我有一个关于文本对齐的问题：我想有一个 G=(tikzpicture) 部分，就像我示例中的矩阵一样。我没有找到有用的答案，我找到的只是对齐节点内的内容。
如果可能的话（如果你知道我猜的话，一切皆有可能），我希望把它放在 tikzpicture 之外，同时我对每个答案都很满意！尝试用新节点解决它只会给我带来错误，真遗憾。我尝试用一个新的小页面，但图表和文本之间存在相当大的差距。
提前致谢！
编辑：感谢大家的快速回复，它们都对我有很大帮助，尤其是让我更好地理解这些内容！
这是可编译的代码，重点关注重要部分：
\documentclass{beamer}
\usepackage{pgfplots}
\usepackage{tikz}
\usetikzlibrary{arrows, automata}
\begin{document}
\begin{minipage}{.3\textwidth}
\resizebox*{\textwidth}{!}{
$G=$
\begin{tikzpicture}[-,>=stealth',shorten >=1pt,auto,node distance=3.5cm,scale = 1,transform shape]
\node[state] (1) {$1$};
\node[state] (2) [right of=1] {$2$};
\node[state] (3) [below of=2] {$3$};
\node[state] (4) [left of=3] {$4$};
\path (1) edge node {$$} (2)
(2) edge node {$$} (3)
(3) edge node {$$} (4)
(4) edge node {$$} (1);
\end{tikzpicture}
}
\end{minipage}
\end{document}
整个代码如下（但由于没有使用包，所以无法编译）：
\begin{frame}
\frametitle{Orthonormalbasis aus Eigenvektoren: Beispiel}
\centering
\begin{minipage}{.3\textwidth}
\resizebox*{\textwidth}{!}{
$G=$
\begin{tikzpicture}[-,>=stealth',shorten >=1pt,auto,node distance=3.5cm,scale = 1,transform shape]
\node[state] (1) {$1$};
\node[state] (2) [right of=1] {$2$};
\node[state] (3) [below of=2] {$3$};
\node[state] (4) [left of=3] {$4$};
\path (1) edge node {$$} (2)
(2) edge node {$$} (3)
(3) edge node {$$} (4)
(4) edge node {$$} (1);
\end{tikzpicture}
}
\end{minipage}
\pause
\begin{minipage}{.2\textwidth}
\resizebox*{\textwidth}{!}{$\leadsto$}
\end{minipage}
\begin{minipage}{.3\textwidth}
\resizebox*{\textwidth}{!}{
$A(G)=
\begin{pmatrix}
0 & 1 & 1 & 0 \\
1 & 0 & 0 & 1 \\
1 & 0 & 0 & 1 \\
0 & 1 & 1 & 0 \\
\end{pmatrix}$
} \end{minipage}
\end{frame}
\end{document}
答案1
我会让它更简单，没有那些缩放和小页面。\leadsto这里是放大的，但我更喜欢标准尺寸。
\documentclass{beamer}
\usepackage{pgfplots}
\usepackage{tikz}
\usetikzlibrary{arrows, automata}
\begin{document}
\begin{frame}
\frametitle{Orthonormalbasis aus Eigenvektoren: Beispiel}
\[
G=
\begin{gathered}
\begin{tikzpicture}[
scale=0.5,
-,
>=stealth',
shorten >=1pt,
auto,
node distance=3cm,
transform shape
]
\node[state] (1) {$1$};
\node[state] (2) [right of=1] {$2$};
\node[state] (3) [below of=2] {$3$};
\node[state] (4) [left of=3] {$4$};
\path (1) edge node {} (2)
(2) edge node {} (3)
(3) edge node {} (4)
(4) edge node {} (1);
\end{tikzpicture}
\end{gathered}
\pause
\mathrel{\raisebox{-0.25\height}{\scalebox{2}{$\leadsto$}}}
A(G)=
\begin{pmatrix}
0 & 1 & 1 & 0 \\
1 & 0 & 0 & 1 \\
1 & 0 & 0 & 1 \\
0 & 1 & 1 & 0 \\
