我从以下简单代码中收到双下标错误:
Consider a sample drawn from the population consisting of the set $\{ e_{1}, e_{2},\cdots, e_{n} \} $. This sample can be selected in any order, i.e $e_{1},e_{2},..._e_{n}$ or $e_{4},e_{8},e_{n-1},...e_{n}$. This implies there are $n!$ different orders for the sample.
据我所知,我检查了两次,所有花括号都分配正确。我可能还做错了什么吗?
答案1
正如评论中提到的,_e_n{n}
应该只是e_{n}
。此外,...
应该是\cdots
(\dots
如果您希望基线处的点。)