如何删除伪代码中的空格

Question

我有这种包含伪代码的图形，我的结果如下所示：

    \documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{cryptocode}
\usepackage{dashbox}

\begin{document}

\begin{figure}[h]
\centering
    \fbox{%
        \pseudocode[]{%
            \textsc{\large Left} \<\< \textsc{\large Right} \\[][\hline]
            \<\< \\[-0.5\baselineskip]
            \begin{subprocedure}%
            \dbox{\procedure{\textsc{Short}}{%
                \text{command} \\
                \text{command}
                }}
            \end{subprocedure}\\[-1.5\baselineskip]
            \< \sendmessageright*{(x,y)} \< 
            \<\<\begin{subprocedure}%
            \dbox{\procedure{\textsc{Long }}{%
                \text{command loooooong}\\
                \text{command loooooong}
                }}
            \end{subprocedure}\\[-1.5\baselineskip]
            \< \sendmessageleft*{(a,b)} \<
            \<\< \\[-1.5\baselineskip]
            \begin{subprocedure}%
            \dbox{\procedure{\textsc{Middle }}{%
                \text{command longer}\\
                \text{command longer}
                }}
            \end{subprocedure}
        }
    }
\end{figure}


\end{document}

如何实现函数“LONG”与右列开头对齐？换句话说，我想删除“LONG”和箭头之间的空白...

另外，是否可以将“SHORT”对齐到箭头旁边的右侧？这样空白就会位于其左侧？

谢谢你的帮助，我找不到有效的解决方案

Answer 1

对于第一个问题，你只是对列数有误。至于第二个问题，由于第一列是左对齐的，你可以\hspace{some length}在程序前面添加一个。长度必须通过反复试验才能找到。以下是可能性：

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{cryptocode}
\usepackage{dashbox}

\begin{document}

\begin{figure}[h]
\centering
    \fbox{%
        \pseudocode[]{%
            \textsc{\large Left} \<\< \textsc{\large Right} \\[][\hline]
            \<\< \\[-0.5\baselineskip]
            \hspace{2.75em} \begin{subprocedure}%
            \dbox{\procedure{\textsc{Short}}{%
                \text{command} \\
                \text{command}
                }}
            \end{subprocedure}\\[-1.5\baselineskip]
            \< \sendmessageright*{(x,y)} \<
            %\< \< delet these column changes
            \begin{subprocedure}%
            \dbox{\procedure{\textsc{Long }}{%
                \text{command loooooong}\\
                \text{command loooooong}
                }}
            \end{subprocedure}\\[-1.5\baselineskip]
            \< \sendmessageleft*{(a,b)} \<
            \<\< \\[-1.5\baselineskip]
            \begin{subprocedure}%
            \dbox{\procedure{\textsc{Middle }}{%
                \text{command longer}\\
                \text{command longer}
                }}
            \end{subprocedure}
        }
    }
\end{figure}

\end{document} 

Answer 2

在\pseudocode列对中创建列；在每对中，第一列左对齐，第二列右对齐。因此你需要

l1 r1 l2 r2 l3

因此“SHORT”和“MIDDLE”应该放在列中r1，“LONG”应该放在列中l3。

如何处理“Left”标签？将其放在列中l1，宽度为零。

命令\>是“转到下一列”；\<是“转到下一列之后的列”。

\documentclass{article}

\usepackage{cryptocode}
\usepackage{dashbox}

\begin{document}

\begin{figure}[htp]
\centering
\fbox{%
  \pseudocode[]{%
    \makebox[0pt][l]{\textsc{\large Left}} \<\< \textsc{\large Right} \\[][\hline]
    \mbox{} \\[-0.5\baselineskip]
\>  \begin{subprocedure}%
      \dbox{\procedure{\textsc{Short}}{%
        \text{command} \\
        \text{command}
      }}
    \end{subprocedure}\\[-1.5\baselineskip]
    \< \sendmessageright*{(x,y)} \<
    \begin{subprocedure}%
      \dbox{\procedure{\textsc{Long }}{%
        \text{command loooooong}\\
        \text{command loooooong}
      }}
    \end{subprocedure}\\[-1.5\baselineskip]
    \< \sendmessageleft*{(a,b)}
    \\[-1.5\baselineskip]
\>    \begin{subprocedure}%
      \dbox{\procedure{\textsc{Middle }}{%
         \text{command longer}\\
         \text{command longer}
      }}
    \end{subprocedure}
  }
}
\end{figure}


\end{document}