我尝试用灰色（\definecolor{grey}{RGB}{220,250,250}）为第一个矩阵中的空单元格着色，但我不知道为什么它不起作用。有什么建议吗？
\documentclass{standalone}
%\usepackage[showframe]{geometry}
\usepackage{tikz}
\definecolor{gris}{RGB}{250,250,250}
\usepackage{lmodern}
\usetikzlibrary{matrix,
positioning}
\tikzset{
mymatrix/.style = {matrix of nodes,
nodes in empty cells,
nodes={minimum height=3ex, minimum width=1em,
inner sep=0pt, outer sep=0pt, anchor=center,
draw, very thin,scale=0.8,transform shape},
column sep=0pt,
row sep=0pt,
inner sep=0.5\pgflinewidth, outer sep=1pt,
draw, thick},
empty node/.style = {draw,fill=grey},
every label/.append style = {font=\large, text=teal}
}
\makeatletter
\def\tikz@lib@matrix@empty@cell{%
\iftikz@lib@matrix@empty%
\node[name=\tikzmatrixname-\the\pgfmatrixcurrentrow-\the\pgfmatrixcurrentcolumn,empty node]{};\fi}
\makeatother
\usepackage{bm}
\newcommand{\MatrixVariable}[1]{\bm{{#1}}}
\definecolor{blue}{RGB}{180, 171, 250}
\definecolor{grey}{RGB}{250,250,250}
\begin{document}
\begin{tikzpicture}[node distance=0pt,scale=0.6,nodes={transform
shape}]
\matrix (m1) [mymatrix,
label={[rotate=90, anchor=south,black]left: Movies},
label={[black]below:$\MatrixVariable{{R}}$},
label={[black]above:Users},
nodes={fill=blue}]
{
1 & & 3 & & & 5 & & & 5 & & 4 & \\
& & 5 & 4 & & & 4 & & & 2 & 1 & 3 \\
2 & 4 & & 1 & 2 & & 3 & & 4 & 3 & 5 & \\
& 2 & 4 & & 5 & & & 4 & & & 2 & \\
& & 4 & 3 & 4 & 2 & & & & & 2 & 5 \\
1 & & 3 & & 3 & & & 2 & & & 4 & \\
};
\node (approx) [right=of m1,scale=2] {$\approx$};
\matrix (m2) [mymatrix=none, right=0.1em of approx,
label={[rotate=90, anchor=south east,xshift=-0.7em,black]left: Movies},
label={[black]below:$\MatrixVariable{{Q}}$},
label={[black]above:$f$-factors},
nodes={minimum width=2.2em,fill=grey}]
{
0.1& -0.4 & -0.2 \\
-0.5& 0.6 & 0.5 \\
-0.2& 0.3 &0.5 \\
1.1& 2.1 & 0.3 \\
-0.7&2.1 & -2 \\
-1& 0.7 & 0.3 \\
};
\node (times) [right=of m2,scale=2] {$\cdot$};
\matrix (m3) [mymatrix=none, right=of times,
label={[rotate=90, anchor=north,black]right: $f$-factors},
label={[black]below:$\MatrixVariable{{P}^{T}}$},
label={[black]above:Users},
nodes={minimum width=2em,fill=grey}]
{
1.1&-2 & 0.3 & 0.5 &-2 & -0.5 & 0.8 & -0.4 & 0.3 & 1.4 & 2.4 & -0.9\\
-0.8& 0.7 & 0.5 & 1.4 &0.3 & -1 & 1.4 & 2.9 & 0.7 & - 1.2 & 1.3& 0.4\\
2.1& -0.4 & 0.6 & 1.7 & 2.4 & 0.9 & -0.3 & 0.4 & 0.8 & 0.7 & -0.6&0.1 \\
};
\end{tikzpicture}
\end{document}
答案1
grey您只需在空节点gray中替换即可。tikzset
\documentclass{standalone}
%\usepackage[showframe]{geometry}
\usepackage{tikz}
\usepackage{lmodern}
\usetikzlibrary{matrix,
positioning}
\tikzset{
mymatrix/.style = {matrix of nodes,
nodes in empty cells,
nodes={minimum height=3ex, minimum width=1em,
inner sep=0pt, outer sep=0pt, anchor=center,
draw, very thin,scale=0.8,transform shape},
column sep=0pt,
row sep=0pt,
inner sep=0.5\pgflinewidth, outer sep=1pt,
draw, thick},
empty node/.style = {draw,fill=gray},
every label/.append style = {font=\large, text=teal}
}
\makeatletter
\def\tikz@lib@matrix@empty@cell{%
\iftikz@lib@matrix@empty%
\node[name=\tikzmatrixname-\the\pgfmatrixcurrentrow-\the\pgfmatrixcurrentcolumn,empty node]{};\fi}
\makeatother
\usepackage{bm}
\newcommand{\MatrixVariable}[1]{\bm{{#1}}}
\definecolor{blue}{RGB}{180, 171, 250}
\begin{document}
\begin{tikzpicture}[node distance=0pt,scale=0.6,nodes={transform
shape}]
\matrix (m1) [mymatrix,
label={[rotate=90, anchor=south,black]left: Movies},
label={[black]below:$\MatrixVariable{{R}}$},
label={[black]above:Users},
nodes={fill=blue}]
{
1 & & 3 & & & 5 & & & 5 & & 4 & \\
& & 5 & 4 & & & 4 & & & 2 & 1 & 3 \\
2 & 4 & & 1 & 2 & & 3 & & 4 & 3 & 5 & \\
& 2 & 4 & & 5 & & & 4 & & & 2 & \\
& & 4 & 3 & 4 & 2 & & & & & 2 & 5 \\
1 & & 3 & & 3 & & & 2 & & & 4 & \\
};
\node (approx) [right=of m1,scale=2] {$\approx$};
\end{tikzpicture}
\end{document}
要得到：
笔记：三倍的
RGB={250,250,250}结果将是白色。