在同一张 tikzpicture 中绘制 4 个相同的图形

Question

我想画这个：

我已经成功使用以下代码制作了一个六边形：

\documentclass{article}
\usepackage{tikz}
\begin{document}
\begin{figure}
\begin{tikzpicture}[scale=2,cap=round,>=latex]

  \newdimen\R
  \R=0.8cm
\coordinate (center) at (0,0);
\draw (0:\R)
 \foreach \x in {60,120,...,360} {  -- (\x:\R) }
          -- cycle (300:\R) node[below] {}
          -- cycle (240:\R) node[below] {}
          -- cycle (180:\R) node[left] {}
          -- cycle (120:\R) node[above] {}
          -- cycle (60:\R) node[above] {}
          -- cycle (0:\R) node[right] {};
\draw { (60:\R) -- (30:0.69) -- (center) -- (60:\R) } [fill=gray];
\draw { (90:0.69) -- (120:\R) -- (center) -- (90:0.69) } [fill=gray];
\draw { (180:\R) -- (150:0.69) -- (center) -- (180:\R) } [fill=gray];
\draw { (240:\R) -- (210:0.69) -- (center) -- (240:\R) } [fill=gray];
\draw { (300:\R) -- (270:0.69) -- (center) -- (300:\R) } [fill=gray];
\draw { (0:\R) -- (330:0.69) -- (center) -- (0:\R) } [fill=gray];

\end{tikzpicture}
\end{figure}

\end{document}

它画出了这个：

但当我尝试做 4 个时，对我来说真的很复杂，请帮忙。谢谢

Answer 1

通常建议使用pics，但在这里您可以使用稍微扩展的标准节点。

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{shapes.geometric,calc}
\tikzset{repeating shape/.style={regular polygon,regular polygon sides=#1,alias=curr,draw,append after command={
    [draw,] foreach \XX [remember=\XX as \YY (initially #1)] 
    in {1,...,#1} {
    (curr.corner \XX) -- (curr.center) -- ($(curr.corner \YY)!0.5!(curr.corner
    \XX)$)}}}}

\begin{document}
\begin{figure}
\begin{tikzpicture}[scale=2]
  \draw[fill=gray] foreach \X in {0,2.2} { foreach \Y in {0,2.2}
  {(\X,\Y) node[repeating shape=6,minimum size=3cm]{} }};
\end{tikzpicture}
\end{figure}
\end{document}

Answer 2

没有人会阻止您pic，并且拥有尽可能多的选择。

\documentclass[tikz]{standalone}
\usetikzlibrary{shapes.geometric}
\newdimen\R
\R=0.8cm
\tikzset{
  pics/hexagon/.style args={#1 and #2}{
    code={
      \node[regular polygon,regular polygon sides=6,minimum size=2*\R] (x) {};
      \coordinate (x.corner 0) at (x.corner 6);
      \foreach \i in {0,...,5} {
        \fill[#1] (x.center) -- (x.{\i*60}) -- (x.{\i*60+30});
        \fill[#2] (x.center) -- (x.{\i*60-30}) -- (x.{\i*60});
      }
    }
  }
}
\begin{document}
\begin{tikzpicture}
\pic at (-1,-1) {hexagon=gray and black};
\pic at (-1, 1) {hexagon=gray and black};
\pic at ( 1,-1) {hexagon=gray and black};
\pic at ( 1, 1) {hexagon=gray and black};
\end{tikzpicture}
\end{document}

Answer 3

这是一个简单的方法！

\documentclass[tikz,border=5mm]{standalone}
\begin{document}
\begin{tikzpicture}
\def\a{2}
\def\subpic{
\fill[gray] (0:\a)--(60:\a)--(120:\a)
--(180:\a)--(240:\a)--(300:\a)--cycle;
\foreach \i in {0,1,...,5} 
\fill[rotate=60*\i] (0,0)--(120:\a)-|cycle;
}

\foreach \j in {45,135,-135,-45}{
\begin{scope}[shift={(\j:4)}]
\subpic 
\end{scope}
}
\end{tikzpicture}
\end{document}