我正在写论文，我想知道如何枚举优化问题的每一行。我已经写好了。谢谢。
\documentclass[11pt,a4paper,fleqn]{epm-bs}
\usepackage{indentfirst}
\usepackage{chicago}
%\usepackage{kmath,kerkis}
\usepackage[greek,english]{babel}
\usepackage[iso-8859-7]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{graphicx}
\usepackage{epsfig}
\usepackage{url}
\usepackage{amssymb,amsfonts,amsmath}
\usepackage{float}
\usepackage{algorithm,algpseudocode}
\usepackage{pgfplots}
\usepackage{optidef}
\usepackage{nccmath}
\overfullrule=0pt
\usepackage[ruled, algo2e]{algorithm2e}
\addto\captionsgreek{
\def\bibname{\greektext{ΑΝΑΦΟΡΕΣ}}
}\begin{document}
\begin{aligned}
&\min\quad \mathlarger\sum\limits_{k \in K}\sum\limits_{ij \in A}c^k_{ij}q^kx^k_{ij}\\
&\textlatin{s.t.}\quad \mathlarger\sum\limits_{k \in K}q^kx^k_{ij}\leq d_{ij}\forall ij \in A \\
&\quad \mathlarger\sum\limits_{ij \in A}x^k_{ij} - \sum\limits_{ji \in A}x^k_{ji} = b^k_i\forall i \in N, \forall k \in K \\
&\quad x_{ij} \in \{0,1\} \forall ij \in A,\forall k \in K
\end{aligned}
\end{document}
epm-bs.cls
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Πρότυπα ΕΠΜ για Πτυχιακή Εργασία
% Εισαγωγικές Σελίδες
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
\NeedsTeXFormat{LaTeX2e}
\LoadClass[a4paper,11pt,oneside,draft,openright]{book}
\ProvidesClass{epm-bs}
[2004/07/16 Ekdoseis PaMak]
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\addtolength{\textheight}{2.5cm}
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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\degreesubject{Ph.D., Electrical Engineering}
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\def\testers#1{\gdef\@testers{#1}}
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%
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% commented out since causing errors (10/9/04)
% \if@botnum
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% \fi
%
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\null\vfil%
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{\Large \bf \MakeUppercase{\@title}}
% \par\vskip 60pt plus2pt minus30pt
\par\vskip 12pt
% {\bf απο}
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{\bf \MakeUppercase{\@author}}
%\par\vskip 80pt plus6pt minus35pt
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{\it Επιβλέπων Καθηγητής} \@supervisor
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\par\hspace{98pt}{\it Εξεταστές} \@testers
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Εντολές που ορίζουν τη σελίδα copywrite
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
\newcommand\makecopyright{%
\thispagestyle{plain}
\begin{center}%
\vspace{+6.5in}
%\copyright \thisyear, \hskip 0.5em \@author
\textlatin{Copyright} \copyright \hskip 0.5em \@author, έτος \thisyear
\par Με επιφύλαξη παντός δικαιώματος. \textlatin {All rights reserved}.
\par\vskip 36pt
Η έγκριση της πτυχιακής εργασίας από το Τμήμα Εφαρμοσμένης Πληροφορικής του
Πανεπιστημίου Μακεδονίας δεν υποδηλώνει απαραιτήτως και αποδοχή των απόψεων
του συγγραφέα εκ μέρους του Τμήματος.
\end{center}%
\vfil\vfil\null%
%\clearpage%
\let\makecopyright\relax}
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Εντολές που ορίζουν την περίληψη (abstract)
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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\clearpage%
{\vfill}
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Ορισμός της διαστημάτωσης (line-spacing) σε 1.5 διάστημα
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%page 241, 8.6.2 from The Latex Companion
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%% redefine table numbering using bold (\textbf} and the section number (\thesection)
%% also changed the Pin'akas from file greek.ldf into bold
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\renewcommand{\thefigure}{\textbf{\thesection.\arabic{figure}}}
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{%
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Define front/main matter
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Ορισμός του \thisyear.
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Ορισμός \thegrmonth - μήνες στα ελληνικά για αυτόματη ημερομηνία
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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\textgreek{Ianou'arios}\or \textgreek{Febrou'arios}\or \testgreek{M'artios}\or \textgreek{Apr'ilios}\or \textgreek{M'a"ios}\or \textgreek{Io'unios}\or
\textgreek{Io'ulios}\or \textgreek{A'ugoustos}\or \textgreek{Sept'embrios}\or \textgreek{Okt'wbrios}\or \textgreek{No'embrios}\or \textgreek{Dek'embrios}\fi}
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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\@mkboth{%
\sffamily\MakeUppercase\contentsname}{\MakeUppercase\contentsname}}%
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\@starttoc{toc}%
\if@restonecol\twocolumn\fi
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Ορισμός του chapter
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Εντολές που ξανά-ορίζουν το table
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
%% the only change in way showing the Table legend
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#1: #2\par
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Εντολές που ξανά-ορίζουν το environment της βιβλιογραφίας
%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
% Λύση στο πρόβλημα του σ που γίνεται αυτόματα τελικό ς όταν ακολουθείται από τελεία
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%::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
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\endinput
答案1
以下是我排版您的表情的方式：
\documentclass[11pt,a4paper]{article}
\usepackage[greek,english]{babel}
\usepackage{amssymb,amsfonts,amsmath}
\usepackage{relsize,mathtools}
\begin{document}
\begin{align}
&\mathrlap{\min \mathlarger\sum\limits_{k \in K}\sum\limits_{ij \in A}c^k_{ij}q^kx^k_{ij}}\\
&\textlatin{s.t.} & \mathlarger\sum\limits_{k \in K}q^kx^k_{ij} &\leq d_{ij} &\forall& ij \in A \\
& & \mathlarger\sum\limits_{ij \in A}x^k_{ij} - \sum\limits_{ji \in A}x^k_{ji} &= b^k_i &\forall& i \in N, \forall k \in K \\
& & x_{ij} &\in \{0,1\} &\forall& ij \in A,\forall k \in K
\end{align}
\end{document}
