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我的工作示例是:
\documentclass[a4paper, 12pt]{scrreprt}
\usepackage{mathrsfs}
\usepackage{amsmath}
\usepackage{amssymb}
\usepackage{braket}
\usepackage{mleftright}
\begin{document}
Due to:
\begin{equation}
\label{FourierRelationPositionMomentumKets}
\braket{x' \vert p'} = \frac{1}{\sqrt{2 \pi \hbar}} \exp \mleft( \frac{i p' x'}{\hbar} \mright)
\end{equation}
they are related by Fourier transformation:
\begin{subequations}
\begin{subequations}
\label{Position-MomentumSpaceWaveFunctionsDiscr}
\begin{align}
\psi \mleft( x \mright) = \braket{x \vert \psi} = \braket{x \vert \hat{\mathbb{I}} \vert \psi} = \braket{x \vert \mleft( \sum_{p' \in \mathscr{P}} \ket{p'} \bra{p'} \mright) \vert \psi} = \sum_{p' \in \mathscr{P}} \braket { x \vert p' } \braket{ p' \vert \psi } = \sum_{p' \in \mathscr{P}} \braket { x \vert p' } \phi \mleft( p' \mright), \label{PositionSpaceWaveFunctionsDiscr} \\
\phi \mleft( p \mright) = \braket{p \vert \psi} = \braket{p \vert \hat{\mathbb{I}} \vert \psi} = \braket{p \vert \mleft( \sum_{x' \in \mathscr{X}} \ket{x'} \bra{x'} \mright) \vert \psi} = \sum_{x' \in \mathscr{X}} \braket { p \vert x' } \braket{ x' \vert \psi } = \sum_{x' \in \mathscr{X}} \braket { p \vert x' } \psi \mleft( x' \mright) \label{MomentumSpaceWaveFunctionsDiscr}
\end{align}
\end{subequations}
or:
\begin{subequations}
\label{Position-MomentumSpaceWaveFunctionsCont}
\begin{align}
\psi \mleft( x \mright) = \braket{x \vert \psi} = \braket{x \vert \hat{\mathbb{I}} \vert \psi} = \braket{x \vert \mleft( \int\limits_{\mathscr{P}} dp' \, \ket{p'} \bra{p'} \mright) \vert \psi} = \int\limits_{\mathscr{P}} dp' \, \braket { x \vert p' } \braket{ p' \vert \psi } = \int\limits_{\mathscr{P}} dp' \, \braket { x \vert p' } \phi \mleft( p' \mright), \label{PositionSpaceWaveFunctionsCont} \\
\phi \mleft( p \mright) = \braket{p \vert \psi} = \braket{p \vert \hat{\mathbb{I}} \vert \psi} = \braket{p \vert \mleft( \int\limits_{\mathscr{X}} dx' \, \ket{x'} \bra{x'} \mright) \vert \psi} = \int\limits_{\mathscr{X}} dx' \, \braket { p \vert x' } \braket{ x' \vert \psi } = \int\limits_{\mathscr{X}} dx' \, \braket { p \vert x' } \psi \mleft( x' \mright), \label{MomentumSpaceWaveFunctionsCont}
\end{align}
\end{subequations}
\end{subequations}
\end{document}
我的问题实际上是方程式 0.2。我希望它们以它们原来的方式嵌套,但它们显然不适合,但我认为将它们分开会使它变得非常庞大。有什么建议可以让我真正节省整个文档的这一部分的空间吗?
