方程编号位置问题

Question

我有两个很长的方程，但问题是方程式定位的数量是错误的我的代码是，我现在知道边距距离左边 6 厘米但它仍然必须工作我的代码如下所示：

\documentclass [12pt]{article}
\usepackage{float}
%\usepackage{showframe} 
\usepackage{authblk} 
\usepackage{etoolbox}
\usepackage{amsmath}
\usepackage{graphicx}
\usepackage{subcaption}
\usepackage{tabularx,ragged2e,booktabs,caption} 
\usepackage[utf8]{inputenc}
\usepackage[english]{babel}
\usepackage{caption}
\usepackage{amssymb}
\usepackage{graphicx,epstopdf}
\usepackage{caption}
\usepackage{graphicx,kantlipsum,setspace}
\usepackage{mathptmx}
\usepackage{pgfplots}
\captionsetup{font={stretch=1.0}}  %% this affects both figure and table
\setstretch{1.0}
\captionsetup{font=footnotesize}
\usepackage[left=6cm,top=3cm,right=2cm,bottom=3cm]{geometry}
\usepackage{lipsum}
\usepackage{setspace}
\usepackage[export]{adjustbox}
\usepackage{apacite}
\setstretch{1.5}

\newcolumntype{C}[1]{>{\Centering}m{#1}}
\renewcommand\tabularxcolumn[1]{C{#1}}
\newcommand\seqwlimits[3]{\{#1\}_{\mathstrut#2}^{\mathstrut#3}}

\renewcommand\Authfont{\fontsize{15}{1}\selectfont}

\begin{document}
\begin{equation}
        \begin{split}
        Q_{G-Ind}(\theta= H\phi)& =-2log\bigg(\frac{L_T(\tilde{\theta})}{L_T(\hat{\theta})}\bigg)\\&= Q_{G-CC}(\theta= H p) - Q_{G-UC} (H\phi=H p)\\
        & =  \biggl(-2\biggl[L_T(\theta_0)-L_    T(\widehat{\theta})\biggr]\biggr) - \biggl(-2\biggl[L_T(\theta_0)-L_T(\tilde{\theta})\biggr]\biggr)
        \end{split}
        \end{equation}

and the other one is 

\begin{equation}
    M_{j+1} (d;p)= \frac{(1-p)(2j+1)+p(j-d+1)}{(j+1)\sqrt{1-p}} M_j(d;p)-\left(\frac{j}{j+1}\right) M_{j-1}(d;p),
    \end{equation}
\end{document}

Answer 1

两个解决方案：如果可以的话，要么减少左边距，要么删除分数 j/j+1 周围的括号。我借此机会删除了多次加载的包和不兼容的包，例如amssymb和mathptmx。我还建议将后者替换为更完整的newtx，基于 Times 克隆TeX Gyre Termes。最后，我将一些分隔符设置为较小的尺寸（我认为更合适）：

\documentclass [12pt]{article}
\usepackage[utf8]{inputenc}
\usepackage[english]{babel}
\usepackage[left=6cm, right=2cm, vmargin=3cm, showframe]{geometry}
\usepackage{,setspace}
 \usepackage{newtxtext, newtxmath}
\usepackage{amsmath}
\usepackage{float} %\usepackage{showframe}
\usepackage{etoolbox}
\usepackage{subcaption}
\usepackage{tabularx,ragged2e,booktabs,caption}
\usepackage{graphicx,epstopdf}
  \usepackage[export]{adjustbox}
 \usepackage{pgfplots}
 \captionsetup{font={stretch=1.0}} %% this affects both figure and table \setstretch{1.0} \captionsetup{font=footnotesize}
 \usepackage{apacite} \setstretch{1.5}

\newcolumntype{C}[1]{>{\Centering}m{#1}} \renewcommand\tabularxcolumn[1]{C{#1}} \newcommand\seqwlimits[3]{{#1}_{\mathstrut#2}^{\mathstrut#3}}

\providecommand\Authfont{\fontsize{15}{1}\selectfont}

\begin{document}

\begin{equation}
\begin{split} Q_{G-Ind}(\theta= H\phi) &=-2\log\biggl(\frac{L_T(\tilde{\theta})}{L_T(\hat{\theta})}\biggr) \\
&= Q_{G-CC}(\theta= H p) - Q_{G-UC} (H\phi=H p)\\
& = \Bigl(-2\Bigl[L_T(\theta_0)-L_ T(\widehat{\theta})\Bigr]\Bigr) - \Bigl(-2\Bigl[L_T(\theta_0)-L_T(\tilde{\theta})\Bigr]\Bigr)
 \end{split}
\end{equation}
and the other one is
\begin{equation}
M_{j+1} (d;p)= \frac{(1-p)(2j+1)+p(j-d+1)}{(j+1)\sqrt{1-p}} M_j(d;p)-\frac{j}{j+1}M_{j-1}(d;p),
\end{equation}

\end{document}