我该如何写出以下反应并给它们贴上标签？

Question

我想写下以下反应并像方程模式一样标记它们。我该怎么做？

Answer 1

您只需将一些\chemfigs放入subequations和equation环境中即可：

\documentclass{article}

\usepackage{chemfig, amsmath}

\begin{document}

\setcounter{equation}{6}
\setchemfig{atom sep=2em, arrow coeff=.5}

\begin{subequations}

\begin{equation}
  \schemestart
    \chemfig{CO} \+ \chemfig{Pt} 
    \arrow(.mid east--.mid west) 
    \chemfig{Pt-[2]C~[2]O}
  \schemestop
  \quad \text{(linear-bonded)}
\end{equation}

\begin{equation}
  \schemestart
    \chemfig{CO} \+ \chemfig{Pt Pt} 
    \arrow(.mid east--.mid west) 
    \chemfig{Pt-[:72.5]C(-[:-72.5]Pt)=[2]O}
  \schemestop
  \quad \text{(bridge-bonded)}
\end{equation}

\end{subequations}

\begin{subequations}

\begin{equation}
  \schemestart
    \chemfig{CO CO} \+ \chemfig{Pt Pt(-[2,,1,]H)-[2,,2,]H} 
    \arrow(.mid east--.mid west) 
    \chemfig{Pt Pt(-[2,,1,]C~[2]O)-[2,,2,]C~[2]O} \+ \chemfig{H2}
  \schemestop
  \quad \text{(linear-bonded)}
\end{equation}

\begin{equation}
  \schemestart
    \chemfig{CO} \+ \chemfig{Pt Pt(-[2,,1,]H)-[2,,2,]H} 
    \arrow(.mid east--.mid west) 
    \chemfig{Pt-[:72.5]C(-[:-72.5]Pt)=[2]O} \+ \chemfig{H2}
  \schemestop
  \quad \text{(bridge-bonded)}
\end{equation}

\end{subequations}

\end{document}