setlength{\tabcolsep}{3.5pt}
\noindent
\begin{column}{0.4\linewidth}
\centering
\begin{tabular}{r|*{7}{2}}
+ & 0 & 1 & 2 & 3 & 4 & 5 & 6\\
\hline
0 & 0 & 1 & 2 & 3 & 4 & 5 & 6\\
1 & 1 & 2 & 3 & 4 & 5 & 6 & 0\\
2 & 2 & 3 & 4 & 5 & 6 & 0 & 1\\
3 & 3 & 4 & 5 & 6 & 0 & 1 & 2\\
4 & 4 & 5 & 6 & 0 & 1 & 2 & 3\\
5 & 5 & 6 & 0 & 1 & 2 & 3 & 4\\
6 & 6 & 0 & 1 & 2 & 3 & 4 & 5\\
\end{tabular}
\captionof{table}{Addition modulo $7$}
\end{column}
\begin{column}{0.4\linewidth}
\centering
\begin{tabular}{r|*{7}{2}}
x & 0 & 1 & 2 & 3 & 4 & 5 & 6\\
\hline
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\
1 & 0 & 1 & 2 & 3 & 4 & 5 & 6\\
2 & 0 & 2 & 4 & 6 & 1 & 3 & 5\\
3 & 0 & 3 & 6 & 2 & 5 & 1 & 4\\
4 & 0 & 4 & 1 & 5 & 2 & 6 & 3\\
5 & 0 & 5 & 3 & 1 & 6 & 4 & 2\\
6 & 0 & 6 & 5 & 4 & 3 & 2 & 1\\
\end{tabular}
\captionof{table}{Multiplicative modulo $7$}
\end{column}
\begin{column}{0.2\linewidth}
\centering
\begin{tabular}{r|*{2}{2}}
w & -w & w^{-1}\\
\hline
0 & 0 & -\\
1 & 6 & 1\\
2 & 5 & 4\\
3 & 4 & 5\\
4 & 3 & 2\\
5 & 2 & 3\\
6 & 1 & 6\\
\end{tabular}
\captionof{table}{Additive and Multiplicative inverse modulo $7$}
\end{column}
\end{columns}
\end{frame}
\end{document}
答案1
\documentclass[usenames,dvipsnames]{beamer}
\usepackage{dcolumn}
\usefonttheme[onlymath]{serif}
\usepackage{amsmath}
\usepackage{booktabs}
\usepackage[justification=centering]{caption}
\usetheme{Madrid}
\newcolumntype{2}{D{.}{}{2.0}}
\begin{document}
\begin{frame}
\frametitle{GF(7)}
\setlength\doublerulesep{0pt}
\begin{columns}[T]
\footnotesize
\setlength{\tabcolsep}{3.5pt}
\noindent
\begin{column}{0.4\linewidth}
\centering
\begin{tabular}{r|*{7}{2}}
+ & 0 & 1 & 2 & 3 & 4 & 5 & 6\\
\hline
0 & 0 & 1 & 2 & 3 & 4 & 5 & 6\\
1 & 1 & 2 & 3 & 4 & 5 & 6 & 0\\
2 & 2 & 3 & 4 & 5 & 6 & 0 & 1\\
3 & 3 & 4 & 5 & 6 & 0 & 1 & 2\\
4 & 4 & 5 & 6 & 0 & 1 & 2 & 3\\
5 & 5 & 6 & 0 & 1 & 2 & 3 & 4\\
6 & 6 & 0 & 1 & 2 & 3 & 4 & 5\\
\end{tabular}
\captionof{table}{Addition modulo $7$}
\end{column}
\begin{column}{0.4\linewidth}
\centering
\begin{tabular}{r|*{7}{2}}
x & 0 & 1 & 2 & 3 & 4 & 5 & 6\\
\hline
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\
1 & 0 & 1 & 2 & 3 & 4 & 5 & 6\\
