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预期输出

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预期输出

我正在尝试绘制这个名为 Kolb Circle 的图像。我尽了最大努力，但还是卡住了。

预期输出

Kolb Circle

平均能量损失

\documentclass[tikz,12pt]{standalone}
\begin{document}
 \begin{tikzpicture}
    \foreach \r in {1,...,5}
  \draw[ thick] (0,0) circle (\r);    
  \foreach \r in {2, 4,...,10}
  \draw (.5*\r,0) node[inner sep=1pt,below=3pt,rectangle,fill=white] {$\r{0}\%$};

    \foreach \a in {0, 90,...,359}
  \draw[thick] (0, 0) -- (\a:5);

    \node(R0) at (5.5,0){RO};
    \node(R0) at (-5.5,0){AE};
    \node(R0) at (0,5.5){CE};
    \node(R0) at (0,-5.5){AC};
    \end{tikzpicture}
\end{document}

答案1

你快到了，不是吗？不幸的是，我无法从你的屏幕截图中读取刻度，但如果你告诉我它们是什么，我会很乐意添加它们。现在我猜它们。

\documentclass[tikz,12pt]{standalone}
\usetikzlibrary{decorations.markings}
\begin{document}
 \begin{tikzpicture}[my ticks/.style={postaction={decorate,
 decoration={ markings,% switch on markings 
 mark=between positions 0 and 1 step 2.5mm
      with
      {
      \pgfmathtruncatemacro{\myX}{mod(\pgfkeysvalueof{/pgf/decoration/mark
      info/sequence number},4)-1}
      \ifnum\myX=0
      \else
      \pgfmathtruncatemacro{\myL}{10+2*\pgfkeysvalueof{/pgf/decoration/mark info/sequence number}}
      \draw (0pt,0pt) -- (0pt,-4pt) node[pos=2,font=\tiny]{\myL};
      \fi
      }
}}}]
    \foreach \r in {1,...,5}
  \draw[ thick] (0,0) circle (\r);    
  \foreach \r in {2, 4,...,10}
  \draw (45:0.5*\r+0.05) node[inner sep=1pt,above right,rectangle,fill=white] {$\r{0}\%$}
  (-135:0.5*\r+0.05) node[inner sep=1pt,below left,rectangle,fill=white] {$\r{0}\%$};

    \foreach \a in {0, 90,...,360}
  \draw[thick,my ticks] (0, 0) -- (\a:5);

    \node[rotate=90](R0) at (5.5,0){RO};
    \node[rotate=90] (AE) at (-5.5,0){AE};
    \node(CE) at (0,5.5){CE};
    \node(AC) at (0,-5.5){AC};
    \end{tikzpicture}
\end{document}

enter image description here

答案2

这仍然可以简化，但似乎有效。大多数代码用于绘制抽动，我认为可以在第二次尝试中简化。

\documentclass[tikz,12pt]{standalone}
\begin{document}

 \begin{tikzpicture}     
 \foreach \r [count=\rcount, evaluate=\r as\p using int(2*\r)] in {1,...,5} {
   \draw [thick] circle (\r) (45:\r+.5) node{$\p{0}\%$} (225:\r+.5) node{$\p{0}\%$};

   \foreach \t [count=\tcount, evaluate=\t as\b using int(16-\tcount+4*\rcount)] in {.2,.5,.8} 
     \draw (\r-\t,0) -- (\r-\t,-2mm) node[below,font=\tiny]{\b};

   \foreach \t [count=\tcount, evaluate=\t as\b using int(18-\tcount+4*\rcount)] in {.2,.5,.8} 
     \draw (\t-\r,0) -- (\t-\r,2mm) node[above,font=\tiny]{\b};

   \foreach \t [count=\tcount, evaluate=\t as\b using int(15-\tcount+4*\rcount)] in {.2,.5,.8} 
     \draw (0,\r-\t) -- (2mm,\r-\t) node[right,font=\tiny]{\b};

   \foreach \t [count=\tcount, evaluate=\t as\b using int(20-\tcount+4*\rcount)] in {.2,.5,.8} 
     \draw (0,\t-\r) -- (-2mm,\t-\r) node[left,font=\tiny]{\b};   
 }    
 \draw[thick] (180:5)node[left]{AE} -- (0:5)node[right]{RO} (90:5)node[above]{CE} -- (-90:5)node[below]{AC};    
\end{tikzpicture}

\end{document}

enter image description here

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