答案1
我会保持对齐并将内容分成两行,这样也许最重要的步骤就直接位于彼此下方。我还建议使用直立的差异,并在标点符号前留出空格。太多不必要的错误发生了,因为有人误认为 是$x_i,$
。$x_{i'}$
我不太喜欢嵌套,subequations
但你似乎喜欢它。
\documentclass[a4paper, 12pt,fleqn]{scrreprt}
\usepackage{mathrsfs}
\usepackage{amsmath}
\usepackage{amssymb}
\usepackage{braket}
\usepackage{mleftright}
\newcommand{\diff}{\mathop{}\!\mathrm{d}}
\begin{document}
Due to:
\begin{equation}
\label{FourierRelationPositionMomentumKets}
\braket{x' \vert p'} = \frac{1}{\sqrt{2 \pi \hbar}}
\exp \mleft( \frac{\mathrm{i}\, p' x'}{\hbar} \mright)
\end{equation}
they are related by Fourier transformation:
\begin{subequations}
\begin{subequations}
\label{Position-MomentumSpaceWaveFunctionsDiscr}
\begin{align}
\psi \mleft( x \mright) = \braket{x \vert \psi} = \braket{x \vert \hat{\mathbb{I}} \vert \psi}
&= \braket{x \vert \mleft( \sum_{p' \in \mathscr{P}} \ket{p'} \bra{p'} \mright) \vert \psi}
\notag\\
&= \sum_{p' \in \mathscr{P}} \braket { x \vert p' } \braket{ p' \vert \psi }
= \sum_{p' \in \mathscr{P}} \braket { x \vert p' } \phi \mleft( p'
\mright)\;, \label{PositionSpaceWaveFunctionsDiscr} \\
\phi \mleft( p \mright) = \braket{p \vert \psi} = \braket{p \vert \hat{\mathbb{I}} \vert \psi}
&= \braket{p \vert \mleft( \sum_{x' \in \mathscr{X}} \ket{x'} \bra{x'} \mright) \vert \psi}
\notag\\
&= \sum_{x' \in \mathscr{X}} \braket { p \vert x' } \braket{ x' \vert \psi } = \sum_{x' \in \mathscr{X}} \braket { p \vert x' } \psi \mleft( x' \mright) \label{MomentumSpaceWaveFunctionsDiscr}
\end{align}
\end{subequations}
or
\begin{subequations}
\label{Position-MomentumSpaceWaveFunctionsCont}
\begin{align}
\psi \mleft( x \mright) = \braket{x \vert \psi} = \braket{x \vert
\hat{\mathbb{I}} \vert \psi} &= \braket{x \vert \mleft(
\int\limits_{\mathscr{P}} \!\diff p' \, \ket{p'} \bra{p'} \mright) \vert \psi}
\notag\\
&= \int\limits_{\mathscr{P}}\! \diff p' \, \braket { x \vert p' } \braket{ p' \vert
\psi } = \int\limits_{\mathscr{P}}\! \diff p' \, \braket { x \vert p' } \phi
\mleft( p' \mright)\;, \label{PositionSpaceWaveFunctionsCont} \\
\phi \mleft( p \mright) = \braket{p \vert \psi} = \braket{p \vert \hat{\mathbb{I}} \vert \psi}
&= \braket{p \vert \mleft( \int\limits_{\mathscr{X}}\! \diff x' \, \ket{x'} \bra{x'} \mright) \vert \psi}
\notag\\
&= \int\limits_{\mathscr{X}}\! \diff x' \, \braket { p \vert x' } \braket{ x' \vert
\psi } = \int\limits_{\mathscr{X}}\! \diff x' \, \braket { p \vert x' } \psi
\mleft( x' \mright)\;, \label{MomentumSpaceWaveFunctionsCont}
\end{align}
\end{subequations}
\end{subequations}
\end{document}
答案2
像这样?
使用split
:
\documentclass[a4paper, 12pt]{scrreprt}
\usepackage{mathrsfs}
\usepackage{amsmath}
\usepackage{amssymb}
\usepackage{braket}
\usepackage{mleftright}
\begin{document}
Due to:
\begin{equation}
\label{FourierRelationPositionMomentumKets}
\braket{x' \vert p'} = \frac{1}{\sqrt{2 \pi \hbar}} \exp \mleft( \frac{i p' x'}{\hbar} \mright)
\end{equation}
they are related by Fourier transformation:
\begin{subequations}
\begin{subequations}
\label{Position-MomentumSpaceWaveFunctionsDiscr}
\begin{align}
\begin{split}\label{PositionSpaceWaveFunctionsDiscr}
\psi \mleft( x \mright)
& = \braket{x \vert \psi}
= \braket{x \vert \hat{\mathbb{I}} \vert \psi}
= \braket{x \vert \mleft( \sum_{p' \in \mathscr{P}} \ket{p'} \bra{p'} \mright) \vert \psi} \\
& = \sum_{p' \in \mathscr{P}} \braket { x \vert p' } \braket{ p' \vert \psi } = \sum_{p' \in \mathscr{P}} \braket { x \vert p' } \phi \mleft( p' \mright),
\end{split} \\
%
\begin{split}\label{MomentumSpaceWaveFunctionsDiscr}
\phi \mleft( p \mright)
& = \braket{p \vert \psi}
= \braket{p \vert \hat{\mathbb{I}} \vert \psi}
= \braket{p \vert \mleft( \sum_{x' \in \mathscr{X}} \ket{x'} \bra{x'} \mright) \vert \psi} \\
& = \sum_{x' \in \mathscr{X}} \braket { p \vert x' } \braket{ x' \vert \psi } = \sum_{x' \in \mathscr{X}} \braket { p \vert x' } \psi \mleft( x' \mright)
\end{split}
\end{align}
\end{subequations}
\end{subequations}
\end{document}