2 & 0 & 2 & 4 & 6 & 1 & 3 & 5\\
3 & 0 & 3 & 6 & 2 & 5 & 1 & 4\\
4 & 0 & 4 & 1 & 5 & 2 & 6 & 3\\
5 & 0 & 5 & 3 & 1 & 6 & 4 & 2\\
6 & 0 & 6 & 5 & 4 & 3 & 2 & 1\\
\end{tabular}
\captionof{table}{Multiplicative modulo $7$}
\end{column}
\begin{column}{0.2\linewidth}
\centering
\begin{tabular}{r|*{2}{2}}
w & -w & w^{-1}\\
\hline
0 & 0 & -\\
1 & 6 & 1\\
2 & 5 & 4\\
3 & 4 & 5\\
4 & 3 & 2\\
5 & 2 & 3\\
6 & 1 & 6\\
\end{tabular}
\captionof{table}{Additive and Multiplicative inverse modulo $7$}
\end{column}
\end{columns}
\end{frame}
\end{document}
答案2
- 我不会混淆
caption包和beamer。beamer 有自己的caption机制 - 在你的情况下，我宁愿使用标题
\parbox（名称Table似乎没有提供信息 - 用数字命名列类型不是一个明智的想法
在你的情况下，你不需要
dcolumn包和d列\documentclass[usenames,dvipsnames]{beamer} \usefonttheme[onlymath]{serif} \usetheme{Madrid} \usepackage{amsmath} \usepackage{array} \newcolumntype{C}{>{$}c<{$}} \begin{document} \begin{frame} \frametitle{GF(7)} \begin{columns}[T] \footnotesize \setlength{\tabcolsep}{4.5pt} \begin{column}{0.35\linewidth} \centering \begin{tabular}{r|*{7}{C}} + & 0 & 1 & 2 & 3 & 4 & 5 & 6\\ \hline 0 & 0 & 1 & 2 & 3 & 4 & 5 & 6\\ 1 & 1 & 2 & 3 & 4 & 5 & 6 & 0\\ 2 & 2 & 3 & 4 & 5 & 6 & 0 & 1\\ 3 & 3 & 4 & 5 & 6 & 0 & 1 & 2\\ 4 & 4 & 5 & 6 & 0 & 1 & 2 & 3\\ 5 & 5 & 6 & 0 & 1 & 2 & 3 & 4\\ 6 & 6 & 0 & 1 & 2 & 3 & 4 & 5\\ \end{tabular}\\[1ex] \parbox{\linewidth}{\centering Addition modulo $7$} \end{column} \begin{column}{0.35\linewidth} \centering \begin{tabular}{r|*{7}{C}} x & 0 & 1 & 2 & 3 & 4 & 5 & 6\\ \hline 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0\\ 1 & 0 & 1 & 2 & 3 & 4 & 5 & 6\\ 2 & 0 & 2 & 4 & 6 & 1 & 3 & 5\\ 3 & 0 & 3 & 6 & 2 & 5 & 1 & 4\\ 4 & 0 & 4 & 1 & 5 & 2 & 6 & 3\\ 5 & 0 & 5 & 3 & 1 & 6 & 4 & 2\\ 6 & 0 & 6 & 5 & 4 & 3 & 2 & 1\\ \end{tabular}\\[1ex] \parbox{\linewidth}{\centering Multiplicative modulo $7$} \end{column} \begin{column}{0.3\linewidth} \centering \begin{tabular}{r|CC} w & -w & w^{-1}\\ \hline 0 & 0 & -\\ 1 & 6 & 1\\ 2 & 5 & 4\\ 3 & 4 & 5\\ 4 & 3 & 2\\ 5 & 2 & 3\\ 6 & 1 & 6\\ \end{tabular}\\[1ex] \parbox{\linewidth}{\centering Additive and Multiplicative inverse modulo $7$} \end{column} \end{columns} \end{frame} \end{document}
