我在 ConTeXt 中有一张这样的表格:
\starttext
\chapter{This is a title}
\bTABLE
\bTABLEhead
\bTR \bTD a \eTD \bTD b \eTD \bTD c \eTD \eTR
\eTABLEhead
\bTABLEbody
\dorecurse{100}{%
\bTR \bTD 1 \eTD \bTD 2 \eTD \bTD 3 \eTD \eTR
}
\eTABLEbody
\eTABLE
\stoptext
我如何设置递归以仅重复单元格直至填充页面的剩余部分?
答案1
一种可能的算法是循环排版表格,添加行直到超过页面上可用的剩余高度。请注意,这种方法非常慢。
\startbuffer[table]
\bTABLE
\bTABLEhead
\bTR \bTD a \eTD \bTD b \eTD \bTD c \eTD \eTR
\eTABLEhead
\bTABLEbody
\dorecurse{\the\scratchcounter}{%
\bTR \bTD 1 \eTD \bTD 2 \eTD \bTD 3 \eTD \eTR
}
\eTABLEbody
\eTABLE
\stopbuffer
\showframe
\starttext
\chapter{This is a title}
\scratchcounter=1
\scratchdimen=0pt
\loop\ifdim\scratchdimen<\dimexpr\pagegoal-\pagetotal-2\lineheight\relax % why 2\lineheight?
\setbox\scratchbox=\vbox{\getbuffer[table]}
\scratchdimen=\dimexpr\ht\scratchbox+\dp\scratchbox\relax
\advance\scratchcounter by 1
\repeat
\advance\scratchcounter by -1
\vbox{\getbuffer[table]}
\stoptext
答案2
这与 Henri Menke 的解决方案的想法相同,但我不是逐行添加行,而是先测量行的高度,然后使用内置命令\getrawnoflines
获取剩余空间中可容纳的行数。
\define\calculatelines
{\setbox\scratchbox\hbox{\bTABLE
\bTR \bTD 1 \eTD \bTD 2 \eTD \bTD 3 \eTD \eTR
\eTABLE}%
\openlineheight=\htdp\scratchbox
\ifdim\pagegoal=\maxdimen % we are at the beginning of the page
\scratchdimen=\dimexpr\textheight - 2\openlineheight\relax
\else
\scratchdimen=\dimexpr\pagegoal - \pagetotal - 2\openlineheight \relax
\fi
\getrawnoflines\scratchdimen}
\define\fillTABLE
{\blank
\bgroup
\calculatelines
\bTABLE
\bTABLEhead
\bTR \bTD a \eTD \bTD b \eTD \bTD c \eTD \eTR
\eTABLEhead
\bTABLEbody
\dorecurse{\the\noflines}
{\bTR \bTD 1 \eTD \bTD 2 \eTD \bTD 3 \eTD \eTR}
\eTABLEbody
\eTABLE
\egroup}
\setuppapersize[A5]
\showframe
\starttext
\fillTABLE
\page
\section{New section}
\fillTABLE
\page
\section{With some text}
\input knuth
\fillTABLE
\stoptext