我的表格中有 8 列，除了最后一个值外，其余都完美匹配，最后一个值大约有 5 列长/宽（这是一个非常长的二进制字符串），并且单独位于最后一行，我希望它像第一列中的所有其他值一样对齐并逐渐变小，但 tabular 会将第二列一直推到这个长字符串的末尾。这可以理解，它只是在执行编程要做的事情，但我可以让 tabular 忽略最后一个值的长度，以便它可以自由地穿过所有列而不会破坏它们吗？
\documentclass[10pt]{article}
\usepackage{verbatim}
\begin{document}
\begin{table}[]
\begin{tabular}{l|llllllll}
\hline %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\emph{utf-8} & \verb s & \verb & \verb | & \verb = & \verb ~ & \verb w & \verb & \verb Ù \\
\hline %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\emph{hexadec} & \verb 73 & \verb 89 & \verb 7C & \verb 3D & \verb 7E & \verb 77 & \verb 87 & \verb D9 \\
\emph{decimal} & \verb 115 & \verb 137 & \verb 124 & \verb 061 & \verb 126 & \verb 119 & \verb 135 & \verb 217 \\
\emph{binary} & \verb 01110011 & \verb 10001001 & \verb 01111100 & \verb 00111101 & \verb 01111110 & \verb 01110111 & \verb 10000111 & \verb 11011001 \\
& \verb 0111001110001001011111000011110101111110011101111000011111011001 & \\
\end{tabular}
\end{table}
\end{document}
答案1
您似乎正在寻找\multicolumn但也不应该\verb在这里使用。
\documentclass[10pt]{article}
%\usepackage{verbatim}
\usepackage{array}
\begin{document}
\begin{table}% latex warns about an empty argument []
% use \ttfamily not space-delimited \verb
\hspace*{-61pt}\begin{tabular}{@{}l|*{8}{>{\ttfamily}l}@{}}
\hline
\emph{utf-8} & s & & | & = & \verb|~| & w & & Ù \\
\hline
\emph{hexadec} & 73 & 89 & 7C & 3D & 7E & 77 & 87 & D9 \\
\emph{decimal} & 115 & 137 & 124 & 061 & 126 & 119 & 135 & 217 \\
\emph{binary} & 01110011 & 10001001 & 01111100 & 00111101 & 01111110 & 01110111 & 10000111 & 11011001 \\
& \multicolumn{8}{l}{0111001110001001011111000011110101111110011101111000011111011001} \\
\end{tabular}\hspace*{-61pt}
\end{table}
\end{document}