答案1
很可能某个地方存在一些非常相似的答案,但我无法找到它。
\documentclass{article}
\usepackage{mathtools}
\usepackage{graphicx}
\usepackage{eqparbox}
\begin{document}
\begin{align*}
\eqmakebox[pft]{$\widetilde{h\circ\partial+\partial\circ h}$}&=
\widetilde{h\circ\partial}+\widetilde{\partial\circ h}=
\widetilde{h}\circ\widetilde{\partial}+\widetilde{\partial}\circ\widetilde{h}\\
\eqmakebox[pft][c]{\rotatebox[origin=c]{90}{$=$}}&\\
\widetilde{(\bar\ell_1)_{\#}+(\bar\ell_1)_{\#}}&=
\widetilde{(\bar\ell_1)_{\#}}+\widetilde{(\bar\ell_1)_{\#}}
=(\bar\ell_1)^{\#}+(\bar\ell_1)^{\#}
\end{align*}
\end{document}
或者用很宽的波浪线这个答案。
\documentclass{article}
\usepackage{mathtools}
\usepackage{scalerel}
\usepackage{stackengine,wasysym}
\newcommand\reallywidetilde[1]{\ThisStyle{%
\setbox0=\hbox{$\SavedStyle#1$}%
\stackengine{-.1\LMpt}{$\SavedStyle#1$}{%
\stretchto{\scaleto{\SavedStyle\mkern.2mu\AC}{.5150\wd0}}{.6\ht0}%
}{O}{c}{F}{T}{S}%
}}
\usepackage{eqparbox}
\begin{document}
\begin{align*}
\eqmakebox[pft]{$\reallywidetilde{h\circ\partial+\partial\circ h}$}&=
\reallywidetilde{h\circ\partial}+\reallywidetilde{\partial\circ h}=
\widetilde{h}\circ\widetilde{\partial}+\widetilde{\partial}\circ\widetilde{h}\\
\eqmakebox[pft][c]{\rotatebox[origin=c]{90}{$=$}}&\\
\reallywidetilde{(\bar\ell_1)_{\#}+(\bar\ell_1)_{\#}}&=
\reallywidetilde{(\bar\ell_1)_{\#}}+\reallywidetilde{(\bar\ell_1)_{\#}}
=(\bar\ell_1)^{\#}+(\bar\ell_1)^{\#}
\end{align*}
\end{document}
对于未来,我希望您展示您所尝试过的方法,以便其他人不必从屏幕截图中输入公式。
答案2
eqparbox
以下是使用和yhmath
(对于)的方法\widetilde
:
\documentclass{article}
\usepackage{mathtools}
\usepackage{yhmath}
\usepackage{eqparbox, graphicx}
\newcommand*{\eqmathbox}[2][M]{\eqmakebox[#1]{$\displaystyle#2$}}
\begin{document}
\begin{align*}
\eqmathbox{ \widetilde{h\circ \partial + \partial\circ h}} & = \widetilde{h\circ \partial} +\widetilde{ \partial\circ h} =\bar{\partial}\circ \widetilde{h}+ \widetilde{h}\circ\bar{\partial} \\[-1ex]
\eqmathbox{\rotatebox[origin=c]{90}{$ = $}} \\[-0.5ex]
\eqmathbox{\widetilde{(u_{1})_{\sharp}-(u_{0})_{\sharp}}} & = \widetilde{(u_{1})}_{\sharp}- \widetilde{(u_{0})}_{\sharp} = (i_{1})^{\sharp}- (i_{0})^{\sharp}
\end{align*}
\end{document}