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元素长度不均匀且增加了行/列的矩阵

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元素长度不均匀且增加了行/列的矩阵

从答案到这个问题

使用以下代码

\documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\usetikzlibrary{arrows, calc, fit, matrix}
\begin{document}
\tikzset{matrix rows/.initial=5,matrix cols/.initial=6,matrix name/.initial=x,
vline/.style={/utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix rows}}
{\ifnum\XX=1
\xdef\MatLstA{(\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
\xdef\MatLstB{(\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
\else
\xdef\MatLstA{\MatLstA (\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
\xdef\MatLstB{\MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
\fi},
insert path={node[fit=\MatLstA,inner sep=0pt] (fitA) {}
node[fit=\MatLstB,inner sep=0pt] (fitB) {}
($(fitA.east)!0.5!(fitB.west)$) coordinate (aux) 
(\pgfkeysvalueof{/tikz/matrix name}.north-|aux) -- (\pgfkeysvalueof{/tikz/matrix name}.south-|aux)}},%end vline
hline/.style={/utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix cols}}
{\ifnum\XX=1
\xdef\MatLstA{(\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
\xdef\MatLstB{(\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
\else
\xdef\MatLstA{\MatLstA (\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
\xdef\MatLstB{\MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
\fi},insert path={node[fit=\MatLstA,inner sep=0pt] (fitA) {}
node[fit=\MatLstB,inner sep=0pt] (fitB) {}
($(fitA.south)!0.5!(fitB.north)$) coordinate (aux) 
(\pgfkeysvalueof{/tikz/matrix name}.west|-aux) -- (\pgfkeysvalueof{/tikz/matrix name}.east|-aux)}},%end hline
full matrix grid/.style={vline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1},
hline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix rows}-1},
insert path={(\pgfkeysvalueof{/tikz/matrix name}.south west) rectangle (\pgfkeysvalueof{/tikz/matrix name}.north east)}}
}
\begin{frame}[t,fragile]
\frametitle{}
\begin{tikzpicture}
\matrix (x) [matrix of nodes, row sep=10pt, column sep=10pt] {%
15.1 & 23.7 & 19.7 & 15.4 & 18.3 & 23.0 & y\\
17.4 & 18.6 & 12.9 & 20.320.320.3 & 13.7 & 21.45 & y\\
10.3 & 26.1 & 15.718.918.9 & 14.0 & 17.8 & 33.8 & y\\
23.2 & 12.9 & 29.8 & 18.3 & 14.2 & 20.8 & y\\
xx & xx & xx & xx & xx & xx & y\\
13.5 & 17.1 & 20.7 & 27.1 & 18.918.9 & 16.6 & y\\};
\draw<2->[ultra thick, blue, latex'-] (x-2-1) node [fill, red!40!white, circle, inner sep=8pt, opacity=.4]{} -- (x-4-5) node [fill, blue!40!white, circle, inner sep=8pt, opacity=.4]{};
% Node names: (<name of matrix>-<row>-<column>)
% \draw[vline/.list={1,...,5},hline/.list={1,...,4}] (\pgfkeysvalueof{/tikz/matrix name}.north west) rectangle 
%  (\pgfkeysvalueof{/tikz/matrix name}.south east); % 
\draw[matrix name=x,matrix cols=6,matrix rows=5,full matrix grid];% drawing the borders
\end{tikzpicture}
\end{frame}
\end{document}

添加新行/列时，新行/列与旧行/列之间没有线。如何修复此问题？

我尝试重新调整

matrix rows/.initial=5,matrix cols/.initial=6

到

matrix rows/.initial=0,matrix cols/.initial=0

或者

matrix rows/.initial=10,matrix cols/.initial=10

但它没有作用。

从我得到的答案来看，问题不在于这条线路；问题在于我没有重新调整线路

\draw[matrix name=x,matrix cols=6,matrix rows=5,full matrix grid];

到

\draw[matrix name=x,matrix cols=7,matrix rows=6,full matrix grid];

在此处输入图片描述 在此处输入图片描述

答案1

您需要更改此行：

\draw[matrix name=x,matrix cols=6,matrix rows=5,full matrix grid];

到

\draw[matrix name=x,matrix cols=7,matrix rows=6,full matrix grid];

