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绘制垂直线、填充区域

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绘制垂直线、填充区域

我对垂直线仍然有些困惑。这是我想复制的图形

在此处输入图片描述

这是我的 MWE

\documentclass[12pt,a4paper]{article}

\usepackage{tikz}
\usetikzlibrary{calc}


\begin{document}


\begin{tikzpicture}[dot/.style={circle,inner sep=1pt,fill,label={#1},name=#1},
  extended line/.style={shorten >=-#1,shorten <=-#1},
  extended line/.default=1cm]

\draw[extended line,thick,->] (-3.5,0) -- (4.5,0) node[anchor=north west] {\small spot 0};
\draw[extended line,thick,->] (0,-3.5) -- (0,4.5) node[anchor=south east] {\small spot 1};

\coordinate (A) at (0,4);
\coordinate (B) at (4,0);

\draw (A) -- (B) 
node[pos=0.7,above=0.5em, font=\small]{$\Delta$};     

\coordinate (C) at (0,0);
\coordinate (D) at (1.5,1.8);
\draw [thick, ->](C) -- (D) 
node[pos=0.7,above=0.5em, font=\small]{$\Phi$};   

\draw [dashed] (D)--(B) node[anchor= south west, font=\small]{$\delta^{0}$};   

\draw (-3.5,-2)--(0,0)--(3.5,-2.5);

\fill[blue!10,fill opacity=0.3] (5,4.5) rectangle (0,0); 

\end{tikzpicture}

\end{document}

我尝试在“圆锥”上添加一个坐标并使用语法calc绘制一条垂直线，但它不起作用。我应该用它arc来填充圆锥吗？谢谢您的时间。

答案1

像这样吗？

\documentclass[12pt,a4paper]{article}

\usepackage{tikz}
\usetikzlibrary{calc,shadings}


\begin{document}


\begin{tikzpicture}[dot/.style={circle,inner sep=1pt,fill,label={#1},name=#1},
  extended line/.style={shorten >=-#1,shorten <=-#1},
  extended line/.default=1cm]

\draw[extended line,thick,->] (-3.5,0) -- (4.5,0) node[anchor=north west] {\small spot 0};
\draw[extended line,thick,->] (0,-3.5) -- (0,4.5) node[anchor=south east] {\small spot 1};

\shade[upper right=gray!20,lower left=gray,fill opacity=0.3] (5,4.5) rectangle (0,0); 


\coordinate (A) at (0,4);
\coordinate (B) at (4,0);

\draw (A) -- (B) 
node[pos=0.7,above=0.5em, font=\small]{$\Delta$};     

\coordinate (C) at (0,0);
\coordinate (D) at (1.3,1.8);
\draw [thick, ->](C) -- (D) 
node[pos=0.7,above=0.5em, font=\small]{$\Phi$};   


\draw let \p1=($(D)-(C)$), \n1={atan2(\y1,\x1)-90}, \n2={\n1-120} in
[upper right=gray,lower left=gray!20,fill opacity=0.3,shading angle=\n1+60]
(\n1:4) coordinate (aux) -- (C) -- (\n2:4) arc(\n2:\n1:4);
\draw [dashed] (D)--(B) node[anchor= south west, font=\small]{$\delta^{0}$}
-- (intersection cs:first line={(B)--($(B)!3cm!90:(D)$)},
second line={(C)--(aux)});   
\end{tikzpicture}
\end{document}

在此处输入图片描述

答案2

对所需图像的另一种近似（在一定程度上类似于@marmot 的回答）：

\documentclass[12pt, tikz, margin=3mm]{standalone}
\usetikzlibrary{arrows.meta,
                calc,
                backgrounds,
                intersections,
                shadings}

\begin{document}
    \begin{tikzpicture}[
               > = Straight Barb,
      dot/.style = {circle,inner sep=1pt,fill,label={#1},name=#1},
every pin/.style = {pin edge={<-,line width=0.5pt,black},},
            font = \small
                        ]

\draw[->] (-4,0.0) -- (6,0) node[below left] {spot 0};
\draw[->] (0,-3.5) -- (0,5) node[below left] {spot 1};

\coordinate (A) at (0,4);
\coordinate (B) at (4,0);

\draw       (A) -- node[coordinate,pin=45:$\Delta$] {} (B) ;

\coordinate (C) at (0,0);
\coordinate (D) at (1.5,1.8);
\draw[->](C) -- (D) node[left]  {$\Phi$};

\draw[dashed] (D)--(B) node[above right]{$\delta^{0}$};
\draw[name path=A]   (210:3.3) -- (0,0) -- (330:3.3);
    \begin{scope}[on background layer]
\fill[top color=blue!30,bottom color=blue!5]
        (0,0) -- (210:3.3) arc (210:330:3.3) -- (0,0);
\fill[lower left=blue!30, upper right=blue!5]
        (4.5,4.5) rectangle (0,0);
    \end{scope}
\path[name path=B]   (B) -- ($(B)!22mm!90:(A)$);
\draw[name intersections={of=A and B,by=x},
      dashed]       (x) node[below] {$x^0$} -- (B);
    \end{tikzpicture}
\end{document}

在此处输入图片描述

离题：使用extended line如你的姆韦可能会使线溢出边界框，从而导致意外问题。而且节点的位置也不在绘制的线的末端，而是在给定的末端坐标。因此我没有使用这种线条样式。

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