![在定理数中添加括号](https://linux22.com/image/386393/%E5%9C%A8%E5%AE%9A%E7%90%86%E6%95%B0%E4%B8%AD%E6%B7%BB%E5%8A%A0%E6%8B%AC%E5%8F%B7.png)
我正在尝试在定义数字中添加括号。我发现了这样的关联,但它对我不起作用:它给了我错误“缺失数字被视为零”
\documentclass[a4paper,12pt]{article}
\usepackage{stix}
\usepackage[T1]{fontenc}
\usepackage[polish]{babel}
\usepackage[utf8]{inputenc}
\usepackage{color}
\usepackage{amsthm}
\setcounter{section}{-1}
\newtheorem{df}{Def.}[subsection]
\newtheorem{nt}[df]{Note}
\newtheorem{st}[df]{Statement}
\makeatletter
\newtheoremstyle{eqStyle}%
{\item[\hskip\labelsep \theorem@headerfont (##2)\ ##1\theorem@separator]}%
{\item[\hskip\labelsep \theorem@headerfont (##2)\ ##1\ (##3)\theorem@separator]}
\makeatother
\theoremstyle{eqStyle}
\newtheorem{eqStyle}[df]{}
%next code.
我不知道这是什么意思。我发现\newtheoremstyle
应该有更多参数,但在我放的链接示例中,它的参数较少,而且正如成员所说,它有效。请帮忙。
谢谢迈克。
编辑:
最小工作示例:
\documentclass[a4paper,12pt]{article}
\usepackage{stix}
\usepackage[T1]{fontenc}
\usepackage[polish]{babel}
\usepackage[utf8]{inputenc}
\usepackage{color}
\usepackage{amsthm}
\setcounter{section}{-1}
\def\n{\newline}
\def\q#1{"#1"}
\def\com#1{{\color[rgb]{0.25, 0.25, 0.25}//#1//}}
\def\aks#1{{\large Aksjomat \underline{#1}}}
\def\bel#1#2{#1 : #2}
\def\kon#1#2{#1 \wedge #2}
\def\imp#1#2{#1 \Rightarrow #2}
\def\rown#1#2{#1 \Leftrightarrow #2}
\def\curly#1{\left\{#1\right\}}
\def\rou#1{\left(#1\right)}
\def\FA#1{\bigwedge\limits_{#1}}
\def\Class{\underline{Class}}
\def\Univ{\underline{Univ}}
\def\Null{\underline{null}}
\def\Char{\underline{Char}}
\def\Var{\underline{Var}}
\newtheorem{df}{Definicja}[subsection]
\newtheorem{nt}[df]{Uwaga}
\newtheorem{st}[df]{Twierdzenie}
%\makeatletter
% \newtheoremstyle{eqStyle}%
% {\item[\hskip\labelsep \theorem@headerfont (##2)\ ##1\theorem@separator]}%
% {\item[\hskip\labelsep \theorem@headerfont (##2)\ ##1\ (##3)\theorem@separator]}
%\makeatother
%\theoremstyle{eqStyle}
\newtheorem{eqStyle}[df]{}
\begin{document}
\section{Intro}
\subsection{Sub 1}
\begin{eqStyle}
\label{013}
\n\n $123 = 100 + 23$
\end{eqStyle}
\end{document}
这有效。当我取消注释中间几行时,出现错误
Missing number, treated as zero.
<to be read again>
\par
l.41 \newtheorem{eqStyle}
[df]{}