如何引用剩余的水平空间？

Question

我正在尝试想出自己的命令来用点填充水平空间的剩余部分，但我希望这些点相对于文本略微降低。这是我的代码：

\newcommand\ansfill{\raisebox{-.2\baselineskip}{\makebox[\linewidth]{\dotfill}}}

当我的线路上没有任何内容时，这很好用

\ansline

但是当我添加任何东西时都会出现 \hbox 溢出错误，因为来自 \makebox 的框始终是 \linewidth。

例如

Example Text \ansfill

给出了一个 overfull hbox 错误。

我需要一个根据水平空间剩余部分而变化的参数。例如：

\newcommand\ansfill{\raisebox{-.2\baselineskip}{\makebox[\whatever-that-is-left]{\dotfill}}}

谢谢。

Answer 1

您可以模拟 的定义\dotfill。我还添加了一个可选参数来设置点的最小宽度。最后一个例子显示了如果没有 会发生什么[8em]。

\documentclass{article}

\newcommand{\ansfill}[1][0pt]{%
  \leavevmode
  \leaders
  \hbox to 0.44em{\hss\raisebox{-2pt}{.}\hss}%
  \hskip #1 plus 1fill
  \kern0pt
}

\begin{document}

Here's a question. \ansfill

Here's another longer question for which we need at least eight ems
of space for the answer. \ansfill[8em]

Here's another longer question for which we need at least eight ems
of space for the answer, even though the line would be almost filled up
with text. \ansfill[8em]

Here's another longer question for which we need at least eight ems
of space for the answer, even though the line would be almost filled up
with text. \ansfill % <--- Uh, oh!

\end{document}

Answer 2

\linegoal同名包定义的维度在这里可能是正确的：

\documentclass[12pt]{article}
\usepackage{linegoal}

\newcommand\ansfill{\raisebox{-.2\baselineskip}{\makebox[\linegoal]{\dotfill}}}

\begin{document}

This is something \ansfill

\end{document}