\end{pmatrix}
\]
\end{frame}
\end{document}
答案2
这是一个起点。
\documentclass{beamer}
\usepackage{tikz}
\usetikzlibrary{arrows,automata,calc}
\begin{document}
\begin{frame}
\[
G=
\begin{tikzpicture}[-,>=stealth',shorten >=1pt,auto,node distance=3.5cm,scale = 1,baseline={(foo)}]
\node[state] (1) {$1$};
\node[state] (2) [right of=1] {$2$};
\node[state] (3) [below of=2] {$3$};
\node[state] (4) [left of=3] {$4$};
\coordinate (foo) at ($(4.base)!0.5!(1.base)$);
\coordinate (faa) at ($(2.base)!0.5!(3.base)$);
\path (1) edge node {$$} (2)
(2) edge node {$$} (3)
(3) edge node {$$} (4)
(4) edge node {$$} (1);
\node[right=1em] at (faa) {\resizebox{.1\linewidth}{!}{$\rightsquigarrow$}};
\end{tikzpicture}
\
A(G)=
\begin{pmatrix}
0 & 1 & 1 & 0 \\
1 & 0 & 0 & 1 \\
1 & 0 & 0 & 1 \\
0 & 1 & 1 & 0 \\
\end{pmatrix}
\]
\end{frame}
\end{document}
答案3
只需使用一个方程。并使用positioning。用适当的基线嵌入tikzpicture。请不要使用\resizebox。
\documentclass{beamer}
\usepackage{tikz}
\usetikzlibrary{automata,positioning}
\begin{document}
\begin{frame}[t]
\frametitle{An equation with an embedded Ti\emph{k}Z picture}
\[G=
\begin{tikzpicture}[-,shorten >=1pt,auto,node
distance=1.5cm,baseline={(Gaux.base)}]
\path node[state] (1) {$1$}
node[state] (2) [right=of 1] {$2$}
node[state] (3) [below=of 2] {$3$}
node[state] (4) [left=of 3] {$4$}
foreach \X [remember=\X as \LastX (initially 4)] in {1,...,4}
{(\LastX) edge (\X)}
(2)-- node(Gaux) {$\vphantom{G}$}(3);
\draw[very thick,line cap=round,->] ([xshift=1em]Gaux)
-- ++ (0.5em,0.5em) -- ++ (1em,-1em) -- ++ (1em,1em)
-- ++ (0.5em,-0.5em) -- ++ (1em,0);
\end{tikzpicture}
~A(G)=\begin{pmatrix}
0 & 1 & 1 & 0 \\
1 & 0 & 0 & 1 \\
1 & 0 & 0 & 1 \\
0 & 1 & 1 & 0 \\
\end{pmatrix}
\]
\end{frame}
\end{document}
答案4
无需额外软件包的解决方案涉及两个tabular环境（参见https://tex.stackexchange.com/a/473626/193767）
\documentclass{beamer}
\usepackage{pgfplots}
\usepackage{tikz}
\usetikzlibrary{arrows, automata}
\begin{document}
\begin{minipage}{.3\textwidth}
$G$
\resizebox*{\textwidth}{!}{%
\begin{tabular}{@{}c@{}c@{}}
$G$=& \begin{tabular}{@{}c}
\begin{tikzpicture}[-,>=stealth',shorten >=1pt,auto,node distance=3.5cm,scale = 1,transform shape]
\node[state] (1) {$1$};
\node[state] (2) [right of=1] {$2$};
\node[state] (3) [below of=2] {$3$};
\node[state] (4) [left of=3] {$4$};
\path (1) edge node {$$} (2)
(2) edge node {$$} (3)
(3) edge node {$$} (4)
(4) edge node {$$} (1);
\end{tikzpicture} \\
\end{tabular}
\end{tabular}
}
\end{minipage}
\end{document}