我正在使用以下代码来制作表格，但看起来一点也不美观。我能够换行，但它会合并到列中给出的值中。任何帮助都将不胜感激。
\begin{document}
\begin{table}[]
\begin{tabular}{ccccc}
\hline
\multirow{2}{*}{\textbf{Years}} & \multicolumn{3}{c}{\textbf{Days}}
& \multirow{2}{*}{\parbox{4cm} {\centering \textbf{Sediment volume excavated
in the year represented by the boundary of the corresponding range of
years}}} \\ \cline{2-4}
& \textbf{\parbox{1.5cm}
{\centeringQ\textgreater{}10 (m\textsuperscript{3}/s)}} &
\textbf{\parbox{1.5cm} {\centering10\textgreater{}Q\textgreater{}20
(m\textsuperscript{3}/s)}} & \textbf{\parbox{1.5cm} {\centering
Q\textgreater{}20 (m\textsuperscript{3}/s)}} & \\
\hline
2002-2003 & 18
& 15 & 3
& 486 \\
2003-2006 & 25
& 18 & 7
& 666 \\
2006-2010 & 24
& 22 & 2
& 217 \\
2010-2013 & 29
& 19 & 10
& 126 \\ \hline
\end{tabular}
\end{table}
\end{document}
答案1
为大段文字使用标题。
\documentclass{article}
\usepackage{booktabs,siunitx,caption}
\sisetup{per-mode=symbol}
\begin{document}
\begin{table}[htp]
\centering
\caption{Sediment volume excavated in the year represented by
the boundary of the corresponding range of years}
\begin{tabular}{ccccc}
\toprule
Years & \multicolumn{3}{c}{Days (\si{\meter\cubed\per\second})} & Sediment \\
\cmidrule(lr){2-4}
& $Q<10$ & $10<Q<20$ & $Q>20$ \\
\midrule
2002-2003 & 18 & 15 & 3 & 486 \\
2003-2006 & 25 & 18 & 7 & 666 \\
2006-2010 & 24 & 22 & 2 & 217 \\
2010-2013 & 29 & 19 & 10 & 126 \\
\bottomrule
\end{tabular}
\end{table}
答案2
\multirow故意与下一行（或几行）重叠。您需要一个支柱将第三行向下推，这意味着它必须放在第二行上。
\documentclass{article}
\usepackage{multirow}
\begin{document}
\begin{table}[]
\sbox0{\parbox[t]{4cm}{\centering \textbf{Sediment volume excavated
in the year represented by the boundary of the corresponding range of
years}}}% measuer height
\begin{tabular}{ccccc}
\hline
\multirow{2}{*}{\textbf{Years}} & \multicolumn{3}{c}{\textbf{Days}}
& \multirow{2}{*}{\usebox0} \\
\cline{2-4}
& \textbf{\parbox[t]{1.5cm}
{\centering Q\textgreater{}10 (m\textsuperscript{3}/s)}} &
\textbf{\parbox[t]{1.5cm} {\centering 10\textgreater{}Q\textgreater{}20
(m\textsuperscript{3}/s)}} & \textbf{\parbox[t]{1.5cm} {\centering
Q\textgreater{}20 (m\textsuperscript{3}/s)}} &
\rule[\dimexpr \arraystretch\normalbaselineskip-\dp0]{0pt}{0pt} \\
\hline
2002-2003 & 18
& 15 & 3
& 486 \\
2003-2006 & 25
& 18 & 7
& 666 \\
2006-2010 & 24
& 22 & 2
& 217 \\
2010-2013 & 29
& 19 & 10
& 126 \\ \hline
\end{tabular}
\end{table}
\end{document}
此版本将第一行向下移动。请注意，\raisebox这次我使用了。 \multirow始终尝试将条目居中，这绝对是我们不希望看到的。要覆盖第二行，我需要将深度设置为 0pt，这可以使用可选参数来完成。
记住这些调整的基线在哪里非常重要，尤其是在使用时\parbox。
\documentclass{article}
\usepackage{multirow}
\begin{document}
\begin{table}[]
\sbox0{\parbox[b]{4cm}{\centering \strut\textbf{Sediment volume excavated
in the year represented by the boundary of the corresponding range of
years}}}% measure height
\sbox1{\textbf{\parbox[t]{1.5cm}
{\centering Q\textgreater{}10 (m\textsuperscript{3}/s)}}}%
\begin{tabular}{ccccc}
\hline
\multirow{2}{*}{\textbf{Years}} & \multicolumn{3}{c}{\textbf{Days}}
& \raisebox{\dimexpr -\dp0-\ht1-\dp1}%
[\dimexpr \ht0-\dp0-\ht1-\dp1][0pt]{\usebox0} \\
\cline{2-4}
& \usebox1 &
\textbf{\parbox[t]{1.5cm} {\centering 10\textgreater{}Q\textgreater{}20
(m\textsuperscript{3}/s)}} & \textbf{\parbox[t]{1.5cm} {\centering
Q\textgreater{}20 (m\textsuperscript{3}/s)}} & \\
\hline
2002-2003 & 18
& 15 & 3
& 486 \\
2003-2006 & 25
& 18 & 7
& 666 \\
2006-2010 & 24
& 22 & 2
& 217 \\
2010-2013 & 29
& 19 & 10
& 126 \\ \hline
\end{tabular}
\end{table}
\end{document}
这次，我在表格中放置了另一个表格，并将其放在\makebox一行中以匹配列宽。
\documentclass{article}
\usepackage{multirow}
\begin{document}
\begin{table}[]
\sbox0{\begin{tabular}{@{}p{1.5cm}p{1.5cm}p{1.5cm}@{}}
\multicolumn{3}{c}{\textbf{Days}} \\
\hline
\centering\textbf{Q\textgreater{}10 (m\textsuperscript{3}/s)} &
\centering\textbf{10\textgreater{}Q\textgreater{}20 (m\textsuperscript{3}/s)} &
\centering\textbf{Q\textgreater{}20 (m\textsuperscript{3}/s)}
\end{tabular}}% savebox not really needed here
\begin{tabular}{ccccc}
\hline
\textbf{Years} & \multicolumn{3}{c}{\usebox0} &
\parbox{4cm}{\centering \strut\textbf{Sediment volume excavated
in the year represented by the boundary of the corresponding range of
years}\strut} \\
\hline
2002-2003 & \makebox[1.5cm]{18} & \makebox[1.5cm]{15} & \makebox[1.5cm]{3} & 486 \\
2003-2006 & 25
& 18 & 7
& 666 \\
2006-2010 & 24
& 22 & 2
& 217 \\
2010-2013 & 29
& 19 & 10
& 126 \\ \hline
\end{tabular}
\end{table}
\end{document}
