定理主体中的直立括号带有 bodyfont=\mdseries\itshape?

定理主体中的直立括号带有 bodyfont=\mdseries\itshape?

bodyfont=\mdseries\itshape当在定理样式的定义中使用声明时,是否可以使定理主体中的方括号直立显示thmtools

使用该包的方法embrac从 newtxttext 复制 theoremfont 选项) 不起作用,因为正如embrac文档所说,它只影响\emph\textit和 ,textsl但不影响\itshape\slshape

尤其:有没有办法避免使用\itshape(或\slshape),但仍然在定理主体中获得斜体(或倾斜)当使用 ? 定义 theoremstyle 时thmtools(当然,除了所需的直立括号)。

例子:

\documentclass{article}

\usepackage{amsmath}
\usepackage{amsthm}
\usepackage{embrac}
\usepackage{thmtools}

\makeatletter
\declaretheoremstyle[
  headfont= \sffamily\bfseries,
  headpunct={\sffamily\bfseries.},
  postheadspace=0.5em,
  notefont=\sffamily\bfseries,
  headformat=\NAME\NUMBER\let\thmt@space\@empty\NOTE,
  bodyfont=\mdseries\itshape,
  spaceabove=12pt,spacebelow=12pt,
]{thmstyle}
\makeatother

\theoremstyle{thmstyle}% default
\declaretheorem[name=Theorem,numberwithin=section]{theorem}

\begin{document}
\section{A section}

\begin{theorem}

Let $A$ and $B$ be subsets [see section 2] of a set $X$.Then
\[
X \setminus (A \cup B) = (X \setminus A) \cap (X \setminus B).
\]
\end{theorem}

\end{document}

想要定理正文中的直立括号

我知道答案如何在整个文档中获得直立的括号?,正如它所说,这会破坏一切。

答案1

自 0.8 版(2019/10/01)起,针对以下情况embrac提供:\embparen\embbracket

\documentclass{article}

\usepackage{amsmath}
\usepackage{amsthm}
\usepackage{embrac}
\usepackage{thmtools}

\makeatletter
\declaretheoremstyle[
  headfont= \sffamily\bfseries,
  headpunct={\sffamily\bfseries.},
  postheadspace=0.5em,
  notefont=\sffamily\bfseries,
  headformat=\NAME\NUMBER\let\thmt@space\@empty\NOTE,
  bodyfont=\mdseries\itshape,
  spaceabove=12pt,spacebelow=12pt,
]{thmstyle}
\makeatother

\theoremstyle{thmstyle}% default
\declaretheorem[name=Theorem,numberwithin=section]{theorem}

\begin{document}
\section{A section}

\begin{theorem}
  Let $A$ and $B$ be subsets \embbracket{see section 2} of a set $X$.Then
  \[ X \setminus (A \cup B) = (X \setminus A) \cap (X \setminus B). \]
\end{theorem}

\end{document}

在此处输入图片描述

答案2

embrac如果您愿意放弃定理中的逐字材料,则可以使用的命令处理定理主体\embrac_replace_brackets:N

\documentclass{article}

\usepackage{embrac}
\usepackage{amsthm,thmtools}

\ExplSyntaxOn
\cs_new_protected:Npn \murray_embrac_text:n #1
  {
    \tl_set:Nn \l__embrac_tmpa_tl {#1}
    \embrac_replace_brackets:N \l__embrac_tmpa_tl
    \l__embrac_tmpa_tl
  }

\NewDocumentCommand { \embracifytheorem } { m }
  {
    \NewEnvironmentCopy { origenv_#1 } { #1 }
    \RenewDocumentEnvironment { #1 } { o +b }
      {
        \IfNoValueTF{##1}
          {\begin{origenv_#1}}
          {\begin{origenv_#1}[##1]}
        \murray_embrac_text:n { ##2 }
        \end{origenv_#1}
      }
      {}
  }
\ExplSyntaxOff

% you can adjust or remove these to your liking
\AddOpEmph{?}[0pt,1pt]
\AddOpEmph{!}[0pt,1pt]
\AddOpEmph{:}[0pt,1pt]

\makeatletter
\declaretheoremstyle[
  headfont= \sffamily\bfseries,
  headpunct={\sffamily\bfseries.},
  postheadspace=0.5em,
  notefont=\sffamily\bfseries,
  headformat=\NAME\NUMBER\let\thmt@space\@empty\NOTE,
  bodyfont=\mdseries\itshape,
  spaceabove=12pt,spacebelow=12pt,
]{thmstyle}
\makeatother

\theoremstyle{thmstyle}% default
\declaretheorem[name=Theorem,numberwithin=section]{theorem}
\embracifytheorem{theorem}

\begin{document}

\section{A section}

\begin{theorem}

Let $A$ and $B$ be subsets [see section 2] of a set $X$.Then
\[
X \setminus (A \cup B) = (X \setminus A) \cap (X \setminus B).
\]
\end{theorem}

\end{document}

韓

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