这个怎么画？

Question

我正在尝试绘制这个图：

如何绘制此图并将角度包含在内？此外，如何将角度的“弧”符号包含在内？

Answer 1

除 之外angles，正如 John Kormylo 所提到的，您可能还想使用calc。然后，构建图片就很简单了（最多为一个总长度尺度，这不是由数据固定的）。

\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{angles,calc,quotes}
\begin{document}
\begin{tikzpicture}
 \path[angle eccentricity=1.5,angle radius=1cm]
   (0,0) coordinate[label=below left:$C$] (C)
   (0,pi) coordinate[label=above left:$B$] (B) 
   (10:5) coordinate (auxC1) (40:5) coordinate (auxC2) 
   ($(B)+(-10:5)$) coordinate (auxB1)
   ($(B)+(-30:5)$) coordinate (auxB2)
   (intersection of B--auxB1 and C--auxC1) coordinate[label=right:$A$](A)
   (intersection of C--A and B--auxB2) coordinate[label=below:$E$](E)
   (intersection of B--A and C--auxC2) coordinate[label=above:$F$](F)
   pic[draw,"$30^\circ$"]{angle=E--C--F}
   pic[draw,"$50^\circ$"]{angle=F--C--B}
   pic[draw,"$60^\circ$"]{angle=C--B--E}
   pic[draw,"$20^\circ$"]{angle=E--B--F}
   pic[draw,"$x$"]{angle=F--E--B};
 \draw[thick] (A) -- (B) -- (C) -- cycle (B) -- (E) -- (F) -- (C);
\end{tikzpicture}
\end{document}

你也可以问 Ti钾Z 测量角度x。

\documentclass[tikz,border=3mm]{standalone}
\usetikzlibrary{angles,calc,quotes}
\begin{document}
\begin{tikzpicture}
 \path[angle eccentricity=1.5,angle radius=1cm]
   (0,0) coordinate[label=below left:$C$] (C)
   (0,5) coordinate[label=above left:$B$] (B) 
   (10:5) coordinate (auxC1) (40:5) coordinate (auxC2) 
   ($(B)+(-10:5)$) coordinate (auxB1)
   ($(B)+(-30:5)$) coordinate (auxB2)
   (intersection of B--auxB1 and C--auxC1) coordinate[label=right:$A$](A)
   (intersection of C--A and B--auxB2) coordinate[label=below:$E$](E)
   (intersection of B--A and C--auxC2) coordinate[label=above:$F$](F)
   pic[draw,"$30^\circ$"]{angle=E--C--F}
   pic[draw,"$50^\circ$"]{angle=F--C--B}
   pic[draw,"$60^\circ$"]{angle=C--B--E}
   pic[draw,"$20^\circ$"]{angle=E--B--F}
   let \p1=($(B)-(E)$),\p2=($(F)-(E)$),
    \n1={atan2(\y1,\x1)},\n2={atan2(\y2,\x2)}  in
   pic[draw,"$x=\pgfmathparse{\n1-\n2}\pgfmathprintnumber\pgfmathresult^\circ$",
    angle radius=2cm,angle eccentricity=1.25]{angle=F--E--B};
 \draw[thick] (A) -- (B) -- (C) -- cycle (B) -- (E) -- (F) -- (C);
\end{tikzpicture}
\end{document}

Answer 2

\documentclass[tikz,border=3mm]{standalone}
\usepackage{tkz-euclide}
\begin{document}
\begin{tikzpicture}
  \tkzDefPoints{0/0/C,0/pi/B}
   \tkzDefPointBy[rotation=center C angle -80](B) \tkzGetPoint{BB}
   \tkzDefPointBy[rotation=center B angle 80](C) \tkzGetPoint{CC}
   \tkzInterLL(B,CC)(C,BB) \tkzGetPoint{A}
   \tkzDefPointBy[rotation=center C angle 30](A) \tkzGetPoint{AA}
   \tkzDefPointBy[rotation=center B angle -20](A) \tkzGetPoint{AAA} 
   \tkzInterLL(B,A)(C,AA) \tkzGetPoint{F}
   \tkzInterLL(C,A)(B,AAA) \tkzGetPoint{E}  
   % drawing   
   \tkzDrawPolygon(A,B,C)
   \tkzDrawSegments(C,F B,E E,F)
   % marking
   \tkzMarkAngles[mark=none](F,E,B E,C,B C,B,F)
   \tkzLabelAngle[pos=1.5](E,C,F){$30^\circ$}
   \tkzLabelAngle[pos=1.5](E,B,F){$20^\circ$}
   \tkzLabelAngle[pos=1.5](F,C,B){$50^\circ$}
   \tkzLabelAngle[pos=1.5](C,B,E){$60^\circ$}
   \tkzLabelAngle[pos=1.5](F,E,B){$x$}
   % labeling
   \tkzLabelPoints[left](B,C)
   \tkzLabelPoints[right](A)
   \tkzLabelPoints[above](F)
   \tkzLabelPoints[below](E)
\end{tikzpicture}
\end{document}