带斜箭头的 Tikz 框图

Question

我怎样才能做出这样的事情？特别是使用有角度的箭头（指向“扫描操作”的线）而不是 90 度 -| 样式的线。

Answer 1

\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{chains}
\definecolor{strange}{RGB}{230,244,253}
\begin{document}
\begin{tikzpicture}[block/.style={draw,fill=strange,minimum height=2.5em},
    font=\sffamily,>=stealth]
 \begin{scope}[start chain=A going below,node distance=1em,
    local bounding box=buffers]
  \foreach \X in {1,...,4}
  {\node[block,on chain,minimum width=8em]{Buffer};
  \draw[<-,thick] (A-\X.west) -- node[above]{$m_\X(t)$} ++ (-4em,0) ;}
 \end{scope} 
 \node[right=6em of buffers,align=center,inner sep=0.5pt,fill=strange,
    circle,draw] (SO) {Scan\\operations};
 \foreach \X in {1,...,4} 
  {\draw[->,thick] (A-\X.east) -- node[above]{$m_\X(t)$} ++ (4em,0) -- (SO);}
 \node[right=4em of SO,block,minimum width=6em](M){Modem};
 \draw[->,thick](SO) -- node[above](mc){$m_c(t)$} (M);
 \draw[->,thick](M.east) -- node[above](s){$s(t)$} ++(4em,0);
 \draw[<-] ([yshift=-1ex]mc.south) -- ++ (-1em,-3em)
  node[below,align=center]{Bla\\ bla};
 \draw[<-] ([yshift=-1ex]s.south) -- ++ (1em,-3em)
  node[below,align=center]{Blub\\ blub};
\end{tikzpicture}
\end{document}