这一行代码的作用是绘制一个具有指定行数和列数的网格。在本例中，代码如下：

在此处输入图片描述

完整代码如下：

documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\usetikzlibrary{arrows, calc, fit, matrix}
\begin{document}
\tikzset{matrix rows/.initial=5,matrix cols/.initial=6,matrix name/.initial=x,
vline/.style={/utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix rows}}
{\ifnum\XX=1
\xdef\MatLstA{(\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
\xdef\MatLstB{(\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
\else
\xdef\MatLstA{\MatLstA (\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
\xdef\MatLstB{\MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
\fi},
insert path={node[fit=\MatLstA,inner sep=0pt] (fitA) {}
node[fit=\MatLstB,inner sep=0pt] (fitB) {}
($(fitA.east)!0.5!(fitB.west)$) coordinate (aux)
(\pgfkeysvalueof{/tikz/matrix name}.north-|aux) -- (\pgfkeysvalueof{/tikz/matrix name}.south-|aux)}},%end vline
hline/.style={/utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix cols}}
{\ifnum\XX=1
\xdef\MatLstA{(\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
\xdef\MatLstB{(\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
\else
\xdef\MatLstA{\MatLstA (\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
\xdef\MatLstB{\MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
\fi},insert path={node[fit=\MatLstA,inner sep=0pt] (fitA) {}
node[fit=\MatLstB,inner sep=0pt] (fitB) {}
($(fitA.south)!0.5!(fitB.north)$) coordinate (aux)
(\pgfkeysvalueof{/tikz/matrix name}.west|-aux) -- (\pgfkeysvalueof{/tikz/matrix name}.east|-aux)}},%end hline
full matrix grid/.style={vline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1},
hline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix rows}-1},
insert path={(\pgfkeysvalueof{/tikz/matrix name}.south west) rectangle (\pgfkeysvalueof{/tikz/matrix name}.north east)}}
}
\begin{frame}[t,fragile]
\frametitle{}
\begin{tikzpicture}
\matrix (x) [matrix of nodes, row sep=10pt, column sep=10pt] {%
15.1 & 23.7 & 19.7 & 15.4 & 18.3 & 23.0 & y\\
17.4 & 18.6 & 12.9 & 20.320.320.3 & 13.7 & 21.45 & y\\
10.3 & 26.1 & 15.718.918.9 & 14.0 & 17.8 & 33.8 & y\\
23.2 & 12.9 & 29.8 & 18.3 & 14.2 & 20.8 & y\\
xx & xx & xx & xx & xx & xx & y\\
13.5 & 17.1 & 20.7 & 27.1 & 18.918.9 & 16.6 & y\\};
\draw<2->[ultra thick, blue, latex'-] (x-2-1) node [fill, red!40!white, circle, inner sep=8pt, opacity=.4]{} -- (x-4-5) node [fill, blue!40!white, circle, inner sep=8pt, opacity=.4]{};
% Node names: (<name of matrix>-<row>-<column>)
% \draw[vline/.list={1,...,5},hline/.list={1,...,4}] (\pgfkeysvalueof{/tikz/matrix name}.north west) rectangle
%  (\pgfkeysvalueof{/tikz/matrix name}.south east); %
\draw[matrix name=x,matrix cols=7,matrix rows=6,full matrix grid];% drawing the borders
\end{tikzpicture}
\end{frame}
\end{document}

答案2

Andrew 指出了正确的事情。现在让我深入研究一下。这是\tikzset, 对齐（我最喜欢的方式）

\tikzset{
    matrix rows/.initial=5,
    matrix cols/.initial=6,
    matrix name/.initial=x,
    vline/.style={
        /utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix rows}} {
            \ifnum\XX=1
                \xdef\MatLstA{
                    (\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
                \xdef\MatLstB{
                    (\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
            \else
                \xdef\MatLstA{
                    \MatLstA (\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
                \xdef\MatLstB{
                    \MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
            \fi},
        insert path={
            node[fit=\MatLstA,inner sep=0pt] (fitA) {}
            node[fit=\MatLstB,inner sep=0pt] (fitB) {} ($(fitA.east)!0.5!(fitB.west)$) coordinate (aux) 
            (\pgfkeysvalueof{/tikz/matrix name}.north-|aux) -- (\pgfkeysvalueof{/tikz/matrix name}.south-|aux)}
    },%end vline
    hline/.style={
        /utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix cols}} {
            \ifnum\XX=1
                \xdef\MatLstA{
                    (\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
                \xdef\MatLstB{
                    (\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
            \else
                \xdef\MatLstA{
                    \MatLstA (\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
                \xdef\MatLstB{
                    \MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
            \fi},
        insert path={
            node[fit=\MatLstA,inner sep=0pt] (fitA) {}
            node[fit=\MatLstB,inner sep=0pt] (fitB) {} ($(fitA.south)!0.5!(fitB.north)$) coordinate (aux) 
            (\pgfkeysvalueof{/tikz/matrix name}.west|-aux) -- (\pgfkeysvalueof{/tikz/matrix name}.east|-aux)}
    },%end hline
    full matrix grid/.style={
        vline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1},
        hline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix rows}-1},
        insert path={(\pgfkeysvalueof{/tikz/matrix name}.south west) rectangle (\pgfkeysvalueof{/tikz/matrix name}.north east)}
    }
}

在没有任何事先知识的情况下，我想我们仍然可以理解vline样式会在给定的列表中添加垂直线，以及hline水平线。

现在，看看full matrix grid：

full matrix grid/.style={
    vline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1},
    hline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix rows}-1},
    insert path={(\pgfkeysvalueof{/tikz/matrix name}.south west) rectangle (\pgfkeysvalueof{/tikz/matrix name}.north east)}
}

它输出给定列表中的一组hlines 和vlines。列表由matrix cols和matrix rows（\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1等）控制，因此您必须更改这些选项的值才能更改网格。

matrix rows和的初始值为matrix cols和5，6但这并不重要，因为你已经在命令中再次重置了它

\draw[matrix name=x,matrix cols=6,matrix rows=5,full matrix grid];

现在，改变上面命令中的matrix cols和的值，您将得到您想要的结果。matrix rows

为了完整起见，请参阅 Andrew 的回答中的可编译代码。

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